Mode of decay has to be predicted for 15 C . Concept Introduction: Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability. Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β − decay. Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e − capture and/or β + decay. Heavier elements mostly undergo e − capture whereas lighter elements undergo β + emission. Nuclides having Z > 83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Question

Want to see the full answer?

Answer 1

Question

Chapter 24, Problem 24.22P

(a)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 15C.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(b)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 120Xe.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(c)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 224Th.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Help me understand this! Thank you in advance.

22.22 For each compound, indicate which group on the ring is more strongly activating and then draw a structural formula of the major product formed by nitration of the compound. Br CHO (a) CH3 (b) (c) CHO CH3 SO₂H (d) ☑ OCHS NO₂ (e) (f) CO₂H NHCOCH3 NHCOCH, (h) CHS 22.23 The following molecules each contain two aromatic rings. (b) 000-100- H3C (a) (c) Which ring in each undergoes electrophilic aromatic substitution more readily? Draw the major product formed on nitration.

V Consider this step in a radical reaction: Br: ? What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. ⚫ionization termination initialization neutralization none of the abc Explanation Check 80 Ο F3 F1 F2 2 F4 01 % do5 $ 94 #3 X 5 C MacBook Air 25 F5 F6 66 ©2025 ˇ F7 29 & 7 8

Answer 2

Question

Chapter 24, Problem 24.22P

(a)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 15C.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(b)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 120Xe.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(c)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 224Th.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 24, Problem 24.22P

(a)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 15C.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(b)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 120Xe.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(c)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 224Th.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 24, Problem 24.22P

(a)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 15C.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(b)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 120Xe.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(c)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 224Th.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 24, Problem 24.22P

(a)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 15C.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(b)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 120Xe.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

(c)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 224Th.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Answer 6

Chapter 24, Problem 24.22P

(a)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 15C.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Answer 7

Chapter 24, Problem 24.22P

(a)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 15C.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Answer 8

(b)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 120Xe.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Answer 9

(b)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 120Xe.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Answer 10

(c)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 224Th.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Answer 11

(c)

Interpretation Introduction

Interpretation:

Mode of decay has to be predicted for 224Th.

Concept Introduction:

Nuclides that are unstable generally decay in a mode that changes its N/Z ratio to the band of stability.

Nuclides having many neutrons (Neutron-rich nuclides) have a high N/Z ratio and lies above the band of stability. Therefore, to decrease N/Z ratio these nuclides undergo β− decay.

Nuclides having many protons (Proton-rich nuclides) have a low N/Z ratio and lies below the band of stability. Therefore, to increase N/Z ratio these nuclides undergo e− capture and/or β+ decay. Heavier elements mostly undergo e− capture whereas lighter elements undergo β+ emission.

Nuclides having Z>83 are considered as too heavy to be stable. To decrease the values of Z and N, it undergoes α decay.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 24.1 - Prob. 24.1AFP Ch. 24.1 - Prob. 24.1BFP Ch. 24.1 - Prob. 24.2AFP Ch. 24.1 - Why is stable but unstable? Ch. 24.1 - Prob. 24.3AFP Ch. 24.1 - Prob. 24.3BFP Ch. 24.2 - Prob. 24.4AFP Ch. 24.2 - Prob. 24.4BFP Ch. 24.2 - Prob. 24.5AFP Ch. 24.2 - Prob. 24.5BFP

Concept explainers

Want to see the full answer?

Chapter 24 Solutions