a. Answer m ∠ V T P = 90 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ V T P and ∠ V T R are supplementary angles. m ∠ V T P + m ∠ V T R = 180 ° ⇒ m ∠ V T P + 90 ° = 180 ° [ ∠ V T R is right angle] ⇒ m ∠ V T P = 180 ° − 90 ° ⇒ m ∠ V T P = 90 ° Thus, m ∠ V T P = 90 ° b. To determine To find: The measure of the angle m ∠ X S Y . Answer m ∠ X S Y = 60 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ Q S R and ∠ X S Y are vertically opposite angles. Then, m ∠ X S Y = m ∠ Q S R [ ∵ Vertically opposite angles are congruent] ⇒ m ∠ X S Y = 60 ° [ ∵ m ∠ Q S R = 60 ° ] Thus, m ∠ X S Y = 60 ° c. To determine To find: The measure of the angle m ∠ R S X . Answer m ∠ R S X = 120 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ Q S R and ∠ R S X are supplementary angles. m ∠ Q S R + m ∠ R S X = 180 ° ⇒ 60 ° + m ∠ R S X = 180 ° [ m ∠ Q S R = 60 ° ] ⇒ m ∠ R S X = 180 ° − 60 ° ⇒ m ∠ R S X = 120 ° Thus, m ∠ R S X = 120 ° d. To determine To find: The measure of the angle m ∠ P S Y . Answer m ∠ P S Y = 90 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ P S R and ∠ P S Y are supplementary angles. m ∠ P S R + m ∠ P S Y = 180 ° ⇒ 90 ° + m ∠ P S Y = 180 ° [ m ∠ P S R = 90 ° ] ⇒ m ∠ P S Y = 180 ° − 90 ° ⇒ m ∠ P S Y = 90 ° Thus, m ∠ P S Y = 90 °

McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

See similar textbooks

Videos

Question

Chapter 2.4, Problem 20CE

To determine

To find: The measure of the angle m∠VTP .

Expert Solution

Answer to Problem 20CE

m∠VTP=90°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 1

Calculation:

From the figure it is observed that, ∠VTP and ∠VTR are supplementary angles.

m∠VTP+m∠VTR=180°⇒m∠VTP+90°=180° [∠VTR is right angle]⇒m∠VTP=180°−90°⇒m∠VTP=90°

Thus, m∠VTP=90°

To determine

To find: The measure of the angle m∠XSY .

Expert Solution

Answer to Problem 20CE

m∠XSY=60°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 2

Calculation:

From the figure it is observed that, ∠QSR and ∠XSY are vertically opposite angles.

Then,

m∠XSY=m∠QSR [∵Vertically opposite angles are congruent]⇒m∠XSY=60° [∵m∠QSR=60°]

Thus, m∠XSY=60°

To determine

To find: The measure of the angle m∠RSX .

Expert Solution

Answer to Problem 20CE

m∠RSX=120°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 3

Calculation:

From the figure it is observed that, ∠QSR and ∠RSX are supplementary angles.

m∠QSR+m∠RSX=180°⇒60°+m∠RSX=180° [m∠QSR=60°]⇒m∠RSX=180°−60°⇒m∠RSX=120°

Thus, m∠RSX=120°

To determine

To find: The measure of the angle m∠PSY .

Expert Solution

Answer to Problem 20CE

m∠PSY=90°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 4

Calculation:

From the figure it is observed that, ∠PSR and ∠PSY are supplementary angles.

m∠PSR+m∠PSY=180°⇒90°+m∠PSY=180° [m∠PSR=90°]⇒m∠PSY=180°−90°⇒m∠PSY=90°

Thus, m∠PSY=90°

Chapter 2.4, Problem 19CE

Chapter 2.4, Problem 21CE

Chapter 2 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 2.1 - Prob. 1CE Ch. 2.1 - Prob. 2CE Ch. 2.1 - Prob. 3CE Ch. 2.1 - Prob. 4CE Ch. 2.1 - Prob. 5CE Ch. 2.1 - Prob. 6CE Ch. 2.1 - Prob. 7CE Ch. 2.1 - Prob. 8CE Ch. 2.1 - Prob. 9CE Ch. 2.1 - Prob. 10CE

Ch. 2.1 - Prob. 11CE Ch. 2.1 - Prob. 12CE Ch. 2.1 - Prob. 13CE Ch. 2.1 - Prob. 14CE Ch. 2.1 - Prob. 15CE Ch. 2.1 - Prob. 16CE Ch. 2.1 - Prob. 1WE Ch. 2.1 - Prob. 2WE Ch. 2.1 - Prob. 3WE Ch. 2.1 - Prob. 4WE Ch. 2.1 - Prob. 5WE Ch. 2.1 - Prob. 6WE Ch. 2.1 - Prob. 7WE Ch. 2.1 - Prob. 8WE Ch. 2.1 - Prob. 9WE Ch. 2.1 - Prob. 10WE Ch. 2.1 - Prob. 11WE Ch. 2.1 - Prob. 12WE Ch. 2.1 - Prob. 13WE Ch. 2.1 - Prob. 14WE Ch. 2.1 - Prob. 15WE Ch. 2.1 - Prob. 16WE Ch. 2.1 - Prob. 17WE Ch. 2.1 - Prob. 18WE Ch. 2.1 - Prob. 19WE Ch. 2.1 - Prob. 20WE Ch. 2.1 - Prob. 21WE Ch. 2.1 - Prob. 22WE Ch. 2.1 - Prob. 23WE Ch. 2.1 - Prob. 24WE Ch. 2.1 - Prob. 25WE Ch. 2.1 - Prob. 26WE Ch. 2.1 - Prob. 27WE Ch. 2.1 - Prob. 28WE Ch. 2.1 - Prob. 29WE Ch. 2.1 - Prob. 30WE Ch. 2.1 - Prob. 31WE Ch. 2.1 - Prob. 1MRE Ch. 2.1 - Prob. 2MRE Ch. 2.1 - Prob. 3MRE Ch. 2.1 - Prob. 4MRE Ch. 2.2 - Prob. 1CE Ch. 2.2 - Prob. 2CE Ch. 2.2 - Prob. 3CE Ch. 2.2 - Prob. 4CE Ch. 2.2 - Prob. 5CE Ch. 2.2 - Prob. 6CE Ch. 2.2 - Prob. 7CE Ch. 2.2 - Prob. 8CE Ch. 2.2 - Prob. 9CE Ch. 2.2 - Prob. 10CE Ch. 2.2 - Prob. 11CE Ch. 2.2 - Prob. 12CE Ch. 2.2 - Prob. 1WE Ch. 2.2 - Prob. 2WE Ch. 2.2 - Prob. 3WE Ch. 2.2 - Prob. 4WE Ch. 2.2 - Prob. 5WE Ch. 2.2 - Prob. 6WE Ch. 2.2 - Prob. 7WE Ch. 2.2 - Prob. 8WE Ch. 2.2 - Prob. 9WE Ch. 2.2 - Prob. 10WE Ch. 2.2 - Prob. 11WE Ch. 2.2 - Prob. 12WE Ch. 2.2 - Prob. 13WE Ch. 2.2 - Prob. 14WE Ch. 2.2 - Prob. 15WE Ch. 2.3 - Prob. 1CE Ch. 2.3 - Prob. 2CE Ch. 2.3 - Prob. 3CE Ch. 2.3 - Prob. 4CE Ch. 2.3 - Prob. 5CE Ch. 2.3 - Prob. 6CE Ch. 2.3 - Prob. 7CE Ch. 2.3 - Prob. 8CE Ch. 2.3 - Prob. 9CE Ch. 2.3 - Prob. 10CE Ch. 2.3 - Prob. 1WE Ch. 2.3 - Prob. 2WE Ch. 2.3 - Prob. 3WE Ch. 2.3 - Prob. 4WE Ch. 2.3 - Prob. 5WE Ch. 2.3 - Prob. 6WE Ch. 2.3 - Prob. 7WE Ch. 2.3 - Prob. 8WE Ch. 2.3 - Prob. 9WE Ch. 2.3 - Prob. 10WE Ch. 2.3 - Prob. 11WE Ch. 2.3 - Prob. 12WE Ch. 2.3 - Prob. 13WE Ch. 2.3 - Prob. 14WE Ch. 2.3 - Prob. 15WE Ch. 2.3 - Prob. 16WE Ch. 2.3 - Prob. 17WE Ch. 2.3 - Prob. 18WE Ch. 2.3 - Prob. 19WE Ch. 2.3 - Prob. 20WE Ch. 2.3 - Prob. 21WE Ch. 2.3 - Prob. 22WE Ch. 2.3 - Prob. 1E Ch. 2.3 - Prob. 2E Ch. 2.3 - Prob. 3E Ch. 2.3 - Prob. 1ST1 Ch. 2.3 - Prob. 2ST1 Ch. 2.3 - Prob. 3ST1 Ch. 2.3 - Prob. 4ST1 Ch. 2.3 - Prob. 5ST1 Ch. 2.3 - Prob. 6ST1 Ch. 2.3 - Prob. 7ST1 Ch. 2.3 - Prob. 8ST1 Ch. 2.4 - Prob. 1CE Ch. 2.4 - Prob. 2CE Ch. 2.4 - Prob. 3CE Ch. 2.4 - Prob. 4CE Ch. 2.4 - Prob. 5CE Ch. 2.4 - Prob. 6CE Ch. 2.4 - Prob. 7CE Ch. 2.4 - Prob. 8CE Ch. 2.4 - Prob. 9CE Ch. 2.4 - Prob. 10CE Ch. 2.4 - Prob. 11CE Ch. 2.4 - Prob. 12CE Ch. 2.4 - Prob. 13CE Ch. 2.4 - Prob. 14CE Ch. 2.4 - Prob. 15CE Ch. 2.4 - Prob. 16CE Ch. 2.4 - Prob. 17CE Ch. 2.4 - Prob. 18CE Ch. 2.4 - Prob. 19CE Ch. 2.4 - Prob. 20CE Ch. 2.4 - Prob. 21CE Ch. 2.4 - Prob. 1WE Ch. 2.4 - Prob. 2WE Ch. 2.4 - Prob. 3WE Ch. 2.4 - Prob. 4WE Ch. 2.4 - Prob. 5WE Ch. 2.4 - Prob. 6WE Ch. 2.4 - Prob. 7WE Ch. 2.4 - Prob. 8WE Ch. 2.4 - Prob. 9WE Ch. 2.4 - Prob. 10WE Ch. 2.4 - Prob. 11WE Ch. 2.4 - Prob. 12WE Ch. 2.4 - Prob. 13WE Ch. 2.4 - Prob. 14WE Ch. 2.4 - Prob. 15WE Ch. 2.4 - Prob. 16WE Ch. 2.4 - Prob. 17WE Ch. 2.4 - Prob. 18WE Ch. 2.4 - Prob. 19WE Ch. 2.4 - Prob. 20WE Ch. 2.4 - Prob. 21WE Ch. 2.4 - Prob. 22WE Ch. 2.4 - Prob. 23WE Ch. 2.4 - Prob. 24WE Ch. 2.4 - Prob. 25WE Ch. 2.4 - Prob. 26WE Ch. 2.4 - Prob. 27WE Ch. 2.4 - Prob. 28WE Ch. 2.4 - Prob. 29WE Ch. 2.4 - Prob. 30WE Ch. 2.4 - Prob. 31WE Ch. 2.4 - Prob. 32WE Ch. 2.4 - Prob. 33WE Ch. 2.4 - Prob. 34WE Ch. 2.4 - Prob. 35WE Ch. 2.4 - Prob. 1E Ch. 2.4 - Prob. 2E Ch. 2.4 - Prob. 3E Ch. 2.4 - Prob. 4E Ch. 2.5 - Prob. 1CE Ch. 2.5 - Prob. 2CE Ch. 2.5 - Prob. 3CE Ch. 2.5 - Prob. 4CE Ch. 2.5 - Prob. 5CE Ch. 2.5 - Prob. 6CE Ch. 2.5 - Prob. 7CE Ch. 2.5 - Prob. 8CE Ch. 2.5 - Prob. 9CE Ch. 2.5 - Prob. 10CE Ch. 2.5 - Prob. 11CE Ch. 2.5 - Prob. 1WE Ch. 2.5 - Prob. 2WE Ch. 2.5 - Prob. 3WE Ch. 2.5 - Prob. 4WE Ch. 2.5 - Prob. 5WE Ch. 2.5 - Prob. 6WE Ch. 2.5 - Prob. 7WE Ch. 2.5 - Prob. 8WE Ch. 2.5 - Prob. 9WE Ch. 2.5 - Prob. 10WE Ch. 2.5 - Prob. 11WE Ch. 2.5 - Prob. 12WE Ch. 2.5 - Prob. 13WE Ch. 2.5 - Prob. 14WE Ch. 2.5 - Prob. 15WE Ch. 2.5 - Prob. 16WE Ch. 2.5 - Prob. 17WE Ch. 2.5 - Prob. 18WE Ch. 2.5 - Prob. 19WE Ch. 2.5 - Prob. 20WE Ch. 2.5 - Prob. 21WE Ch. 2.5 - Prob. 22WE Ch. 2.5 - Prob. 23WE Ch. 2.5 - Prob. 24WE Ch. 2.5 - Prob. 25WE Ch. 2.5 - Prob. 26WE Ch. 2.5 - Prob. 27WE Ch. 2.5 - Prob. 28WE Ch. 2.5 - Prob. 29WE Ch. 2.5 - Prob. 1MRE Ch. 2.5 - Prob. 2MRE Ch. 2.5 - Prob. 3MRE Ch. 2.5 - Prob. 4MRE Ch. 2.5 - Prob. 5MRE Ch. 2.5 - Prob. 6MRE Ch. 2.5 - Prob. 7MRE Ch. 2.6 - Prob. 1CE Ch. 2.6 - Prob. 2CE Ch. 2.6 - Prob. 3CE Ch. 2.6 - Prob. 4CE Ch. 2.6 - Prob. 5CE Ch. 2.6 - Prob. 6CE Ch. 2.6 - Prob. 7CE Ch. 2.6 - Prob. 8CE Ch. 2.6 - Prob. 9CE Ch. 2.6 - Prob. 10CE Ch. 2.6 - Prob. 1WE Ch. 2.6 - Prob. 2WE Ch. 2.6 - Prob. 3WE Ch. 2.6 - Prob. 4WE Ch. 2.6 - Prob. 5WE Ch. 2.6 - Prob. 6WE Ch. 2.6 - Prob. 7WE Ch. 2.6 - Prob. 8WE Ch. 2.6 - Prob. 9WE Ch. 2.6 - Prob. 10WE Ch. 2.6 - Prob. 11WE Ch. 2.6 - Prob. 12WE Ch. 2.6 - Prob. 13WE Ch. 2.6 - Prob. 14WE Ch. 2.6 - Prob. 15WE Ch. 2.6 - Prob. 16WE Ch. 2.6 - Prob. 17WE Ch. 2.6 - Prob. 18WE Ch. 2.6 - Prob. 19WE Ch. 2.6 - Prob. 20WE Ch. 2.6 - Prob. 21WE Ch. 2.6 - Prob. 22WE Ch. 2.6 - Prob. 23WE Ch. 2.6 - Prob. 24WE Ch. 2.6 - Prob. 25WE Ch. 2.6 - Prob. 1ST2 Ch. 2.6 - Prob. 2ST2 Ch. 2.6 - Prob. 3ST2 Ch. 2.6 - Prob. 4ST2 Ch. 2.6 - Prob. 5ST2 Ch. 2.6 - Prob. 6ST2 Ch. 2.6 - Prob. 7ST2 Ch. 2.6 - Prob. 8ST2 Ch. 2.6 - Prob. 9ST2 Ch. 2.6 - Prob. 1E Ch. 2.6 - Prob. 2E Ch. 2.6 - Prob. 3E Ch. 2.6 - Prob. 4E Ch. 2.6 - Prob. 5E Ch. 2 - Prob. 1CR Ch. 2 - Prob. 2CR Ch. 2 - Prob. 3CR Ch. 2 - Prob. 4CR Ch. 2 - Prob. 5CR Ch. 2 - Prob. 6CR Ch. 2 - Prob. 7CR Ch. 2 - Prob. 8CR Ch. 2 - Prob. 9CR Ch. 2 - Prob. 10CR Ch. 2 - Prob. 11CR Ch. 2 - Prob. 12CR Ch. 2 - Prob. 13CR Ch. 2 - Prob. 14CR Ch. 2 - Prob. 15CR Ch. 2 - Prob. 16CR Ch. 2 - Prob. 17CR Ch. 2 - Prob. 18CR Ch. 2 - Prob. 19CR Ch. 2 - Prob. 20CR Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 1AR Ch. 2 - Prob. 2AR Ch. 2 - Prob. 3AR Ch. 2 - Prob. 4AR Ch. 2 - Prob. 5AR Ch. 2 - Prob. 6AR Ch. 2 - Prob. 7AR Ch. 2 - Prob. 8AR Ch. 2 - Prob. 9AR Ch. 2 - Prob. 10AR Ch. 2 - Prob. 11AR Ch. 2 - Prob. 12AR Ch. 2 - Prob. 13AR Ch. 2 - Prob. 14AR Ch. 2 - Prob. 15AR Ch. 2 - Prob. 16AR Ch. 2 - Prob. 17AR Ch. 2 - Prob. 18AR Ch. 2 - Prob. 1CUR Ch. 2 - Prob. 2CUR Ch. 2 - Prob. 3CUR Ch. 2 - Prob. 4CUR Ch. 2 - Prob. 5CUR Ch. 2 - Prob. 6CUR Ch. 2 - Prob. 7CUR Ch. 2 - Prob. 8CUR Ch. 2 - Prob. 9CUR Ch. 2 - Prob. 10CUR Ch. 2 - Prob. 11CUR Ch. 2 - Prob. 12CUR Ch. 2 - Prob. 13CUR Ch. 2 - Prob. 14CUR Ch. 2 - Prob. 15CUR Ch. 2 - Prob. 16CUR Ch. 2 - Prob. 17CUR Ch. 2 - Prob. 18CUR Ch. 2 - Prob. 19CUR Ch. 2 - Prob. 20CUR Ch. 2 - Prob. 21CUR Ch. 2 - Prob. 22CUR Ch. 2 - Prob. 23CUR Ch. 2 - Prob. 24CUR Ch. 2 - Prob. 25CUR

Additional Math Textbook Solutions

Find more solutions based on key concepts

In hypothesis testing, the common level of significance is =0.05. Some might argue for a level of significance ...

Basic Business Statistics, Student Value Edition

Identifying a Test In Exercises 21–24, determine whether the hypothesis test is left-tailed, right-tailed, or t...

Elementary Statistics: Picturing the World (7th Edition)

Standard Normal Distribution. In Exercises 17–36, assume that a randomly selected subject is given a bone densi...

Elementary Statistics (13th Edition)

How many outcome sequences are possible ten a die is rolled four times, where we say, for instance, that the ou...

A First Course in Probability (10th Edition)

Assessment 1-1A The following is a magic square all rows, columns, and diagonals sum to the same number. Find t...

A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)

Integral Test Use the Integral Test to determine the convergence or divergence of the following series, or stat...

Calculus: Early Transcendentals (2nd Edition)

Knowledge Booster

$Geometry$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.

Recommended textbooks for you

Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,
Elementary Geometry for College Students
Geometry
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Cengage Learning

Elementary Geometry For College Students, 7e

Geometry

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Cengage,

Elementary Geometry for College Students

Geometry

ISBN:9781285195698

Author:Daniel C. Alexander, Geralyn M. Koeberlein

Publisher:Cengage Learning

SEE MORE TEXTBOOKS

What are the Different Types of Triangles? | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=1k0G-Y41jRA;License: Standard YouTube License, CC-BY

Law of Sines AAS, ASA, SSA Ambiguous Case; Author: Mario's Math Tutoring;https://www.youtube.com/watch?v=FPVGb-yWj3s;License: Standard YouTube License, CC-BY

Introduction to Statistics..What are they? And, How Do I Know Which One to Choose?; Author: The Doctoral Journey;https://www.youtube.com/watch?v=HpyRybBEDQ0;License: Standard YouTube License, CC-BY

Triangles | Mathematics Grade 5 | Periwinkle; Author: Periwinkle;https://www.youtube.com/watch?v=zneP1Q7IjgQ;License: Standard YouTube License, CC-BY

What Are Descriptive Statistics And Inferential Statistics?; Author: Amour Learning;https://www.youtube.com/watch?v=MUyUaouisZE;License: Standard Youtube License

The measure of the angle m ∠ V T P .

Videos

To find: The measure of the angle m∠VTP .

Answer to Problem 20CE

Explanation of Solution

To find: The measure of the angle m∠XSY .

Answer to Problem 20CE

Explanation of Solution

To find: The measure of the angle m∠RSX .

Answer to Problem 20CE

Explanation of Solution

To find: The measure of the angle m∠PSY .

Answer to Problem 20CE

Explanation of Solution

Chapter 2 Solutions

Additional Math Textbook Solutions