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Concept explainers
(a)
To find: the proportion of observations from the standard
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 49E
The proportion of observations is 0.8587
Explanation of Solution
Given:
z is between −1.33 and 1.65
Calculation:
The below standard normal possibilities table is a table of areas under the standard normal curve. The table entry for each value z is the area under the curve to the left of z.
From the Standard Normal probabilities table, the area to the left of = = 1.65is 0.9505 and the area to the left of z = -1.33 is 0.0918.
The area between z = -1.33 and z =1.65is the area to the left of 1.65 minus the area to the left of -1.33.
Therefore, the area between z =-1.33 & z =1.65 is 0.9505 - 0.0918 =0.8587. The result is shown in the below graph.
Conclusion:
The proportion of observations is 0.8587
(b)
To find: the proportion of observations from the standard normal distribution
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 49E
The proportion of observations is0.2718.
Explanation of Solution
Given:
z is between 0.50 and 1.79
Calculation:
From the Standard Normal probabilities table, the area to the left of
The area between z = 0.50 and z =1.79is the area to the left of 1.79 minus the area to the left of 0.50.
Therefore, the area between z = 0.50 & z =1.79 is 0.9633 - 0.6915 =0.2718. The result is shown in the below graph
Conclusion:
Therefore, proportion of observations is 0.2718.
Chapter 2 Solutions
The Practice of Statistics for AP - 4th Edition
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