Elementary Surveying (14th Edition)
14th Edition
ISBN: 9780133758887
Author: Charles D. Ghilani, Paul R. Wolf
Publisher: PEARSON
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Chapter 24, Problem 24.2P
To determine
(a)
Degree of the curvature by arc definition and chord definition.
To determine
(b)
Degree of the curvature by arc definition and chord definition
To determine
(c)
Degree of the curvature by arc definition and chord definition
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Following are the data of gauge and discharge collected at a particular section of the river by stream gauging operation.
Gauge reading
Discharge
Gauge reading
Discharge
(m)
(cms)
(m)
(cms)
7.65
15
8.48
170
7.70
30
8.98
400
7.77
57
9.30
600
7.80
39
9.50
800
7.90
60
89
10.50
1500
7.91
100
11.10
2000
8.08
150
11.70
2400
1. Develop a rating curve for this stream at this section for use in estimating the discharge for a known gauge reading and fit a
linear regression equation for use in estimation of stage for a known value of discharge. Use a value of 7.50 as the gauge
reading corresponding to zero discharge. (20 pts) Equation 1 arith
2. What is the coefficient of correlation of the derived relationship? (10 pts) R2² arith
Equation 2 log
R2 log
3. Determine the stage for a discharge of 3500 cms (5 pts)
4. Determine the discharge for a stage of 15 m (5 pts)
NB Do both arithmetic and logarithmic plots
Q2/ A (2m x 4 m) rectangular flexible foundation is placed above the ground
surface (G.S) for two layers of clay, each layer 10 m thick. The modulus of
Elasticity (E.) of the upper layer is 13 MN/m² and that of the lower layer is
15 MN/m². The Poisson ratio is (u, = 0.6) for the two layers. The pressure (stress) of
100 kN/m²is distributed along the surface of foundation. Determine the rigid
immediate settlement at the corner of the foundation using Elastic theory method?
Q1/ Find the maximum allowable load for a square foundation (3 m x 3 m) placed
vertically in cohesive soil? (Use Terzaghi equation)
Note:
Yt=Yeat=18 kN/m³
Depth of foundation = 1.5 m
Depth of water table below the ground surface = 0.8 m
Factor of safety 3
C=20
Yw = 10 kN/m³
=
No vertical or inclined loads
Chapter 24 Solutions
Elementary Surveying (14th Edition)
Ch. 24 - Prob. 24.1PCh. 24 - Prob. 24.2PCh. 24 - Prob. 24.3PCh. 24 - Prob. 24.4PCh. 24 - Prob. 24.5PCh. 24 - Prob. 24.6PCh. 24 - Prob. 24.7PCh. 24 - Prob. 24.8PCh. 24 - Prob. 24.9PCh. 24 - Prob. 24.10P
Ch. 24 - Prob. 24.11PCh. 24 - Prob. 24.12PCh. 24 - Prob. 24.13PCh. 24 - Prob. 24.14PCh. 24 - Prob. 24.15PCh. 24 - Prob. 24.16PCh. 24 - Prob. 24.17PCh. 24 - Prob. 24.18PCh. 24 - Prob. 24.19PCh. 24 - Prob. 24.20PCh. 24 - Prob. 24.21PCh. 24 - Prob. 24.22PCh. 24 - Prob. 24.23PCh. 24 - Prob. 24.24PCh. 24 - Prob. 24.25PCh. 24 - Prob. 24.26PCh. 24 - Prob. 24.27PCh. 24 - Prob. 24.28PCh. 24 - Prob. 24.29PCh. 24 - Prob. 24.30PCh. 24 - Prob. 24.31PCh. 24 - Prob. 24.32PCh. 24 - Prob. 24.33PCh. 24 - Prob. 24.34PCh. 24 - Prob. 24.35PCh. 24 - Prob. 24.36PCh. 24 - Prob. 24.37PCh. 24 - Prob. 24.38P
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