CHEMISTRY 1111 LAB MANUAL >C<
1st Edition
ISBN: 9781307092097
Author: Chang
Publisher: MCG/CREATE
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Question
Chapter 24, Problem 24.73QP
Interpretation Introduction
Interpretation:
Chirality and the alcohol based structural isomer should be identified for the given formula of
Concept introduction:
Isomer: Molecule has same molecular formula but different structural arrangement is called isomer.
Chiral: Absence of a plane of symmetry or a center of symmetry is called chiral molecule, a non-superimposable on its mirror image is called chiral. A carbon atom is attached by the four different groups is called chiral carbon.
Achiral: Presence of a plane of symmetry or a center of symmetry is called achiral molecule, a superimposable on its mirror image is called achiral. A carbon atom does not have four different groups is called achiral carbon
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Students have asked these similar questions
Part I.
a) Elucidate
the structure of compound A using the following information.
• mass spectrum: m+ = 102, m/2=57
312=29
• IR spectrum:
1002.5
% TRANSMITTANCE
Ngg
50
40
30
20
90
80
70
60
MICRONS
5
8
9 10
12
13
14 15 16
19
1740 cm
M
10
0
4000
3600
3200
2800
2400
2000
1800
1600
13
• CNMR
'H
-NMR
Peak
8
ppm (H)
Integration
multiplicity
a
1.5 (3H)
triplet
b
1.3
1.5 (3H)
triplet
C
2.3
1 (2H)
quartet
d
4.1
1 (2H)
quartet
& ppm (c)
10
15
28
60
177 (C=0)
b) Elucidate the structure of compound B using the following information
13C/DEPT NMR 150.9 MHz
IIL
1400
WAVENUMBERS (CM-1)
DEPT-90
DEPT-135
85 80 75
70
65
60
55
50
45 40
35
30 25 20
ppm
1200
1000
800
600
400
•
Part II.
a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below:
• IR spectra
% TRANSMITTANCE
1002.5
90
80
70
60
50
40
30
20
10
0
4000
3600
3200
2800
2400
2000
1800
1600
• Information from 'HAMR
MICRONS
8 9 10
11
14 15 16
19
25
1400
WAVENUMBERS (CM-1)
1200
1000
800
600
400
peak
8 ppm
Integration
multiplicity
a
2.1
1.5 (3H)
Singlet
b
3.6
1 (2H)
singlet
с
3.8
1.5 (3H)
Singlet
d
6.8
1(2H)
doublet
7.1
1(2H)
doublet
Information from 13C-nmR
Normal carbon
29ppm
Dept 135
Dept -90
+
NO peak
NO peak
50 ppm
55 ppm
+
NO peak
114 ppm
t
126 ppm
No peak
NO peak
130 ppm
t
+
159 ppm
No peak
NO peak
207 ppm
по реак
NO peak
Could you redraw these and also explain how to solve them for me pleas
Chapter 24 Solutions
CHEMISTRY 1111 LAB MANUAL >C<
Ch. 24.2 - How many structural isomers are there in the...Ch. 24.2 - Prob. 2PECh. 24.2 - Prob. 3PECh. 24.2 - Prob. 4PECh. 24.4 - Prob. 5PECh. 24 - Prob. 24.1QPCh. 24 - Prob. 24.2QPCh. 24 - What do saturated and unsaturated mean when...Ch. 24 - Prob. 24.4QPCh. 24 - Prob. 24.5QP
Ch. 24 - Why is it that alkanes and alkynes, unlike...Ch. 24 - Prob. 24.7QPCh. 24 - Prob. 24.8QPCh. 24 - Prob. 24.9QPCh. 24 - Give examples of a chiral substituted alkane and...Ch. 24 - Draw all possible structural isomers for the...Ch. 24 - Prob. 24.12QPCh. 24 - Draw all possible isomers for the molecule C4H8.Ch. 24 - Draw all possible isomers for the molecule C3H5Br.Ch. 24 - Prob. 24.15QPCh. 24 - Prob. 24.16QPCh. 24 - Draw the structures of cis-2-butene and...Ch. 24 - Prob. 24.18QPCh. 24 - Prob. 24.19QPCh. 24 - Prob. 24.20QPCh. 24 - Prob. 24.21QPCh. 24 - Prob. 24.22QPCh. 24 - Prob. 24.23QPCh. 24 - Prob. 24.24QPCh. 24 - Which of the following amino acids are chiral: (a)...Ch. 24 - Name the following compounds: (a) CH3CCCH2CH3Ch. 24 - Prob. 24.27QPCh. 24 - Prob. 24.28QPCh. 24 - Prob. 24.29QPCh. 24 - Prob. 24.30QPCh. 24 - Prob. 24.31QPCh. 24 - Name the following compounds:Ch. 24 - Prob. 24.33QPCh. 24 - Prob. 24.34QPCh. 24 - Prob. 24.35QPCh. 24 - Prob. 24.36QPCh. 24 - Prob. 24.37QPCh. 24 - Prob. 24.38QPCh. 24 - Prob. 24.39QPCh. 24 - Prob. 24.40QPCh. 24 - Predict the product or products of each of the...Ch. 24 - Prob. 24.42QPCh. 24 - Prob. 24.43QPCh. 24 - Given these data...Ch. 24 - Prob. 24.45QPCh. 24 - Prob. 24.46QPCh. 24 - Prob. 24.47QPCh. 24 - Prob. 24.48QPCh. 24 - How many liters of air (78 percent N2, 22 percent...Ch. 24 - Prob. 24.50QPCh. 24 - Prob. 24.51QPCh. 24 - Prob. 24.52QPCh. 24 - Prob. 24.53QPCh. 24 - The combustion of 3.795 mg of liquid B, which...Ch. 24 - Prob. 24.55QPCh. 24 - Indicate the asymmetric carbon atoms in the...Ch. 24 - Prob. 24.57QPCh. 24 - Prob. 24.58QPCh. 24 - Prob. 24.59QPCh. 24 - Name the classes to which the following compounds...Ch. 24 - Prob. 24.61QPCh. 24 - Prob. 24.62QPCh. 24 - Prob. 24.63QPCh. 24 - Prob. 24.64QPCh. 24 - Prob. 24.65QPCh. 24 - Prob. 24.66QPCh. 24 - Prob. 24.67QPCh. 24 - When a mixture of methane and bromine vapor is...Ch. 24 - Prob. 24.69QPCh. 24 - Prob. 24.70QPCh. 24 - Prob. 24.71QPCh. 24 - Prob. 24.72QPCh. 24 - Prob. 24.73QPCh. 24 - Prob. 24.74QP
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- In the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+. Assuming there is 2.00 L of solution, answer the following: The Ka of the left & right solution is? The pH of the left & right solution is? The acid on the left & right is what kind of acid?arrow_forwardNonearrow_forwardNonearrow_forward
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