The process of production of dilute urine by the kidneys. Introduction: The urine is said to be dilute when its osmolarity is less than 300 mOsm (milliosmoles). It contains less concentration of solutes and high amount of water. The amount and concentration of urine produced by kidneys occurs in accordance with the needs of the body and is influenced by hormones.

Question

Want to see the full answer?

Answer 1

Question

Chapter 24.6, Problem 4QC

Summary Introduction

To review:

The process of production of dilute urine by the kidneys.

Introduction:

The urine is said to be dilute when its osmolarity is less than 300 mOsm (milliosmoles). It contains less concentration of solutes and high amount of water. The amount and concentration of urine produced by kidneys occurs in accordance with the needs of the body and is influenced by hormones.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

. Consider a base substitution mutation that occurred in a DNA sequence that resulted in a change in the encoded protein from the amino acid glutamic acid to aspartic acid. Normally the glutamic acid amino acid is located on the outside of the soluble protein but not near an active site. O-H¨ A. What type of mutation occurred? O-H B. What 2 types of chemical bonds are found in the R-groups of each amino acid? The R groups are shaded. CH2 CH2 CH2 H2N-C-COOH H2N-C-COOH 1 H Glutamic acid H Aspartic acid C. What 2 types of bonds could each R-group of each of these amino acids form with other molecules? D. Consider the chemical properties of the two amino acids and the location of the amino acid in the protein. Explain what effect this mutation will have on this protein's function and why.

engineered constructs that consist of hollow fibers are acting as synthetic capillaries, around which cells have been loaded. The cellular space around a single fiber can be modeled as if it were a Krogh tissue cylinder. Each fiber has an outside “capillary” radius of 100 µm and the “tissue” radius can be taken as 200 µm. The following values apply to the device:R0 = 20 µM/secaO2 = 1.35 µM/mmHgDO2,T = 1.67 x 10-5 cm2/secPO2,m = 4 x 10-3 cm/secInstead of blood inside the fibers, the oxygen transport and tissue consumption are being investigated by usingan aqueous solution saturated with pure oxygen. As a result, there is no mass transfer resistance in the synthetic“capillary”, only that due to the membrane itself. Rather than accounting for pO2 variations along the length ofthe fiber, use an average value in the “capillary” of 130 mmHg.Is the tissue fully oxygenated?

Molecular Biology Please help with question. thank you You are studying the expression of the lac operon. You have isolated mutants as described below. In the presence of glucose, explain/describe what would happen, for each mutant, to the expression of the lac operon when you add lactose AND what would happen when the bacteria has used up all of the lactose (if the mutant is able to use lactose).5. Mutations in the lac operator that strengthen the binding of the lac repressor 200 fold 6. Mutations in the promoter that prevent binding of RNA polymerase 7. Mutations in CRP/CAP protein that prevent binding of cAMP8. Mutations in sigma factor that prevent binding of sigma to core RNA polymerase