Explanation Given info: The current flowing through each wire is 2.2 A , the distance of point A from wire 1 is 7.5 cm , the distance of point A from wire 2 is 22.5 cm , the distance of point B from wire 1 is 7.5 cm , the distance of point B from wire 2 is 7.5 cm , the distance of point C from wire 1 is 22.5 cm and the distance of point C from wire 2 is 7.5 cm . Explanation: For point 1, Formula to calculate magnetic field at point A due to wire 1, B 1 A = μ o I 2 π r 1 A Here, μ o is the permittivity of the free space. I is the current flowing through the wires. r 1 A is the distance of point A from wire 1. Formula to calculate magnetic field at point A due to wire 2, B 2A = μ o I 2 π r 2A Here, r 2A is the distance of point A from wire 2. Write the expression for net magnetic field at point A, B A = B 1A + B 2A (1) Substitute μ o I 2 π r 2A for B 2 A and μ o I 2 π r 1A for B 1 A in equation (1). B A = μ o I 2 π r 1A + μ o I 2 π r 2A = μ o I 2 π ( 1 r 1A + 1 r 2A ) Substitute 4 π × 10 − 7 T ⋅ m / A for μ o , 2.2 A for I , 7.5 cm for r 1 A and 22.5 cm for r 2 A , B A = ( 4 π × 10 − 7 T ⋅ m / A ) ( 2.2 A ) 2 π ( 1 7.5 cm + 1 22.5 cm ) = ( 4 π × 10 − 7 T ⋅ m / A ) ( 2.2 A ) 2 π ( 1 7.5 cm 10 − 2 m 1 cm + 1 22.5 cm ( 10 − 2 m 1 cm ) ) = 7.8 × 10 − 6 T = 7.8 × 10 − 6 T 10 6 μT 1 T Further solve above expression to calculate the value of B A , B A = 7.8 μT The direction of the current is toward right and point A is placed to the left of wire 1 and wire 2 so direction of magnetic field will be out of the page

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

See similar textbooks

Concept explainers

Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

Chapter 22, Problem 77GP

To determine

The direction and magnitude of net magnetic force at point A, B and C.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 22, Problem 76GP

Chapter 22, Problem 78GP

Students have asked these similar questions

Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.) a C 3.00 με Hh. 6.00 με 20.0 με HE (a) Find the equivalent capacitance between points a and b. 5.92 HF (b) Calculate the charge on each capacitor, taking AV ab = 16.0 V. 20.0 uF capacitor 94.7 6.00 uF capacitor 67.6 32.14 3.00 µF capacitor capacitor C ☑ με με The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC 32.14 ☑ You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC

In the pivot assignment, we observed waves moving on a string stretched by hanging weights. We noticed that certain frequencies produced standing waves. One such situation is shown below: 0 ст Direct Measurement ©2015 Peter Bohacek I. 20 0 cm 10 20 30 40 50 60 70 80 90 100 Which Harmonic is this? Do NOT include units! What is the wavelength of this wave in cm with only no decimal places? If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with NO decimal places)?

Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.) A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b. (a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V. 20.0 µF capacitor µC 6.00 µF capacitor µC 3.00 µF capacitor µC capacitor C µC

Chapter 22 Solutions

Physics (5th Edition)

Ch. 22.1 - Is pole 1 in the bar magnet shown in Figure 22-7 a...Ch. 22.2 - Prob. 2EYU Ch. 22.3 - A particle orbits in a magnetic field with a...Ch. 22.4 - The following systems consist of a...Ch. 22.5 - Two current-carrying loops are identical, except...Ch. 22.6 - Prob. 6EYU Ch. 22.7 - Rank the following solenoids in order of...Ch. 22 - Two charged particles move at right angles to a...Ch. 22 - An electron moves with constant velocity through a...Ch. 22 - An electron moves with constant velocity through a...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The direction and magnitude of net magnetic force at point A, B and C.

Solution Summary: The author explains how to determine the direction and magnitude of net magnetic force at points A, B, and C.

Concept explainers

The direction and magnitude of net magnetic force at point A, B and C.

Want to see the full answer?

Chapter 22 Solutions