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Chapter 23, Problem 4P

The electric field along the axis of a uniformly charged disk of radius R and total charge Q was calculated in Example 23.3. Show that the electric field at distances x that are large compared with R approaches that of a particle with charge Q = σπR2. Suggestion: First show that x/(x2 + R2)1/2 = (1 + R2/x2)−1/2 and use the binomial expansion (1 + δ)n = 1 + , when δ << 1.

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The electric field along the axis of a uniformly charged disk of radius R and total charge Q was calculated the given example. Show that the electric field at distances x that are large compared with R approaches that of a particle with charge Q = σπR2. Suggestion: First show that x/(x2 + R2)1/2 = (1 +R2/x2)-1/2 and use the binomial expansion (1 + δ)n ≈ 1 + nδ, when δ << 1.
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Two conductors with concentric radii r1=5 m and r2=22 m are placed in such a way that their center is the origin. While there is a charge Q1=8 uC on the circle with radius r1, there is a charge Q2=3,8 µC Accordingly, the electric field at point A(19, 32°, 45°) is given below. Find the amplitude of the electric field. n=3,1416 E= 36 10-9 Q2 12 Q1

Chapter 23 Solutions

Bundle: Physics For Scientists And Engineers With Modern Physics, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Multi-term

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