Chapter 24, Problem 52E

Interpretation Introduction

Interpretation: It is given that, ${\text{NH}}_{\text{3}}\left(\text{aq}\right)$ reacts with $\text{HCl}\left(\text{g}\right)$ to form ${\text{NH}}_{\text{4}}\text{Cl}\left(\text{s}\right)$ . The substance that acts as Bronsted-Lowry acid and base is to be identified in the given reaction.

Concept introduction: The donor of proton $\left({\text{H}}^{\text{+}}\right)$ is known as Bronsted-Lowry acid whereas the acceptor of $\left({\text{H}}^{\text{+}}\right)$ is known as Bronsted-Lowry base.