COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 24, Problem 49QAP
To determine

(a)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 49QAP

Image distance =30.0cm

Image height =60.0cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 10.0cm

Radius of the mirror = 15.0cm

Height of the object = 20.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=15.0cm2=7.5cm

  1q=1f1p=17.5cm110.0cmq=30.0cm

  hiho=qphi20.0cm=30.0cm10.0cmhi=60.0cm

Conclusion:

Image distance =30.0cm

Image height =60.0cm

Type of image = Real
Orientation of the image = Inverted

To determine

(b)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 49QAP

Image distance =12.0cm

Image height =12.0cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 20.0cm

Radius of the mirror = 15.0cm

Height of the object = 20.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=15.0cm2=7.5cm

  1q=1f1p=17.5cm120.0cmq=12.0cm

  hiho=qphi20.0cm=12.0cm20.0cmhi=12.0cm

Conclusion:

Image distance =12.0cm

Image height =12.0cm

Type of image = Real
Orientation of the image = Inverted

To determine

(c)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 49QAP

Image distance =8.11cm

Image height =1.62cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 100.0cm

Radius of the mirror = 15.0cm

Height of the object = 20.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=15.0cm2=7.5cm

  1q=1f1p=17.5cm1100.0cmq=8.11cm

  hiho=qphi20.0cm=8.11cm100.0cmhi=1.62cm

Conclusion:

Image distance =8.11cm

Image height =1.62cm

Type of image = Real
Orientation of the image = Inverted

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
please answer this asap!!!!
RT = 4.7E-30 18V IT = 2.3E-3A+ 12 38Ω ли 56Ω ли r5 27Ω ли r3 28Ω r4 > 75Ω r6 600 0.343V 75.8A Now figure out how much current in going through the r4 resistor. |4 = unit And then use that current to find the voltage drop across the r resistor. V4 = unit
7 Find the volume inside the cone z² = x²+y², above the (x, y) plane, and between the spheres x²+y²+z² = 1 and x² + y²+z² = 4. Hint: use spherical polar coordinates.

Chapter 24 Solutions

COLLEGE PHYSICS

Ch. 24 - Prob. 11QAPCh. 24 - Prob. 12QAPCh. 24 - Prob. 13QAPCh. 24 - Prob. 14QAPCh. 24 - Prob. 15QAPCh. 24 - Prob. 16QAPCh. 24 - Prob. 17QAPCh. 24 - Prob. 18QAPCh. 24 - Prob. 19QAPCh. 24 - Prob. 20QAPCh. 24 - Prob. 21QAPCh. 24 - Prob. 22QAPCh. 24 - Prob. 23QAPCh. 24 - Prob. 24QAPCh. 24 - Prob. 25QAPCh. 24 - Prob. 26QAPCh. 24 - Prob. 27QAPCh. 24 - Prob. 28QAPCh. 24 - Prob. 29QAPCh. 24 - Prob. 30QAPCh. 24 - Prob. 31QAPCh. 24 - Prob. 32QAPCh. 24 - Prob. 33QAPCh. 24 - Prob. 34QAPCh. 24 - Prob. 35QAPCh. 24 - Prob. 36QAPCh. 24 - Prob. 37QAPCh. 24 - Prob. 38QAPCh. 24 - Prob. 39QAPCh. 24 - Prob. 40QAPCh. 24 - Prob. 41QAPCh. 24 - Prob. 42QAPCh. 24 - Prob. 43QAPCh. 24 - Prob. 44QAPCh. 24 - Prob. 45QAPCh. 24 - Prob. 46QAPCh. 24 - Prob. 47QAPCh. 24 - Prob. 48QAPCh. 24 - Prob. 49QAPCh. 24 - Prob. 50QAPCh. 24 - Prob. 51QAPCh. 24 - Prob. 52QAPCh. 24 - Prob. 53QAPCh. 24 - Prob. 54QAPCh. 24 - Prob. 55QAPCh. 24 - Prob. 56QAPCh. 24 - Prob. 57QAPCh. 24 - Prob. 58QAPCh. 24 - Prob. 59QAPCh. 24 - Prob. 60QAPCh. 24 - Prob. 61QAPCh. 24 - Prob. 62QAPCh. 24 - Prob. 63QAPCh. 24 - Prob. 64QAPCh. 24 - Prob. 65QAPCh. 24 - Prob. 66QAPCh. 24 - Prob. 67QAPCh. 24 - Prob. 68QAPCh. 24 - Prob. 69QAPCh. 24 - Prob. 70QAPCh. 24 - Prob. 71QAPCh. 24 - Prob. 72QAPCh. 24 - Prob. 73QAPCh. 24 - Prob. 74QAPCh. 24 - Prob. 75QAPCh. 24 - Prob. 76QAPCh. 24 - Prob. 77QAPCh. 24 - Prob. 78QAPCh. 24 - Prob. 79QAPCh. 24 - Prob. 80QAPCh. 24 - Prob. 81QAPCh. 24 - Prob. 82QAPCh. 24 - Prob. 83QAPCh. 24 - Prob. 84QAPCh. 24 - Prob. 85QAPCh. 24 - Prob. 86QAPCh. 24 - Prob. 87QAPCh. 24 - Prob. 88QAPCh. 24 - Prob. 89QAPCh. 24 - Prob. 90QAPCh. 24 - Prob. 91QAPCh. 24 - Prob. 92QAPCh. 24 - Prob. 93QAPCh. 24 - Prob. 94QAPCh. 24 - Prob. 95QAPCh. 24 - Prob. 96QAPCh. 24 - Prob. 97QAPCh. 24 - Prob. 98QAPCh. 24 - Prob. 99QAPCh. 24 - Prob. 100QAPCh. 24 - Prob. 101QAPCh. 24 - Prob. 102QAPCh. 24 - Prob. 103QAP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
AP Physics 2 - Geometric Optics: Mirrors and Lenses - Intro Lesson; Author: N. German;https://www.youtube.com/watch?v=unT297HdZC0;License: Standard YouTube License, CC-BY