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Concept explainers
(a)
Interpretation:
The step of glycolysis in which ATP are formed should be determined.
Concept Introduction:
Aerobic respiration occurs in two steps:
- Glycolysis
- Citric acid cycle
Glycolysis is the first step that forms pyruvate as given below:
In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like
![Check Mark](/static/check-mark.png)
Answer to Problem 31P
In glycolysis, ATP's are formed in step-7 and 10.
Explanation of Solution
The
The overall reaction of glycolysis must be written as:
Two steps; 7th and 10th step are involved in the production of ATP;
- Conversion of 1,3-bisphosphoglycerate to 3-phosphoglycerate occurs with the conversion of ADP to form ATP in the presence of Phosphoglycerate kinase that transfers a phosphate group.
- Conversion of phosphoenolpyruvate (PEP) to pyruvic acid with the conversion of ATP in the presence enzyme pyruvate kinase
(b)
Interpretation:
The step of glycolysis which uses ATP molecules should be determined.
Concept Introduction:
Aerobic respiration occurs in two steps:
- Glycolysis
- Citric acid cycle
Glycolysis is the first step that forms pyruvate as given below:
In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like
![Check Mark](/static/check-mark.png)
Answer to Problem 31P
In glycolysis, ATP's are formed in step-1 and 3.
Explanation of Solution
The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions that involves the conversion of glucose molecules into pyruvate with the production of ATP molecules.
The overall reaction of glycolysis must be written as:
Two steps; 1st and 3rdstep use ATP molecules.
- The first step in glycolysis, glucose converts to glucose-6-phosphate in the presence of hexokinase. It uses energy in the form of ATP and converts it to ADP molecule.
- Phosphofructokinase, with magnesium as a cofactor, changes fructose 6-phosphate into fructose 1, 6-bisphosphate.
(c)
Interpretation:
The step of glycolysis which forms a reduce coenzyme should be determined.
Concept Introduction:
Aerobic respiration occurs in two steps:
- Glycolysis
- Citric acid cycle
Glycolysis is the first step that forms pyruvate as given below:
In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like
![Check Mark](/static/check-mark.png)
Answer to Problem 31P
In glycolysis, step-6 forms a reduced coenzyme NADH.
Explanation of Solution
The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions which involves the conversion of glucose molecules into pyruvate with the production of ATP molecules.
The overall reaction of glycolysis must be written as:
In the 6th step of glycolysis, glyceraldehyde-3-phosphate converts to 1,3-bisphosphoglycerate. It is a dehydrogenation step that occurs in the presence of Glyceraldehyde-3-phosphate dehydrogenase (GAPDH) and converts NAD+ to NADH and H+ ions.
(c)
Interpretation:
The step of glycolysis which breaks a C-C bond should be determined.
Concept Introduction:
Aerobic respiration occurs in two steps:
- Glycolysis
- Citric acid cycle
- Glycolysis is the first step that forms pyruvate as given below:
In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like
![Check Mark](/static/check-mark.png)
Answer to Problem 31P
In glycolysis, step-4breaks a C-C bond.
Explanation of Solution
The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions which involves the conversion of glucose molecules into pyruvate with production of ATP molecules.
The overall reaction of glycolysis must be written as:
In the 4thstep of glycolysis, in the presence of enzyme Aldolase, fructose 1, 6-bisphosphate breaks into two sugar molecules. These sugar molecules are isomers of each other; dihydroxyacetone phosphate (DHAP) and glyceraldehyde 3-phosphate (GAP).
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Chapter 24 Solutions
General, Organic, and Biological Chemistry - 4th edition
- 1. For the four structures provided, Please answer the following questions in the table below. a. Please draw π molecular orbital diagram (use the polygon-and-circle method if appropriate) and fill electrons in each molecular orbital b. Please indicate the number of π electrons c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non- aromatic TT MO diagram Number of π e- Aromaticity Evaluation (X choose one) Non-aromatic Aromatic Anti-aromatic || ||| + IVarrow_forward1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?arrow_forwardQ3: Circle the molecules that are optically active: ДДДДarrow_forward
- 6. How many peaks would be observed for each of the circled protons in the compounds below? 8 pts CH3 CH3 ΤΙ A. H3C-C-C-CH3 I (₁₁ +1)= 7 H CI B. H3C-C-CI H (3+1)=4 H LIH)=2 C. (CH3CH2-C-OH H D. CH3arrow_forwardNonearrow_forwardQ1: Draw the most stable and the least stable Newman projections about the C2-C3 bond for each of the following isomers (A-C). Are the barriers to rotation identical for enantiomers A and B? How about the diastereomers (A versus C or B versus C)? H Br H Br (S) CH3 (R) CH3 H3C (S) H3C H Br Br H A C enantiomers H Br H Br (R) CH3 H3C (R) (S) CH3 H3C H Br Br H B D identicalarrow_forward
- 2. Histamine (below structure) is a signal molecule involved in immune response and is a neurotransmitter. Histamine features imidazole ring which is an aromatic heterocycle. Please answer the following questions regarding Histamine. b a HN =N C NH2 a. Determine hybridization of each N atom (s, p, sp, sp², sp³, etc.) in histamine N-a hybridization: N-b hybridization: N-c hybridization: b. Determine what atomic orbitals (s, p, sp, sp², sp³, etc.) of the lone pair of each N atom resided in N-a hybridization: N-b hybridization: N-c hybridization:arrow_forwardNonearrow_forward29. Use frontier orbital analysis (HOMO-LUMO interactions) to decide whether the following dimerization is 1) thermally allowed or forbidden and 2) photochemically allowed or forbidden. +arrow_forward
- 30.0 mL of 0.10 mol/L iron sulfate and 20.0 mL of 0.05 mol/L of silver nitrate solutions are mixed together. Justify if any precipitate would formarrow_forwardDoes the carbonyl group first react with the ethylene glycol, in an intermolecular reaction, or with the end alcohol, in an intramolecular reaction, to form a hemiacetal? Why does it react with the alcohol it does first rather than the other one? Please do not use an AI answer.arrow_forwardThe number of noncyclic isomers that have the composition C4H8Owith the O as part of an OH group, counting a pair of stereoisomers as1, is A. 8; B. 6; C. 9; D. 5; E. None of the other answers is correct.arrow_forward
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