Interpretation:
The changes of the oxidation state of cobalt in the course of methylmalonyl CoA mutase reaction should be discussed.
Concept Introduction:
The final product of ß oxidation of fatty acids with odd number of carbon is 3-C propionyl CoA instead of acetyl CoA. Then propionyl CoA is converted into succinyl CoA via several steps.
The carboxylation of a propionyl CoA to produce D-methylmalonyl CoA is the first step. The catalyst for the reaction is a biotin dependent enzyme propionyl CoA carboxylase. In the next step, D-methylmalonyl CoA so formed is isomerized into L-isomer by methylmalonyl CoA epimerase.
This product is then subjected to methylmalonyl CoA mutase reaction which catalyzes the conversion of L-methylmalonyl CoA into succinyl CoA. This enzyme is vitamin B12 dependent.

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Chapter 23 Solutions
BIOCHEM. II-EBOOK ACCESS>CUSTOM<
- Sodium borohydride (NaBH4) is a potent inhibitor of aldolase. It is known to ONLY inhibit theenzyme when it is complexed with substrate. Treatment of the enzyme alone has no effect.What is the mechanism for this inhibition? Please draw out the mechanism and show how it inhibits this.arrow_forwardShow the fate of the proton on the 4-Oxygen molecule of F-1,6-BP. Please include a drawing showing the electron flow that occurs.arrow_forward1. Which one is the major organic product obtained from the following aldol condensation? O NaOH, H₂O heat A B C D Earrow_forward
- An organic chemist ordered the wrong item. She wanted to obtain 1-hydroxy-2-butanone, butinstead ordered 2-hydroxybutyraldehyde. As a good biochemist, show how the organic chemistcould use biological catalysis to make her desired compound. Please show the mechanism by drawing.arrow_forwardShow the fate of the hydrogen on carbon-2 of glucose. Please draw out the structure using curve arrows to show electron flow.arrow_forward3. Which one of the compounds below is the major product formed by the reaction sequence shown here? CH3 + CH3NO2 NaOH H2, Ni ? nitromethane acetophenone OH OH HO HN- u x x x x Ph A HO -NH2 HO H Ph Ph Ph N- H B Ph NH2 D Earrow_forward
- 4. Only ONE of the five compounds below can be prepared by an aldol condensation in which a single carbonyl compound is treated with base. Which one is it? To solve this problem, reverse the aldol condensation that formed each of these molecules to find out what two molecules came together to make the products. The one in which the two molecules are identical is the answer. Ph Ph ཚིག གནས ག ནཱ ཀ ན ཀནཱ A Ph H B Ph Ph H D Ph. Ph Ph E Harrow_forward5. Which one is the major organic product obtained from the following reaction sequence? First, equimolar amounts of cyclopentanone and LDA are mixed at -78°C. Then propionaldehyde (propanal) is added. Addition of aqueous acid completes the process. LDA, -78°C. 1. 2. H₂O* H A B H 0 D H H Earrow_forward2. Which one is the major organic product obtained from the following reaction? NaOH, H₂O heat A B C D Earrow_forward
- CH3CH2CHO + propanal PhCH2CHO 2-phenylacetaldehyde mixture of four products NaOH 10. In the crossed aldol reaction of propanal and 2-phenylacetaldehyde shown above, a mixture of four products will be formed. Which ONE of the compounds below will NOT be formed in this crossed aldol reaction? OH Ph A H OH OH Ph H B OH OH H H H Ph Ph C Ph D Earrow_forwardAn organic chemist ordered the wrong item. She wanted to obtain 1-hydroxy-2-butanone, butinstead ordered 2-hydroxybutyraldehyde. As a good biochemist, show how the organic chemistcould use biological catalysis to make her desired compound.arrow_forwardPredict the products of aldolase catalyzing the reaction with acetone and (S)-3-hydroxybutyraldehyde.arrow_forward
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