Explanation Given: Four current carrying long wires are place at vertices of a square of side 20 c m = 2 × 10 − 1 m = 0.2 m as shown in the figure. Magnitude and direction of current in each wire is mentioned in the figure. Dark circle represents current out of page while circle enclose cross represents current into the page. Formula used: Magnetic field due to a long current carrying wire at perpendicular distance d from the wire is B = μ o I 2 π d where I is the current in the wire and μ o is permeability in free space. Calculation: Label the wires as P, Q, R and S. The point equidistance from the wires placed at vertices of a square is the centre of the square, label it as O. From each wire the point O is 10 2 c m = 2 × 10 − 1 m away. The magnetic of magnetic field at point O due to the wires P, Q, R and S are given as B P = μ o I 2 π d = 2 × 10 − 7 × 10 2 × 10 − 1 = 2 × 10 − 5 T = 10 2 μ T B Q = μ o I 2 π d = 2 × 10 − 7 × 10 2 × 10 − 1 = 2 × 10 − 5 T = 10 2 μ T B R = μ o I 2 π d = 2 × 10 − 7 × 5 2 × 10 − 1

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Author: OpenStax

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Chapter 22, Problem 70PE

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The magnitude and direction of the magnetic field at the point equidistance from the long current carrying wires placed at vertices of square.

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Chapter 22, Problem 69PE

Chapter 22, Problem 71PE

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The magnitude and direction of the magnetic field at the point equidistance from the long current carrying wires placed at vertices of square.

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