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(a)
Interpretation:
The type of semiconductor formed when silicon combine with the given set of elements has to be determined.
Concept Introduction:
Semiconductors are substances that conduct electricity either by addition of an impurity or by the effects of temperature on it. Semiconductors electrically conductivity lies between conductor and insulator. Semiconductors have small energy gap between valence band and conduction band.
Addition of impurity to a semiconductor is termed as doping. Doping alters the conductivity of a semiconductor. The addition of an element having either more or less number of valence electrons than the natural semiconductor decides the combination as the following two types of semiconductor.
- n- type semiconductor: (conduction is due to movement of extra electrons)
The element added will have more valence electron than the natural semiconductor. Therefore, the extra electron from the added element resides in conduction band and increase the conductivity.
Example: Silicon (natural semiconductor) and Phosphorus
- p-type semiconductor: (conduction is due to movement of holes)
The element added will have less valence electron than the natural semiconductor. Here, instead of extra electron, there will be “holes” at the places, where a semiconductor is replaced by added element. A p-type semiconductor increases conductivity because the holes (effective positive charge; lies at valence band) move through the natural semiconductor rather than electrons.
Example: Silicon (natural semiconductor) and Gallium
To Explain:
The type of semiconductor formed when silicon combines with the given set of elements.
(b)
Interpretation:
The type of semiconductor formed when silicon combine with the given set of elements has to be determined.
Concept Introduction:
Semiconductors are substances that conduct electricity either by addition of an impurity or by the effects of temperature on it. Semiconductors electrically conductivity lies between conductor and insulator. Semiconductors have small energy gap between valence band and conduction band.
Addition of impurity to a semiconductor is termed as doping. Doping alters the conductivity of a semiconductor. The addition of an element having either more or less number of valence electrons than the natural semiconductor decides the combination as the following two types of semiconductor.
- n- type semiconductor: (conduction is due to movement of extra electrons)
The element added will have more valence electron than the natural semiconductor. Therefore, the extra electron from the added element resides in conduction band and increase the conductivity.
Example: Silicon (natural semiconductor) and Phosphorus
- p-type semiconductor: (conduction is due to movement of holes)
The element added will have less valence electron than the natural semiconductor. Here, instead of extra electron, there will be “holes” at the places, where a semiconductor is replaced by added element. A p-type semiconductor increases conductivity because the holes (effective positive charge; lies at valence band) move through the natural semiconductor rather than electrons.
Example: Silicon (natural semiconductor) and Gallium
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Chapter 24 Solutions
Chemistry: Atoms First
- Nonearrow_forward4. Experimental Procedure. a. How many (total) data plots are to be completed for this experiment? Account for each. b. What information is to be extracted from each data plot?arrow_forwardProvide the IUPAC name of the following molecule. Don't forget to include the proper stereochemistry where appropriate.arrow_forward
- 3. 2. 1. On the graph below, plot the volume of rain in milliliters versus its height in centimeters for the 400 mL beaker. Draw a straight line through the points and label it "400 mL beaker." Volume (mL) 400 350 300 250 200 150 750 mL Florence Volume Versus Height of Water 400 mL beaker 100 50 0 0 2 3 4 5 Height (cm) 6 7 8 9 10 Explain why the data points for the beaker lie roughly on a straight line. What kind of relationship is this? How do you know? (see page 276 text) the design of the beaker is a uniform cylinder the volume of liquid increases evenly with its height resulting in a linear relationship. What volume would you predict for 10.0 cm of water? Explain how you arrived at your answer. Use the data table and the graph to assist you in answering the question. 4. Plot the volume of rain in milliliters versus its height in centimeters for the 250 mL Florence flask on the same graph. Draw a best-fit curve through the points and label it "250 mL Florence flask." oke camearrow_forwardShow work. Don't give Ai generated solutionarrow_forwardIn the video, we looked at the absorbance of a certain substance and how it varies depending on what wavelength of light we are looking at. Below is a similar scan of a different substance. What color BEST describes how this substance will appear? Absorbance (AU) Violet Blue Green Orange 1.2 1.0- 0.8- 0.6- 0.4- 0.2 0.0 450 500 550 600 650 700 Wavelength (nm) violet indigo blue green yellow orange red Red O Cannot tell from this information In the above graph, what causes -450 nm wavelength of light to have a higher absorbance than light with a -550 nm wavelength? Check all that are true. The distance the light travels is different The different data points are for different substances The concentration is different at different times in the experiment Epsilon (molar absortivity) is different at different wavelengthsarrow_forward
- 5. a. Data were collected for Trial 1 to determine the molar mass of a nonvolatile solid solute when dissolved in cyclo- hexane. Complete the table for the analysis (See Report Sheet). Record calculated values with the correct number of significant figures. B. Freezing Point of Cyclohexane plus Calculation Zone Unknown Solute 2. Mass of cyclohexane (g) 10.14 Part C.4 3. Mass of added solute (g) 0.255 C. Calculations 1. k; for cyclohexane (°C⚫ kg/mol) 20.0 2. Freezing point change, AT, (°C) 3.04 Part C.6 3. Mass of cyclohexane in solution (kg) 4. Moles of solute, total (mol) Show calculation. 5. Mass of solute in solution, total (g) 6. Molar mass of solute (g/mol) Show calculation.arrow_forwardDraw and name the R groups of all 20 amino acids.arrow_forward3. Two solutions are prepared using the same solute: Solution A: 0.14 g of the solute dissolves in 15.4 g of t-butanol Solution B: 0.17 g of the solute dissolves in 12.7 g of cyclohexane Which solution has the greatest freezing point change? Show calculations and explain.arrow_forward
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