Chapter 23, Problem 23.88QP

(a)

Interpretation Introduction

Interpretation:

The given set of combustion reaction has to be completed and balanced.

Concept Introduction:

Combustion is a process in which a compound is burnt in presence of oxygen.  The by-products obtained during combustion reaction is carbon dioxide and water.

Answer to Problem 23.88QP

The combustion reaction can be given as,

${\text{2C}}_{\text{6}}{\text{H}}_{\text{14}}{\text{ + 19O}}_{\text{2}}\stackrel{}{\to }{\text{12CO}}_{\text{2}}\text{+}{\text{14H}}_{\text{2}}\text{O}$

Explanation of Solution

2-methylpentane has the molecular formula of ${\text{C}}_{\text{6}}{\text{H}}_{\text{14}}$.  When this undergoes combustion with oxygen, a total of 12 carbon dioxide molecules and 14 water molecules are formed as product.  The equation can be given as,

${\text{2C}}_{\text{6}}{\text{H}}_{\text{14}}{\text{ + 19O}}_{\text{2}}\stackrel{}{\to }{\text{12CO}}_{\text{2}}\text{+}{\text{14H}}_{\text{2}}\text{O}$

(b)

Interpretation Introduction

Interpretation:

The given set of combustion reaction has to be completed and balanced.

Concept Introduction:

Combustion is a process in which a compound is burnt in presence of oxygen.  The by-products obtained during combustion reaction is carbon dioxide and water.

Answer to Problem 23.88QP

The combustion reaction can be given as,

${\text{C}}_5{\text{H}}_{\text{12}}{\text{ + 8O}}_{\text{2}}\stackrel{}{\to }5{\text{CO}}_{\text{2}}\text{+}6{\text{H}}_{\text{2}}\text{O}$

Explanation of Solution

2,2-dimethylpropane has the molecular formula of ${\text{C}}_5{\text{H}}_{\text{12}}$.  When this undergoes combustion with oxygen, a total of 5 carbon dioxide molecules and 6 water molecules are formed as product.  The equation can be given as,

${\text{C}}_5{\text{H}}_{\text{12}}{\text{ + 8O}}_{\text{2}}\stackrel{}{\to }5{\text{CO}}_{\text{2}}\text{+}6{\text{H}}_{\text{2}}\text{O}$

(c)

Interpretation Introduction

Interpretation:

The given set of combustion reaction has to be completed and balanced.

Concept Introduction:

Combustion is a process in which a compound is burnt in presence of oxygen.  The by-products obtained during combustion reaction is carbon dioxide and water.

Answer to Problem 23.88QP

The combustion reaction can be given as,

${\text{2C}}_7{\text{H}}_{\text{14}}{\text{ + 21O}}_{\text{2}}\stackrel{}{\to }14{\text{CO}}_{\text{2}}\text{+}14{\text{H}}_{\text{2}}\text{O}$

Explanation of Solution

3-methyl-3-hexene has the molecular formula of ${\text{C}}_7{\text{H}}_{\text{14}}$.  When this undergoes combustion with oxygen, a total of 14 carbon dioxide molecules and 14 water molecules are formed as product.  The equation can be given as,

${\text{2C}}_7{\text{H}}_{\text{14}}{\text{ + 21O}}_{\text{2}}\stackrel{}{\to }14{\text{CO}}_{\text{2}}\text{+}14{\text{H}}_{\text{2}}\text{O}$

(d)

Interpretation Introduction

Interpretation:

The given set of combustion reaction has to be completed and balanced.

Concept Introduction:

Combustion is a process in which a compound is burnt in presence of oxygen.  The by-products obtained during combustion reaction is carbon dioxide and water.

Answer to Problem 23.88QP

The combustion reaction can be given as,

${\text{2C}}_5{\text{H}}_{\text{12}}{\text{O + 15O}}_{\text{2}}\stackrel{}{\to }{\text{10CO}}_{\text{2}}\text{+}{\text{12H}}_{\text{2}}\text{O}$

Explanation of Solution

3-ethyl-2-propanol has the molecular formula of ${\text{C}}_{\text{5}}{\text{H}}_{\text{12}}\text{O}$.  When this undergoes combustion with oxygen, a total of 10 carbon dioxide molecules and 12 water molecules are formed as product.  The equation can be given as,

${\text{2C}}_5{\text{H}}_{\text{12}}{\text{O + 15O}}_{\text{2}}\stackrel{}{\to }{\text{10CO}}_{\text{2}}\text{+}{\text{12H}}_{\text{2}}\text{O}$

(e)

Interpretation Introduction

Interpretation:

The given set of combustion reaction has to be completed and balanced.

Concept Introduction:

Combustion is a process in which a compound is burnt in presence of oxygen.  The by-products obtained during combustion reaction is carbon dioxide and water.

Answer to Problem 23.88QP

The combustion reaction can be given as,

${\text{2C}}_8{\text{H}}_{\text{10}}{\text{ + 21O}}_{\text{2}}\stackrel{}{\to }{\text{16CO}}_{\text{2}}\text{+}10{\text{H}}_{\text{2}}\text{O}$

Explanation of Solution

ethylbenzene has the molecular formula of ${\text{C}}_8{\text{H}}_{10}$.  When this undergoes combustion with oxygen, a total of 16 carbon dioxide molecules and 10 water molecules are formed as product.  The equation can be given as,

${\text{2C}}_8{\text{H}}_{\text{10}}{\text{ + 21O}}_{\text{2}}\stackrel{}{\to }{\text{16CO}}_{\text{2}}\text{+}10{\text{H}}_{\text{2}}\text{O}$