
If all carbohydrates are digestible by humans or not.

Answer to Problem 3RQ
All the carbohydrate are not digestible by human beings, one of them is cellulose. It is so because of the absence of cellulase enzyme in
Explanation of Solution
Carbohydrates which upon hydrolysis give a large number of monosaccharide molecules are considered as polysaccharides. The one of the polysaccharide is not digestible by human. The name of that polysaccharide is cellulose.
The molecular mass of cellulose varies from
The human digestive system does not contain enzyme cellulase which can hydrolyse cellulose into glucose and hence cannot digest cellulose. However,the enzyme cellulaseenzyme is present in stomach of ruminant mammals that is grazing animals where they are produced by intestinal bacteria such as cows, buffalo, and many others.
Thus, the grazing animals can use cellulose of grass and plants as food by covering then into glucose.
Hence, all the carbohydrates are not digestible by human beings.
Conclusion:
The carbohydrate which is not digestible by human beings is cellulose. This is so because there is the absence of cellulase enzyme in digestive system of the humans.
Chapter 23 Solutions
Conceptual Physical Science Explorations
Additional Science Textbook Solutions
Applications and Investigations in Earth Science (9th Edition)
Biology: Life on Earth with Physiology (11th Edition)
Campbell Biology in Focus (2nd Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Chemistry: A Molecular Approach (4th Edition)
Microbiology: An Introduction
- Pls help ASAParrow_forward9. Light of wavelength 442 nm is sent through a single slit with a width of 884 nm. At what angle does the first dark fringe occur? a. 30.0° b. 45.0° C. 60.0° d. 90.0° 10. Light travels through a single-slit and forms an interference pattern. The spacing of the dark fringes on one side of the pattern is 1.44 cm. What is the width of the central maximum? a. 0.720 cm 1.44 cm b. C. 2.88 cm d. 4.32 cmarrow_forwardPls help ASAParrow_forward
- d. when the index of refraction of medium A is equal to the index of refraction of medium B 7. What is the term for the bending of a wave front as it passes an obstacle? a. interference b. reflection C. d. diffraction refraction 8. A ray of light travels from air into a soap film on a layer of glass, as shown right. Which statement about ray 1 is true? a. There is no inversion at either surface. b. There is an inversion the surface between air and soap, but not soap and glass. C. There is no inversion at the surface between air and soap, incident light ray 1 ray 2 ray 3 but there is one at the surface between soap and glass. d. There is an inversion at both surfaces. air = nair 1.00 soap film nfilm = 1.35 glass = nglass 1.50arrow_forwardA circular wire with radius 0.4 meters in on x-y plane. There is a constant Magnetic field with 14T strengthtowards z-axis. Find the magnitude of the electromotive force and the direction of the current for a) B decreasesto 10T in 5 seconds. B) B is rotated by 45 degrees and the area doubles in 4 seconds.arrow_forwardWrite the expression for the magnetic flux inside a region om x-z plane at y=0 bounded by z=3x z=0 x=5 x=7due to a magnetic field B = f(x,y,z) i +g(x,y,z) j + h(x,y,z) karrow_forward
- Explain mutual inductance of two loops facing one another and compare with one loop inside the other.arrow_forwardTwo very long wires carry each 3 amps current in the same direction along the z-axis (outward). First is at x=0y=0 current is upward. Second at x=0 y=3 current is also upward. Find the net magnetic field at x=4 y=3.arrow_forwardFind the integral expression for the magnetic field at x=5 y=6 due to a wire on the x axis with length 5 meters onend at x=0 and the other at x=5. Don’t take the integralarrow_forward
- Two very long wires carry current along y-axis. First is at x=0 0.45 amps current is upward. Second at x=5 currentwith 0.65 amps current downward. Find the net magnetic a) Two meters to the left of the first wire. b) Twometers to the right of the first wire. a) Two meters to the right of the second wire. b) Two meters to the right ofthe second wire.arrow_forward! Required information The PV diagram shown is for a heat engine that uses 1.030 mol of a diatomic ideal gas as its working substance. In the constant-temperature processes A and C, the gas is in contact with reservoirs at temperatures 373 K and 273 K, respectively. In constant-volume process B, the gas temperature decreases as heat flows into the cold reservoir. In constant- volume process D, the gas temperature increases as heat flows from the hot reservoir. Pressure (kPa) 160 150 A 140 D 373 K 130 120 110 100 273 K C 90 80 B 0.019 0.02 0.021 0.022 0.023 0.024 0.025 0.026 Volume (m³) To compare the efficiency of the heat engine to that of an ideal engine, what is the ratio of the efficiency of an ideal engine using the same reservoirs to that of the heat engine, if the heat input per cycle is 2854 J?arrow_forward4 1.00 mol of oxygen gas (O2) is heated at a constant pressure of 1.00 atm from 10.0°C to 25.0°C. How much heat is absorbed by the gas? Multiple Choice О 389 J о 544 J О 436 J О 288 Jarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





