(a) Explanation Given info: the distance between two wire is 9.25 cm , current carrying by wire 1 is 2.75 A and the current carrying by wire 2 is 4.33 A . Explanation: Formula to calculate force in 2.75 A wire, F 1 = μ o I 1 I 2 L 2 π d Here, μ o is the permittivity of the free space. I 1 is the current flowing wire carries a current 2.75 A . I 2 is the current flowing wire carries a current 4.33 A . L is the length of the power lines. d is the distance between power lines. Rearrange the above expression to calculate force per meter, F 1 L = μ o I 1 I 2 2 π d (1) Substitute 4 π × 10 − 7 T ⋅ m / A for μ o , 2.75 A for I 1 , 4.33 A for I 2 and 9 (b) To determine Whether force per meter on 4.33 A wire is greater or less than force per meter exerted on the 2.75 A wire.

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

Chapter 22, Problem 50PCE

(a)

To determine

The force per meter exerted on wire carries a current of 2.75 A .

(b)

To determine

Whether force per meter on 4.33 A wire is greater or less than force per meter exerted on the 2.75 A wire.

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Chapter 22, Problem 49PCE

Chapter 22, Problem 51PCE

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The force per meter exerted on wire carries a current of 2.75 A .

Solution Summary: The author explains how the force per meter exerted on the wire carries a current of 2.75A.

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The force per meter exerted on wire carries a current of 2.75 A .

Whether force per meter on 4.33​ A wire is greater or less than force per meter exerted on the 2.75 A wire.

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Chapter 22 Solutions

Whether force per meter on 4.33 A wire is greater or less than force per meter exerted on the 2.75 A wire.