
Interpretation:
The movement of electrons in a solar battery that uses p-type and n-type semiconductors when light shines on the solar cell has to be explained
Concept Introduction:
Semiconductors are substances that conduct electricity either by addition of an impurity or by the effects of temperature on it. Semiconductors electrically conductivity lie between conductor and insulator. Semiconductors have small energy gap between valence band and conduction band.
Addition of impurity to a semiconductor is termed as doping. Doping alters the conductivity of a semiconductor. The addition of an element having either more or less number of valence electrons than the natural semiconductor decides the combination as the following two types of semiconductor.
- n- type semiconductor: (conduction is due to movement of extra electrons)
The element added will have more valence electron than the natural semiconductor. Therefore, the extra electron from the added element resides in conduction band and increase the conductivity.
Example: Silicon (natural semiconductor) and Phosphorus
- p-type semiconductor: (conduction is due to movement of holes)
The element added will have less valence electron than the natural semiconductor. Here, instead of extra electron, there will be “holes” at the places, where a semiconductor is replaced by added element. A p-type semiconductor increases conductivity because the holes (effective positive charge; lies at valence band) move through the natural semiconductor rather than electrons.
Example: Silicon (natural semiconductor) and Gallium
To Explain:
The movement of electrons in a solar battery that uses p-type and n-type semiconductors when light shines on the solar cell

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Chapter 24 Solutions
Chemistry: Atoms First
- Correct each molecule in the drawing area below so that it has the condensed structure it would have if it were dissolv a 0.1 M aqueous solution of HCI. If there are no changes to be made, check the No changes box under the drawing area. No changes. HO—CH,—C—CH,—OH X 5 2 2 2 HO–CH,—CH,—C—CH,—OH Explanation Check Center Accessi ©2025 on 5 Carrow_forwardMake the calculations to prepare 2M H2SO4, from concentrated H2SO4 (98%; density: 1.84 g/mL).arrow_forwardH CH3 CH3 b) Write the products of your compound and the following reagents. If the reaction would not work for your compound, write "no reaction" and explain the problem. NaCN H* H₂NNHCH5 H* -à NaBH -à CH2MgBr Cro₁₂ --à H3O+ -à c) Would your compound give a positive Tollen's test? Why or why not?arrow_forward
- Homework 4 Chem 204 Dr. Hellwig Consider this compound, which will be referred to as "your compound". a) Name your compound according to the IUPAC system. Include stereochemistry (E/Z/R/S) H CH3 CH3arrow_forwardWhat is the mechanism for this?arrow_forward21.50 Determine the combinations of haloalkane(s) and alkoxide(s) that could be used to synthesize the following ethers through Williamson ether synthesis. (a) (c) (d) (e) (f) H₂COarrow_forward
- 1. Arrange the following in order of increasing bond energy (lowest bond energy first, highest bond energy last). Provide your rationale. C=C, C-F, C=C, C-N, C-C List the bond order for each example.arrow_forwardWhat is the major enolate formed when treated with LDA? And why that one?arrow_forward4. Calculate the total number of sigma bonds and total number of pi bonds in each of the following compounds. a. HH :D: +1 I H-N-C-C-O-H I H b. HH H Н :N=C-C-C=C-CEC-H :0: total o H-C-H H-C = `C-H I H. 11 H-C = C= CH H total o total π total π 1 Harrow_forward
- In the following reaction, what quantity in moles of CH₃OH are required to give off 4111 kJ of heat? 2 CH₃OH (l) + 3 O₂ (g) → 2 CO₂ (g) + 4 H₂O(g) ∆H° = -1280. kJarrow_forwardIndicate the processes in the dismutation of Cu2O.arrow_forward1. Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. 2600 2400 2200 2000 1800 1600 1400 1200 1000 800 Potential Energy (kJ) 600 400 200 0 -200- -400 -600- -800 (i) Cl₂ (g) + Pt(s) → 2Cl (g) + Pt(s) (ii) Cl (g)+ CO (g) + Pt (s) → CICO (g) + Pt (s) Ea = 1550 kJ Ea = 2240 kJ (iii) Cl (g) + CICO (g) → Cl₂CO (g) Ea = 2350 kJ AH=-950 kJ ΔΗ = 575 ΚΙ AH=-825 kJ a. Draw the potential energy diagram for the reaction. Label the data points for clarity. The potential energy of the reactants is 600 kJ Reaction Progress b. What is the overall chemical equation? c. What is the overall change in enthalpy for the above chemical reaction? d. What is the overall amount of activation energy for the above chemical reaction? e. Which reaction intermediate would be considered a catalyst (if any) and why? f. If you were to add 2700kJ of energy to the reaction (e.g. 2700 kl of heat or electricity), would you be able to make the reaction reverse itself (i.e. have…arrow_forward
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning

