Chapter 24, Problem 18P

As described in Prob. 24.17, the cross-sectional area of a channel can be computed as

$A_c={\int }_0^{B}H\left(y\right)dy$

Where $B=$ the total channel width $\left(\text{m}\right),H=$ the depth $\left(\text{m}\right),\text{ and }y=$ distance from the bank $\left(\text{m}\right)$. In a similar fashion, the average flow $Q\left({\text{m}}^3/\text{s}\right)$ can be computed as

$Q={\int }_0^{B}U\left(y\right)H\left(y\right)dy$

Where $U=$ water velocity $\left(\text{m}/\text{s}\right)$ Use these relationships and a numerical method to determine $A_c\text{ and }Q$ for the following data:

y, m	0	2	4	5	6	9
H, m	0.5	1.3	1.25	1.7	1	0.25
U, m/s	0.03	0.06	0.05	0.12	0.11	0.02