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a) 2-cyclohexanone
Interpretation:
The product obtained in the base catalyzed Michael reaction of 2, 4-pentanedione with 2-cyclohexanone (α, β- unsaturated acceptor) is to be given.
Concept introduction:
Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β- diketones or β- ketonitriles or malonic esters (donors) to an unhindered α,β- unsaturated
To give:
The product obtained in the base catalyzed Michael reaction of 2, 4-pentanedione with 2-cyclohexanone (α, β- unsaturated acceptor).
b) Propenenitrile
Interpretation:
The product obtained in the base catalyzed Michael reaction of 2, 4-pentanedione with propenenitrile (α, β- unsaturated acceptor) is to be given.
Concept introduction:
Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β- diketones or β- ketonitriles or malonic esters (donors) to an unhindered α,β- unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β- carbon of the unsaturated ester.
To give:
The product obtained in the base catalyzed Michael reaction of 2, 4-pentanedione with propenenitrile (α, β- unsaturated acceptor).
c) Ethyl-2-butenoate
Interpretation:
The product obtained in the base catalyzed Michael reaction of 2, 4-pentanedione with ethyl-2-butenoate (α, β- unsaturated acceptor) is to be given.
Concept introduction:
Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β- diketones or β- ketonitriles or malonic esters (donors) to an unhindered α,β- unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β- carbon of the unsaturated ester.
To give:
The product obtained in the base catalyzed Michael reaction of 2, 4-pentanedione with ethyl-2-butenoate (α, β- unsaturated acceptor).
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Chapter 23 Solutions
OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card for McMurry's Organic Chemistry, 9th
- Nonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forward
- given cler asnwerarrow_forwardAdd curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Draw curved arrows. : 0: si H : OH :: H―0: Harrow_forwardConsider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑arrow_forward
- Nonearrow_forwardCan I get a drawing of what is happening with the orbitals (particularly the p orbital) on the O in the OH group? Is the p orbital on the O involved in the ring resonance? Why or why not?arrow_forward1) How many monochlorination products-including stereochemistry- are there for the molecule below:arrow_forward
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