COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 24, Problem 68QAP
To determine
To explain:
The how the light bends physically in concave and convex lens
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• An object is a distance 2ƒ from a convex lens. (a) Use a ray diagram to find the approximate location of the image. (b) Is theimage upright or inverted? (c) Is the image real or virtual? Explain.
• (a) Use a ray diagram to determine the approximate location ofthe image produced by a concave lens when the object is at a distance 12 ∙ ƒ ∙ from the lens. (b) Is the image upright or inverted? (c) Isthe image real or virtual? Explain
• During a daytime football game you notice that a player’s reflective helmet forms an image of the Sun 4.8 cm behind the surface ofthe helmet. What is the radius of curvature of the helmet, assuming it to be roughly spherical?
Chapter 24 Solutions
COLLEGE PHYSICS
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- •Explain what happens to the light ray at ech boundary: a plastic rectblock a mirrorarrow_forward• A mirrored-glass gazing globe in a garden is 31.9 cm in diameter.What is the focal length of the globe?arrow_forward• Light is refracted as it travels from a point A in medium 1 to apoint B in medium 2. If the index of refraction is 1.33 in medium1 and 1.51 in medium 2, how much time does it take for light to gofrom A to B, assuming it travels 331 cm in medium 1 and 151 cm inmedium 2?arrow_forward
- 400 •44 An object is placed against the center of a thin lens and then moved away from it along the central axis as the image distance i is measured. Figure 34-41 gives i versus object distance p out to p, = 60 cm. What is the image distance when p= 100 -400 p (cm) Figure 34-41 Problem 44. cm? (un)!arrow_forward•• A slab of glass that has an index of refraction of 1.50 is submerged in water that has an index of refraction of 1.33. Light in the water is incident on the glass. Find the angle of refraction if the angle of incidence is (a) 60°, (b) 45°, and (c) 30°. SSM 31arrow_forward• The radius of the 10th dark ring in Newton's rings apparatus changes from 60 to 50 mm when a liquid is introduced between the lens and the plate. Calculate the refraction index of the liquid.arrow_forward
- A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -56 cm are 176 cm apart. A 3.3-cm-tall object is 60 cm in front of the converging lens. | - • Part A You may want to review (Pages 996 - 997) Calculate the distance between image and diverging lens. For help with math skills, you may want to review: Express your answer to two significant figures and include the appropriate units. Rearrangement of Expressions Involving Multiplication and Division • View Available Hint(s) Rearrangement of Algebraic Expressions Hint 1. How to approach the problem Draw a sketch showing the object and the two lenses. Label the distance from the object to the converging lens and the separation between the diverging and converging lenses. The light is going to go through both lenses. How is the image from the first lens related to what would be the object of the second lens? Applying the thin lens equation, what is the image distance for the first (converging) lens?…arrow_forward• A convex mirror has a radius of curvature that has a magnitude equal to 24 cm. Use ray diagrams to locate the image, if it exists, for an object near the axis at distances of (a) 55 cm, (b) 24 cm, (c) 12 cm, (d) 8.0 cm, and (e) 1.0 cm from the mirror. For each case, state whether the image is real or virtual; upright or inverted; and enlarged, reduced, or the same size as the object. 26arrow_forward•• Alight ray passes through a prism with an apex angle of a, as shown in Figure 31-62. The ray and the bisector of the apex angle intersect at right angles. Show that the angle of deviation & is related to the apex angle and the index of refraction of the prism material by sin {(a + 8)] = n sin(ta). 78arrow_forward
- •• An object is 15.0 cm in front of a converging lens that has a focal length equal to 15.0 cm. A diverging lens that has a focal length whose magnitude is equal to 15.0 cm is located 20.0 cm in back of the first. (a) Find the location of the final image and describe its properties (for example, real and inverted) and (b) draw a ray diagram to corroborate your answers to Part (a). SSM 55arrow_forward•• A concave mirror has a radius of curvature equal to 24 cm. Use ray diagrams to locate the image, if it exists, for an ob- ject near the axis at distances of (a) 55 cm, (b) 24 cm, (c) 12 cm, and (d) 8.0 cm from the mirror. For each case, state whether the image is real or virtual; upright or inverted; and enlarged, reduced, or the same size as the object. 24arrow_forward•8 An object is placed against the center of a spherical mirror and then moved 70 cm from it along the central axis as the image distance i is measured. Figure 34-36 gives i versus object distance p out to P. = 40 cm. What is i for p = 70 cm? 400 -400arrow_forward
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