Figure 24.15 (Example 24.6) A uniformly charged disk of radius Rlies in a plane perpen- R V7²+x² dicular to the xaxis. The calcu- lation of the electric potential at any point Pon the x axis is simplified by dividing the disk into many rings of radius rand width dr, with area 2™r dr. dA = 2Tr dr dr

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Chapter1: Units, Trigonometry. And Vectors
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A uniformly charged disk has radius R and surface charge density σ.
(A) Find the electric potential at a point P along the perpendicular central axis of the disk.                                                                                                          (B) Find the x component of the electric field at a point P along the perpendicular central axis of the disk.

Figure 24.15 (Example 24.6)
A uniformly charged disk of
radius Rlies in a plane perpen-
R
V7²+x²
dicular to the xaxis. The calcu-
lation of the electric potential
at any point Pon the x axis is
simplified by dividing the disk
into many rings of radius rand
width dr, with area 2™r dr.
dA = 2Tr dr
dr
Transcribed Image Text:Figure 24.15 (Example 24.6) A uniformly charged disk of radius Rlies in a plane perpen- R V7²+x² dicular to the xaxis. The calcu- lation of the electric potential at any point Pon the x axis is simplified by dividing the disk into many rings of radius rand width dr, with area 2™r dr. dA = 2Tr dr dr
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