Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
9th Edition
ISBN: 9781305932302
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 24, Problem 3CQ
To determine
The net electric flux through the Gaussian surface under the given conditions.
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A vertical electric field of magnitude 2e4 N/C exists above the earth's surface on a day when a thunderstorm is brewing. A car with a rectangular size of 6.00 m by 3.00 m is travelling along a dry gravel rod way sloping downward at 10°. Find the direction of the area vector and determine the electric flux through the bottom of the car.
The figure below shows a closed cylinder with cross-sectional area A = 2.00m2. The constant electric field E has magnitude 3.50 X 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux through the cylinder's (a) top and (b) bottom surfaces. (c) Determine the amount of charge inside the cylinder
Consider an imaginary box with dimensions 15 cm × 45 cm × 95 cm. There is an E- field with a uniform magnitude 850 N/C going in through the left side of the box and an E-field with a uniform magnitude 550 N/C going in through the right side, as shown in the figure below.
(a) Calculate the total electric flux through the box.
(b) Use Gauss’s law and your previous answer to find the net charge enclosed by the box.
Chapter 24 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
Ch. 24.1 - Suppose a point charge is located at the center of...Ch. 24.2 - If the net flux through a gaussian surface is...Ch. 24 - Prob. 1OQCh. 24 - Prob. 2OQCh. 24 - Prob. 3OQCh. 24 - Prob. 4OQCh. 24 - Prob. 5OQCh. 24 - Prob. 6OQCh. 24 - Prob. 7OQCh. 24 - Prob. 8OQ
Ch. 24 - Prob. 9OQCh. 24 - Prob. 10OQCh. 24 - Prob. 11OQCh. 24 - Prob. 1CQCh. 24 - Prob. 2CQCh. 24 - Prob. 3CQCh. 24 - Prob. 4CQCh. 24 - Prob. 5CQCh. 24 - Prob. 6CQCh. 24 - Prob. 7CQCh. 24 - Prob. 8CQCh. 24 - Prob. 9CQCh. 24 - Prob. 10CQCh. 24 - Prob. 11CQCh. 24 - A flat surface of area 3.20 m2 is rotated in a...Ch. 24 - A vertical electric field of magnitude 2.00 104...Ch. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - A nonuniform electric field is given by the...Ch. 24 - An uncharged, nonconducting, hollow sphere of...Ch. 24 - Prob. 8PCh. 24 - Prob. 9PCh. 24 - Prob. 10PCh. 24 - Prob. 11PCh. 24 - A charge of 170 C is at the center of a cube of...Ch. 24 - Prob. 13PCh. 24 - A particle with charge of 12.0 C is placed at the...Ch. 24 - Prob. 15PCh. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Find the net electric flux through (a) the closed...Ch. 24 - Prob. 19PCh. 24 - Prob. 20PCh. 24 - Prob. 21PCh. 24 - Prob. 22PCh. 24 - Prob. 23PCh. 24 - Prob. 24PCh. 24 - Prob. 25PCh. 24 - Determine the magnitude of the electric field at...Ch. 24 - A large, flat, horizontal sheet of charge has a...Ch. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - A nonconducting wall carries charge with a uniform...Ch. 24 - A uniformly charged, straight filament 7.00 m in...Ch. 24 - Prob. 32PCh. 24 - Consider a long, cylindrical charge distribution...Ch. 24 - A cylindrical shell of radius 7.00 cm and length...Ch. 24 - A solid sphere of radius 40.0 cm has a total...Ch. 24 - Prob. 36PCh. 24 - Prob. 37PCh. 24 - Why is the following situation impossible? A solid...Ch. 24 - A solid metallic sphere of radius a carries total...Ch. 24 - Prob. 40PCh. 24 - A very large, thin, flat plate of aluminum of area...Ch. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - A long, straight wire is surrounded by a hollow...Ch. 24 - Prob. 46PCh. 24 - Prob. 47PCh. 24 - Prob. 48APCh. 24 - Prob. 49APCh. 24 - Prob. 50APCh. 24 - Prob. 51APCh. 24 - Prob. 52APCh. 24 - Prob. 53APCh. 24 - Prob. 54APCh. 24 - Prob. 55APCh. 24 - Prob. 56APCh. 24 - Prob. 57APCh. 24 - An insulating solid sphere of radius a has a...Ch. 24 - Prob. 59APCh. 24 - Prob. 60APCh. 24 - Prob. 61CPCh. 24 - Prob. 62CPCh. 24 - Prob. 63CPCh. 24 - Prob. 64CPCh. 24 - Prob. 65CPCh. 24 - A solid insulating sphere of radius R has a...Ch. 24 - Prob. 67CPCh. 24 - Prob. 68CPCh. 24 - Prob. 69CP
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- If the net flux through a gaussian surface is zero, the following four statements could be true. Which of the statements must be true? (a) There are no charges inside the surface. (b) The net charge inside the surface is zero. (c) The electric field is zero everywhere on the surface. (d) The number of electric field lines entering the surface equals the number leaving the surface.arrow_forwardIf more electric field lines leave a gaussian surface than enter it, what can you conclude about the net charge enclosed by that surface?arrow_forwardA long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of , and the cylinder has a net charge per unit length of 2. From this information, use Gausss law to find (a) the charge per unit length on the inner surface of the cylinder, (b) the charge per unit length on the outer surface of the cylinder, and (c) the electric field outside the cylinder a distance r from the axis.arrow_forward
- A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure 124.63. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non- uniform and is given by E = (3.00 + 2.00x2)i N/C, where x is in meters. (a) Calculate the net electric flux leaving the closed surface. (b) What net charge enclosed by the surface?arrow_forwardA solid conducting sphere of radius 2.00 cm has a charge 8.00 μC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a total charge −4.00 μC. Find the electric field at (a) r = 1.00 cm, (b) r = 3.00 cm, (c) r = 4.50 cm, and (d) r = 7.00 cm from the center of this charge configuration.arrow_forwardA uniform electric field exists in a region of space containing no charges. What can you conclude about the net electric flux through a gaussian surface placed in this region of space?arrow_forward
- As shown in the figure below, a solid insulating sphere of radius a - 5.00 cm carries a net positive charge Q = 3.00 µC that is uniformly distributed throughout its volume. Concentric with this sphere is a conducting spherical shell with inner radius b = 10.0 cm, outer radius c - 15.0 cm, and having net charge q = -1.00 µC. Determine the magnitude of the electric field (in N/C) at each of the following distances from the center of the spheres. Insulator Conductor (a) r= 4.50 cm N/C (b) r- 9.50 cm N/C (c) r= 12.0 cm N/C (d) r= 20.0 cm N/Carrow_forwardConsider an imaginary box with dimensions 15 cm × 45 cm × 95 cm. There is an E- field with a uniform magnitude 850 N/C going out through the left side of the box and an E-field with a uniform magnitude 550 N/C going in through the right side, as shown in the figure below. (a) Calculate the total electric flux through the box. (b) Use Gauss’s law and your previous answer to find the net charge enclosed by the box.arrow_forwardAn anemoscope is a device invented to show the direction of the wind, or to foretell a change of wind direction or weather. Consider a situation where an anemoscope is in a uniform electric field of magnitude E= 50.5 N/C, as depicted in the above figure. If the rim of the anemoscope is a circle with radius of 10 cm, and is perpendicular to the electric field, what is the magnitude of the electric flux through the fabric of the anemoscope?arrow_forward
- In a uniform electric field of magnitude E, the field lines cross through a rectangle of area A at an angle of 32.9° with respect to the plane of the rectangle. What is the flux through the rectangle?arrow_forwardConsider the uniform electric field E = (4.0ĵ + 3.0k) × 10³ N/C. What is the electric flux magnitude through a circular area of radius 2.0 m that lines in the xy-plane?arrow_forwardAs shown in the figure below, a solid insulating sphere of radius a = 5.00 cm carries a net positive charge Q = 3.00 μC that is uniformly distributed throughout its volume. Concentric with this sphere is a conducting spherical shell with inner radius b = 10.0 cm, outer radius c = 15.0 cm, and having net charge q = -1.00 µC. Determine the magnitude of the electric field (in N/C) at each of the following distances from the center of the spheres. (a) r= 1.50 cm (b) r= 8.50 cm (c) r= 12.5 cm 0 x Construct a spherical Gaussian surface centered at the center of the insulated sphere and with a radius equal to the distance from the center at which we wish to determine the electric field. Write Gauss's law for this case, evaluate both sides, and solve for the electric field. How can you determine the charge enclosed by the Gaussian surface? N/C (d) r= 17.0 cm N/C ✓ N/C N/C Need Help? Read It 7 W Insulator T Conductor ↑ F $ R 5 T Y 8arrow_forward
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