In Exercises 53–56, graph the three equations together and determine the number of solutions (exactly one, none, or infinitely many). If there is exactly one solution, estimate the solution.
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Finite Mathematics & Its Applications (12th Edition)
- For Exercises 5–10, a. Simplify the expression. b. Substitute 0 for h in the simplified expression. 2(x + h)? + 3(x + h) · 5. (2x + 3x) 3(x + h - 4(x + h) – (3x - 4x) 6. h 1 1 1 1 (x + h) – 2 7. x - 2 2(x + h) + 5 8. 2x + 5 h (x + h) – x 9. (x + h) 10. - X h harrow_forwardFor Exercises 31–56, perform the indicated operations. Write the answers in standard form, a + bi. (See Examples 3-6) 31. (2 – 7i) + (8 – 3i) 32. (6 – 10i) + (8 + 4i) 33. (15 + 21i) – (18 – 40i) 34. (250 + 100i) – (80 + 25i) 35. (2.3 + 4i) – (8.1 – 2.7i) + (4.6 – 6.7i) 36. (0.05 – 0.03i) + (-0.12 + 0.08i) – (0.07 + 0.05i) 37. 2i(5 + i) 38. 4i(6 + 5i) 39. (3 – 6i)(10 + i) 40. (2 – 5i)(8 + 2i) 43. (3 – V-5)(4 + V-5) 46. (3 – 21)? + (3 + 2i)? 41. (3 - 42. (10 — З1)? 44. (2 + V=7)(10 + V-7) 45. (2 – i)? + (2 + i)? 47. (10 – 4i)(10 + 4i) 48. (3 9i)(3 + 9i) 49. (V2 + V3i)(V2 - V3i) 50. (V3 + V7i)(V5 – Vīi) 6 + 2i 51. 3 - i 5 + i 52. 4 - i 8 - 5i 53. 13 + 2i 10 – 3i 54. 11 + 4i 55. 13i 56. 7iarrow_forwardIn Exercises 43–54, solve each absolute value equation or indicate the equation has no solution. 43. |x – 2| = 7 45. |2x – 1| = 5 47. 2|3x – 2| = 14 44. |x + 1| = 5 46. |2r – 3| = 11 48. 3|2x – 1| = 21 %3D %3D 5 24 - + 6 = 18 50. 4 1 x + 7 = 10 51. |x + 1| + 5 = 3 53. |2x – 1| + 3 = 3 52. |x + 1| + 6 = 2 54. |3x – 2| + 4 = 4arrow_forward
- For Exercises 115–120, factor the expressions over the set of complex numbers. For assistance, consider these examples. • In Section R.3 we saw that some expressions factor over the set of integers. For example: x - 4 = (x + 2)(x – 2). • Some expressions factor over the set of irrational numbers. For example: - 5 = (x + V5)(x – V5). To factor an expression such as x + 4, we need to factor over the set of complex numbers. For example, verify that x + 4 = (x + 2i)(x – 2i). 115. а. х - 9 116. а. х? - 100 117. а. х - 64 b. x + 9 b. + 100 b. x + 64 118. а. х — 25 119. а. х— 3 120. а. х — 11 b. x + 25 b. x + 3 b. x + 11arrow_forwardFor Exercises 8–10, a. Simplify the expression. Do not rationalize the denominator. b. Find the values of x for which the expression equals zero. c. Find the values of x for which the denominator is zero. 4x(4x – 5) – 2x² (4) 8. -6x(6x + 1) – (–3x²)(6) (6x + 1)2 9. (4x – 5)? - 10. V4 – x² - -() 2)arrow_forwardExercises 43–52: Complete the following. (a) Solve the equation symbolically. (b) Classify the equation as a contradiction, an identity, or a conditional equation. 43. 5x - 1 = 5x + 4 44. 7- 9: = 2(3 – 42) – z 45. 3(x - 1) = 5 46. 22 = -2(2x + 1.4) 47. 0.5(x – 2) + 5 = 0.5x + 4 48. 눈x-2(x-1)3-x + 2 2x + 1 2x 49. 50. x – 1.5 2- 3r - 1.5 51. -6 52. 0.5 (3x - 1) + 0.5x = 2x – 0.5arrow_forward
- In Exercises 126–129, determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. 126. Once a GCF is factored from 6y – 19y + 10y“, the remaining trinomial factor is prime. 127. One factor of 8y² – 51y + 18 is 8y – 3. 128. We can immediately tell that 6x? – 11xy – 10y? is prime because 11 is a prime number and the polynomial contains two variables. 129. A factor of 12x2 – 19xy + 5y² is 4x – y.arrow_forwardbrett expects that each guest 0.2 of a sandwich. sketch a model to show how many sandwiches brett expects the guests to eat in all.arrow_forwardUse the Gauss-Jordan technique to solve 3x1 - 0.1x2 - 0.2xg = 7.85 0.1x, + 7x2 - 0.3x3 = -19.3 0.3x1 – 0.2x2 + 10x3 = 71.4arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:CengageAlgebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal Littell