EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
3rd Edition
ISBN: 9781259298424
Author: SMITH
Publisher: VST
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Chapter 24, Problem 24.38P
Interpretation Introduction

(a)

Interpretation:

The role of coenzymes NAD+ and NADH in the conversion of pyruvate to acetyl CoA should be determined.

Concept Introduction:

Aerobic respiration occurs in two steps:

  • Glycolysis
  • Citric acid cycle

Glycolysis is the first step that forms pyruvate as given below:

  Glucose +   2NAD+ + 4ADP + 2Pi  2 Pyruvate + 4ATP + 2NADH + 2H+

In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like NAD+, GDP, and FAD and CO2 gas is formed as the waste product. The products of citric acid cycles act as precursors for electron transport chains.

Expert Solution
Check Mark

Answer to Problem 24.38P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 24, Problem 24.38P , additional homework tip  1

Explanation of Solution

The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions that involve the glucose molecules into pyruvate with the production of ATP molecules.

The overall reaction of glycolysis must be written as:

  C6H12O6 + 2 NAD+ + 2 ADP + 2 P  2  (CH3(C=O)COOH + 2 ATP + 2 NADH + 2 H+

The pyruvate from glycolysis synthesizes acetyl CoA by the loss of one C atom in the form of CO2 gas in the presence of CoenzymeA. This breakdown of pyruvate molecule occurs by transfer of electrons to NAD+ to form NADH. Further, NADH will be used by the cell to produce ATP.

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 24, Problem 24.38P , additional homework tip  2

Interpretation Introduction

(b)

Interpretation:

The role of coenzymes NAD+ and NADH in the conversion of pyruvate to lactate should be determined.

Concept Introduction:

Aerobic respiration occurs in two steps:

  • Glycolysis
  • Citric acid cycle

Glycolysis is the first step that forms pyruvate as given below:

  Glucose +   2NAD+ + 4ADP + 2Pi  2 Pyruvate + 4ATP + 2NADH + 2H+

In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like NAD+, GDP, and FAD and CO2 gas is formed as the waste product. The products of citric acid cycles act as precursors for electron transport chains.

Expert Solution
Check Mark

Answer to Problem 24.38P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 24, Problem 24.38P , additional homework tip  3

Explanation of Solution

The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions that involve the glucose molecules into pyruvate with the production of ATP molecules.

The overall reaction of glycolysis must be written as:

  C6H12O6 + 2 NAD+ + 2 ADP + 2 P  2  (CH3(C=O)COOH + 2 ATP + 2 NADH + 2 H+

The conversion of pyruvate to lactate is an enzymatical process. It is a hydrogenation reaction in which NADH changes to NAD+whereas the reversible process is catalyzed by lactate dehydrogenases.

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 24, Problem 24.38P , additional homework tip  4

Interpretation Introduction

(c)

Interpretation:

The role of coenzymes NAD+ and NADH in the conversion of pyruvate to ethanol should be determined.

Concept Introduction:

Aerobic respiration occurs in two steps:

  • Glycolysis
  • Citric acid cycle

Glycolysis is the first step that forms pyruvate as given below:

  Glucose + 2ATP + 2NAD+ + 4ADP + 2Pi  2 Pyruvate + 4ATP + 2NADH + 2H+

In the presence of oxygen means aerobic respiration, this pyruvate enters the Krebs cycle and extracts energy in the form of electrons transfer. Electrons are transferred from the pyruvate to the receptors like NAD+, GDP, and FAD and CO2 gas is formed as the waste product. The products of citric acid cycles act as precursors for electron transport chains.

Expert Solution
Check Mark

Answer to Problem 24.38P

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 24, Problem 24.38P , additional homework tip  5

Explanation of Solution

The metabolism of glucose starts from the glycolysis process. It is the first step in cellular metabolism to extract energy from glucose. It is the sequence of 10 enzyme-catalyzed reactions which involves the conversion of glucose molecules into pyruvate with production of ATP molecules.

The overall reaction of glycolysis must be written as:

  C6H12O6 + 2 NAD+ + 2 ADP + 2 P  2  (CH3(C=O)COOH + 2 ATP + 2 NADH + 2 H+

In the anaerobic conditions and presence of yeast, pyruvate converts to carbon dioxide and ethanol. Enzyme pyruvate decarboxylase catalyzes this reaction and removes a carbon dioxide molecule from the pyruvate to yield acetaldehyde which further changes to ethanol in the presence of NADH.

