2 SEM ACC W/RAVEN CARDED
12th Edition
ISBN: 9781264439218
Author: Raven
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 23.4, Problem 1LO
Summary Introduction
To determine: The importance of homoplasy in order to interpret the patterns of evolutionary change.
Introduction: Homoplasy within biology and phylogenetics implies when a feature has achieved or failed individually in distinct lineages throughout evolution. The method is distinctive from homology, which is the association of traits that can be described by common ancestry.
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Look at the ideal results. Were your predictions accurate, and how did they compare with your results?
a) Calculating Transformation Efficiency
For the +DNA/+Amp/+IPTG plate, record the following:
Number of transformants (colonies): _________________
Nanograms of plasmid DNA added: 50 ng
Final recovery volume: 0.50 mL
Volume plated: 0.25 mL
Transformation efficiency equation:
Transformation efficiency = Number of transformants / µg of DNA x Final volume at recovery (mL)/ volume plated (mL)
b) Using the equation above, calculate the transformation efficiency.
c) Describe the success of the transformation efficiency of this demo based on the calculation you did above?
a) What differences would you expect to see between the -DNA/+Amp and +DNA/+Amp plates?
b) Predict the growth you would expect to see on each of the following plates:
– DNA ___________________________________________________________
– DNA/+Amp ______________________________________________________
+DNA/+Amp ______________________________________________________
+DNA/+Amp/+IPTG _________________________________________________
Chapter 23 Solutions
2 SEM ACC W/RAVEN CARDED
Ch. 23.1 - Prob. 1LOCh. 23.1 - Prob. 2LOCh. 23.2 - Prob. 1LOCh. 23.2 - Prob. 2LOCh. 23.2 - Demonstrate how a cladogram is constructed.Ch. 23.3 - Explain the taxonomic classification system.Ch. 23.3 - Prob. 2LOCh. 23.3 - Prob. 3LOCh. 23.4 - Prob. 1LOCh. 23.4 - Prob. 2LO
Ch. 23.4 - Prob. 3LOCh. 23.5 - Prob. 1LOCh. 23 - Construct a data matrix like the one in figure...Ch. 23 - Prob. 1IQCh. 23 - Prob. 2IQCh. 23 - Prob. 3IQCh. 23 - Prob. 4IQCh. 23 - Overall similarity of phenotypes may not always...Ch. 23 - a. is based on overall similarity of phenotypes....Ch. 23 - The principle of parsimony a. helps evolutionary...Ch. 23 - Parsimony suggests that parental care in birds,...Ch. 23 - The forelimb of a bird and the forelimb of a...Ch. 23 - In order to determine polarity for different...Ch. 23 - In a paraphyletic group a. all species are more...Ch. 23 - A paraphyletic group includes a. an ancestor and...Ch. 23 - Prob. 9UCh. 23 - A taxonomic group that contains species that have...Ch. 23 - Rapid rates of character change relative to the...Ch. 23 - Species recognized by the phylogenetic species...Ch. 23 - Prob. 1SCh. 23 - Identifying outgroups is a central component of...Ch. 23 - As noted in your reading, cladistics is a widely...Ch. 23 - Across many species of limpets, loss of larval...Ch. 23 - Birds, pterosaurs (a type of flying reptile that...Ch. 23 - AID:1825 | 10/04/2018 6. In what sense does the...
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- Overview of Transformation Protocol -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes. Questions: 1)What is the selectable marker in this experiment? How…arrow_forwardBased on your results, which suspect's DNA best matches the DNA found at the crime scene?arrow_forwardIn oxidase test with Pseudomonas aeruginosa, the cell cultures on the slide turn colorless to be purple after tetra-methyl-p-phenylenediamine dihydrochloride (TMPD) is added. In the reaction, OTMPD is electron acceptor O cytochrome c is the electron source oxygen is terminal electron acceptor OH2 produced is electron donorarrow_forward
- You will use the following scenario to answer a group of 5 questions. You have isolated a microbe from an environmental sample. The microbe has the ability to perform a new metabolic reaction at a very low temperature, so you are excited that it could be a new species. You have shipped your samples off for sequencing and are now waiting for the results. Out of curiosity (and maybe boredom...) you decide to test your culture for the Catalase and Oxidase enzymes. Upon testing your sample for catalase, you don't see any bubbles; however, you do see a color change to purple during the Oxidase test. What results can you conclude from this? O Catalase-/ Oxidase + O Catalase +/ Oxidase + Catalase + / Oxidase- O Catalase / Oxidase - O None of the abovearrow_forwardWhich of the following is not a strength of using 16S rRNA for phylogenetic analyses? OA. It's cheap OB. It's easy to do C. It can be used to identify all the way down to the strain level OD. Both A & B OE. None of the abovearrow_forwardWhy are molecular approaches important to the field of microbial taxonomy and phylogeny? Phylogenetic inferences based on molecular approaches provide the most robust analysis of microbial evolution currently available. It allows for the collection of a large and accurate dataset from many organisms Almost no fossil record was left by microbes when compared to plants and animals All of the above None of the abovearrow_forward
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