(a)
Interpretation:
The alcohol present in the given compound has to be classified whether it is primary, secondary or tertiary.
Concept Introduction:
In an organic compound, the reactive portion is known as functional group. This undergoes reactions with other reagents and this does not depend upon how the rest of the compound is like. Few of the common
The nitrogen containing linear compounds are classified as
(b)
Interpretation:
The alcohol present in the given compound has to be classified whether it is primary, secondary or tertiary.
Concept Introduction:
In an organic compound, the reactive portion is known as functional group. This undergoes reactions with other reagents and this does not depend upon how the rest of the compound is like. Few of the common functional groups are alcohol, ester, carboxylic acid, ketone, aldehyde etc. Functional group determines the nature of the compound.
The nitrogen containing linear compounds are classified as amines and amides. Amines are compounds that have nitrogen connected to alkyl or aromatic groups. Amides are compounds that have nitrogen connected to a carbonyl bond. In amine, if the nitrogen is bonded to only one alkyl group, it is known as primary amine. If the nitrogen is bonded to two alkyl, or two aromatic groups it is known as secondary amine. If the nitrogen is bonded to three alkyl or aromatic groups it is known as tertiary amine. If the nitrogen is bonded to a carbonyl group means it is known as amide.
To Identify: Whether the given compound is a primary, secondary or tertiary amine, or an amide.
Trending nowThis is a popular solution!
Chapter 23 Solutions
General Chemistry - Standalone book (MindTap Course List)
- Consider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> C2H4Cl 2 MW = 26 36.5 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?arrow_forwardWhat is the name of the major product of this reaction? OH CH3 H₂SO4, heat 1-methylcyclohexene O2-methyl-1-cyclohexene O 3-mthylcyclohexene 1-methyl-2-cyclohexenearrow_forwardWe added a brown solution of Br2 to one of our products, and the brown color disappeared. This indicated that our product wasarrow_forward
- Rank the following according to reactivity toward nitration: a) benzene b) bromobenzene c) nitrobenzene d) phenol Od) greatest, c) least Od) greatest, b) least Od) greatest, a) least a) greatest, b) least a) greatest, c) least Oa) greatest, d) least Ob) greatest, a) least O b) greatest, c) least Ob) greatest, d) least O c) greatest, a) least O c) greatest, b) least O c) greatest, d) leastarrow_forwardO-Nitrophenol was distilled over with the steam in our experiment while the other isomer did not. This is due to: O intramolecular hydrogen bonding in the ortho isomer O intermolecular hydrogen bonding in the the ortho isomer O the ortho isomer has a lower density O the ortho isomer has a lower molecular weightarrow_forwardK 44% Problem 68 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :6: :: :CI: CI CI: :0:0 Select to Add Arrows Select to Add Arrows H H Cl CI: CI CI: Select to Add Arrows Select to Add Arrows H :CI: Alarrow_forward
- I I H :0: Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. 0:0 :0: CI ΑΙ :CI: :CI: :0: CI Select to Add Arrows Select to Add Arrows cl. :0: Cl © ハ CI:: CI H CO Select to Add Arrows Select to Add Arrows 10: AI ::arrow_forwardOrder the following compounds from slowest to fastest in a nucleophilic acyl substitution reaction. ii 요 OB D A E C OCE Darrow_forwardI need the most help figuring out how to find [I^-] mol/ L, [S2O8^2-] mol/L. 1st and 2nd Blank columns.arrow_forwardCan someone help me whats the issue?arrow_forwarda. The change in the Gibbs energy of a certain constant pressure process is found to fit the expression: AG-85.1 J mol −1 +36.5 J mol ¹K-1 × T A. Calculate the value of AS for the process. B. Next, use the Gibbs-Helmholtz equation: (a(AG/T)) ΔΗ - T2 to calculate the value of AH for the process.arrow_forwardNonearrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning