Explanation Given info: The magnitude of the magnetic field is 0.42 T , the current flowing in the loop is 8.8 A and the side of the square loop is 0.38 m . Explanation: For the top and the bottom side of the loop magnetic field is parallel to the direction of current that is θ = 90 ° and for the left and the right side of the loop magnetic field is perpendicular to the direction of the current that is θ = 90 ° . Formula to calculate the magnetic force on the side of loop, F = B i l sin θ Here, B is the magnitude of the magnetic field. i is the current flowing through loop. l is the side of the loop or the length of the conductor. θ is the angle between the direction of current and magnetic field. For top side of the loop: Formula to calculate the magnetic force on top side of loop, F T = B i l sin θ (1) Substitute 0.42 T for B , 8.8 A for i , 0.38 m for l and 0 ° for θ in equation (1). F T = ( 0.42 T ) ( 8.8 A ) ( 0.38 m ) sin0 ° = 0 N Thus, the magnetic force on the top side of the loop is 0 N . For bottom side of the loop: Formula to calculate the magnetic force on the bottom side of loop, F B = B i l sin θ (1) Substitute 0.42 T for B , 8.8 A for i , 0.38 m for l and 0 ° for θ in equation (1). F B = ( 0.42 T ) ( 8

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ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

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Chapter 22, Problem 69GP

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The magnitude of the magnetic force exerted on the each side of the loop.

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Chapter 22, Problem 68GP

Chapter 22, Problem 70GP

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The magnitude of the magnetic force exerted on the each side of the loop.

Solution Summary: The author explains the magnetic force exerted on the top and bottom sides of the loop.

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The magnitude of the magnetic force exerted on the each side of the loop.

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