ORGANIC CHEM PRINT STUDY GDE & SSM
ORGANIC CHEM PRINT STUDY GDE & SSM
4th Edition
ISBN: 9781119810650
Author: Klein
Publisher: WILEY
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Chapter 22, Problem 70PP
Interpretation Introduction

Interpretation: Conversion of an amine compound into quaternary ammonium salt has to be done via Hofmann elimination.

Concept Introduction:

The reagents such as methyl iodide and silver oxide are given and used as the reaction conditions in the given reactions.  This reaction is called Hofmann elimination.  The amines undergo exhaustive alkylation in the presence of excess methyl iodide producing quaternary ammonium salt which is an excellent leaving group.  After treatment with strong base, aqueous silver oxide and heat, quaternary ammonium salt gives alkenes.  Alkene formation involves in E2 elimination.  Through E2 elimination, the major product is less substituted alkene with trace amount of more substituted alkene.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 22, Problem 70PP

To find: Conversion of an amine compound into quaternary ammonium salt and draw the structure of quaternary ammonium salt

Count the number of nitrogen atoms and find nitrogen which forms quaternary ammonium salt

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Chapter 22 Solutions

ORGANIC CHEM PRINT STUDY GDE & SSM

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