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Chapter 24, Problem 42AP

A Geiger–Mueller tube is a radiation detector that consists of a closed, hollow, metal cylinder (the cathode) of inner radius ra and a coaxial cylindrical wire (the anode) of radius rb (Fig. P24.42a). The charge per unit length on the anode is λ, and the charge per unit length on the cathode is −λ. A gas fills the space between the electrodes. When the tube is in use (for example, in measuring radioactivity from fruit in Fig. P24.42b) and a high-energy elementary particle passes through this space, it can ionize an atom of the gas. The strong electric field makes the resulting ion and electron accelerate in opposite directions. They strike other molecules of the gas to ionize them, producing an avalanche of electrical discharge. The pulse of electric current between the wire and the cylinder is counted by an external circuit. (a) Show that the magnitude of the electric potential difference between the wire and the cylinder is

Δ V 2 k e λ ln ( r a r b )

(b) Show that the magnitude of the electric field in the space between cathode and anode is

E = Δ V ln ( r a / r b ) ( 1 r )

where r is the distance from the axis of the anode to the point where the field is to be calculated.

Figure P24.42

Chapter 24, Problem 42AP, A GeigerMueller tube is a radiation detector that consists of a closed, hollow, metal cylinder (the

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Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = αe-r/a0 + β/r + b0 where alpha (α), beta (β), a0 and b0 are constants. Find an expression for its capacitance.   First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by:   Calculating the antiderivative or indefinite integral , Vab = (-αa0e-r/a0 + β + b0 )     By definition, the capacitance C is related to the charge and potential difference by: C =  /    Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q / ( (e-rb/a0 - e-ra/a0) + β ln() + b0 () )
Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = αe-r/a0 + β/r + b0 where alpha (α), beta (β), a0 and b0 are constants. Find an expression for its capacitance.
Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rb has charge -Q. The electric field E at a radial distance r from the central axis is given by the function: E = αe-r/a0 + β/r + b0 where alpha (α), beta (β), a0 and b0 are constants. Find an expression for its capacitance.   First, let us derive the potential difference Vab between the two conductors. The potential difference is related to the electric field by:

Chapter 24 Solutions

Bundle: Physics For Scientists And Engineers With Modern Physics, Loose-leaf Version, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Single-term

Ch. 24 - Three positive charges are located at the corners...Ch. 24 - Two point charges Q1 = +5.00 nC and Q2 = 3.00 nC...Ch. 24 - You are working on a laboratory device that...Ch. 24 - Your roommate is having trouble understanding why...Ch. 24 - Four point charges each having charge Q are...Ch. 24 - The two charges in Figure P24.12 are separated by...Ch. 24 - Show that the amount of work required to assemble...Ch. 24 - Two charged particles of equal magnitude are...Ch. 24 - Three particles with equal positive charges q are...Ch. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Prob. 18PCh. 24 - How much work is required to assemble eight...Ch. 24 - Four identical particles, each having charge q and...Ch. 24 - It is shown in Example 24.7 that the potential at...Ch. 24 - Figure P24.22 represents a graph of the electric...Ch. 24 - Figure P24.23 shows several equipotential lines,...Ch. 24 - An electric field in a region of space is parallel...Ch. 24 - A rod of length L (Fig. P24.25) lies along the x...Ch. 24 - For the arrangement described in Problem 25,...Ch. 24 - A wire having a uniform linear charge density is...Ch. 24 - You are a coach for the Physics Olympics team...Ch. 24 - The electric field magnitude on the surface of an...Ch. 24 - Why is the following situation impossible? A solid...Ch. 24 - A solid metallic sphere of radius a carries total...Ch. 24 - Prob. 32PCh. 24 - A very large, thin, flat plate of aluminum of area...Ch. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - A long, straight wire is surrounded by a hollow...Ch. 24 - Prob. 37APCh. 24 - Prob. 38APCh. 24 - Prob. 39APCh. 24 - Why is the following situation impossible? You set...Ch. 24 - The thin, uniformly charged rod shown in Figure...Ch. 24 - A GeigerMueller tube is a radiation detector that...Ch. 24 - Review. Two parallel plates having charges of...Ch. 24 - When an uncharged conducting sphere of radius a is...Ch. 24 - A solid, insulating sphere of radius a has a...Ch. 24 - Prob. 46APCh. 24 - For the configuration shown in Figure P24.45,...Ch. 24 - An electric dipole is located along the y axis as...Ch. 24 - A disk of radius R (Fig. P24.49) has a nonuniform...Ch. 24 - Prob. 50CPCh. 24 - (a) A uniformly charged cylindrical shell with no...
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