Chapter 24, Problem 24.136P

(a)

Interpretation Introduction

Interpretation:

Energy released when $1.00kg$ each of antimatter and matter annihilate with each other has to be determined.

Concept Introduction:

Nuclear binding energy: It is the energy that requires for the breaking one mole of nuclei of an element to its individual nucleons.

  $\text{Nucleus + nuclear binding energy }\underset{}{\to }\text{ nucleons}$

Nuclear binding energy can be calculated by Einstein’s mass energy equivalence relationship that is,

  $\begin{array}{l}\text{E = }\Delta {\text{mc}}^2\\ \\ where,\\ \Delta \text{m = Mass Difference}\\ c=\text{ Speed of light}\end{array}$

(b)

Interpretation Introduction

Interpretation:

Energy released by $1.00\text{ kg}$ of $antiH$ has to be determined using the given data.

Concept Introduction:

Nuclear binding energy:  It is the energy that requires for the breaking one mole of nuclei of an element to its individual nucleons.

  $\text{Nucleus + nuclear binding energy }\underset{}{\to }\text{ nucleons}$

Change in mass of a given reaction can be determined as given,

  $\Delta m\text{ = }Mass\text{ of reactant}-\text{ Mass of products}$

Unit conversion:

  $\begin{array}{l}1\text{ amu = 931}\text{.5}\times {\text{10}}^6\text{ eV = 931}\text{.5 MeV}\\ \\ 1\text{ MeV = }\left({\text{10}}^6\text{ eV}\right)\left(\frac{1.602\times {10}^{-19}\text{ J}}{1\text{ eV}}\right)\end{array}$

(c)

Interpretation Introduction

Interpretation:

Procedure that produces more energy per kilogram of antihydrogen has to be determined from part (a) and part (b).

Concept Introduction:

Nuclear binding energy: It is the energy that requires for the breaking one mole of nuclei of an element to its individual nucleons.

  $\text{Nucleus + nuclear binding energy }\underset{}{\to }\text{ nucleons}$