a.
To calculate: The points of horizontal tangents.
a.
Answer to Problem 4QQ
The points are
Explanation of Solution
Given information:
The function is.
Concept used:
The formula used is
Calculation:
The function is
Differentiate the function with respect to
Equate the derivative to zero for the point of horizontal tangents.
Substitute
Substitute
Substitute
Conclusion: The equation of tangents are
b.
To calculate: The equation of tangent at
b.
Answer to Problem 4QQ
The equation of tangent is
Explanation of Solution
Given information:
The function is.
Concept used:
The formula used is
Calculation:
The function is
Differentiate the function with respect to
Substitute
Substitute
Substitute the values in the formula
Conclusion: The equation of tangent is
c.
To calculate: The equation of normal line at
c.
Answer to Problem 4QQ
The equation of normal is
Explanation of Solution
Given information:
The function is.
Concept used:
The formula used is
Calculation:
The function is
Differentiate the function with respect to
Substitute
Use the formula
The slope of normal is
Substitute
Substitute the values in the formula
Conclusion: The equation of normal is
Chapter 2 Solutions
Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
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