How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h. Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Question

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Answer 1

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 2

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 3

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 4

Question

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

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Answer 5

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

Answer 6

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

Answer 7

Chapter 22, Problem 22.83UTC

Interpretation Introduction

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Answer 8

Expert Solution & Answer

Answer to Problem 22.83UTC

Solution: 120 moles of ATP is consumed when a person hikes for 2.5 hours.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given: On a hike, one expend 350 kcal/h.

Let us first find out the conversion factor for the conversion of 1 mole of ATP into kcal.

$1 m o l e o f A T P = 7.3 k c a l$

Thus, the conversion factor is given as:

$C o n v e r s i o n f a c t o r = \frac{7.3 k c a l}{m o l e}$

Also, it is given that in 1 hours, 350 kcals are expended. Thus, the conversion factor to convert hours to kcals is given as:

$1 h o u r = 350 k c a l$

Hence, the conversion factor is:

$C o n v e r s i o n f a c t o r = \frac{350 k c a l}{1 h}$

Now, we can find out the energy expended in 2.5 hours using conversion factor:

$E n e r g y E x p e n d e d = 2.5 h \times \frac{350 k c a l}{1 h} \times \frac{1 m o l e o f A T P}{7.3 k c a l}$

$E n e r g y E x p e n d e d = 120 m o l e s o f A T P$

Answer 12

Conclusion

When a person hikes for 2.5 hours, 120 moles of ATP is consumed.

Answer 13

Ch. 22.1 - Prob. 22.1QAP Ch. 22.1 - Prob. 22.2QAP Ch. 22.1 - Prob. 22.3QAP Ch. 22.1 - Prob. 22.4QAP Ch. 22.1 - Prob. 22.5QAP Ch. 22.1 - Prob. 22.6QAP Ch. 22.1 - Prob. 22.7QAP Ch. 22.1 - Prob. 22.8QAP Ch. 22.1 - Prob. 22.9QAP Ch. 22.1 - Prob. 22.10QAP

How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h. Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h. Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.

Answer to Problem 22.83UTC

Explanation of Solution

Want to see more full solutions like this?

Chapter 22 Solutions

Interpretation: How many moles of ATP is consumed when a person hikes for 2.5 h, given that on a hike, one expend 350 kcal/h.

Concept Introduction: The energy obtained from catabolic activities is stored in the body in the form ATP molecules.