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM, Chapter 24, Problem 24.38P , additional homework tip  6

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Chapter 24 Solutions

EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM

Ch. 24.4 - Prob. 24.11PCh. 24.5 - Prob. 24.12PCh. 24.5 - Prob. 24.13PCh. 24.5 - Prob. 24.14PCh. 24.6 - Prob. 24.15PCh. 24.7 - Prob. 24.16PCh. 24.7 - Prob. 24.17PCh. 24.7 - Prob. 24.18PCh. 24.7 - Prob. 24.19PCh. 24.7 - Use the number of molecules of ATP formed from the...Ch. 24.7 - Prob. 24.21PCh. 24.8 - Prob. 24.22PCh. 24.8 - Prob. 24.23PCh. 24.8 - Prob. 24.24PCh. 24.8 - Prob. 24.25PCh. 24.9 - Prob. 24.26PCh. 24.9 - Prob. 24.27PCh. 24.9 - Prob. 24.28PCh. 24 - Analyze each reaction by considering the...Ch. 24 - Analyze each reaction by considering the...Ch. 24 - Prob. 24.31PCh. 24 - Prob. 24.32PCh. 24 - Prob. 24.33PCh. 24 - Prob. 24.34PCh. 24 - Prob. 24.35PCh. 24 - Prob. 24.36PCh. 24 - Prob. 24.37PCh. 24 - Prob. 24.38PCh. 24 - Glucose is completely metabolized to six molecules...Ch. 24 - Why is glycolysis described as an anaerobic...Ch. 24 - Write the overall equation with key coenzymes for...Ch. 24 - Prob. 24.42PCh. 24 - Prob. 24.43PCh. 24 - Prob. 24.44PCh. 24 - Consider the aerobic and anaerobic avenues of...Ch. 24 - Prob. 24.46PCh. 24 - Prob. 24.47PCh. 24 - Prob. 24.48PCh. 24 - Prob. 24.49PCh. 24 - Prob. 24.50PCh. 24 - Prob. 24.51PCh. 24 - Prob. 24.52PCh. 24 - Prob. 24.53PCh. 24 - Prob. 24.54PCh. 24 - Prob. 24.55PCh. 24 - Prob. 24.56PCh. 24 - Prob. 24.57PCh. 24 - Prob. 24.58PCh. 24 - Prob. 24.59PCh. 24 - Prob. 24.60PCh. 24 - Prob. 24.61PCh. 24 - Prob. 24.62PCh. 24 - Prob. 24.63PCh. 24 - Prob. 24.64PCh. 24 - Prob. 24.65PCh. 24 - Prob. 24.66PCh. 24 - Prob. 24.67PCh. 24 - Fill in the boxes with the number of moles of each...Ch. 24 - Prob. 24.69PCh. 24 - Prob. 24.70PCh. 24 - Prob. 24.71PCh. 24 - Prob. 24.72PCh. 24 - Prob. 24.73PCh. 24 - Prob. 24.74PCh. 24 - Prob. 24.75PCh. 24 - Prob. 24.76PCh. 24 - What is the difference between ketogenic and...Ch. 24 - Prob. 24.78PCh. 24 - Prob. 24.79PCh. 24 - Draw the structure of the keto acid formed by the...Ch. 24 - Draw the products formed in each transamination...Ch. 24 - Prob. 24.82PCh. 24 - Prob. 24.83PCh. 24 - Prob. 24.84PCh. 24 - What metabolic intermediate is formed from the...Ch. 24 - What metabolic intermediate is formed from the...Ch. 24 - Prob. 24.87PCh. 24 - Prob. 24.88PCh. 24 - Prob. 24.89PCh. 24 - What is the cause of the pain and cramping in a...Ch. 24 - Prob. 24.91PCh. 24 - Prob. 24.92PCh. 24 - Prob. 24.93PCh. 24 - Prob. 24.94PCh. 24 - Prob. 24.95PCh. 24 - Prob. 24.96PCh. 24 - What type of enzyme would catalyze the conversion...Ch. 24 - Prob. 24.98PCh. 24 - Prob. 24.99CPCh. 24 - Prob. 24.100CPCh. 24 - Prob. 24.101CPCh. 24 - Prob. 24.102CP
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