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Identify the structures of D and E, isomers of molecular formula
a. IR absorption for D at
b. IR absorption for E at
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ORGANIC CHEMISTRY
- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forward22. A compound with the molecular formula C8H8O produces an IR spectrum with signals at 3063, 1686, and 1646 cm-1. The 1H NMR spectrum of this compound exhibits a singlet at 2.6ppm(l=3H), and a multiplet at 7.5(l= 5H). Draw the structure and give the common name of this compound . Show the correlations between the structure and spectra.arrow_forwardDraw the structure of molecular formula C8H10O that produced the 1H NMR spectra shown below. The IR spectrum does not show a broad absorbance at 3300 cm–1 or a strong absorbance at 1710 cm–1.arrow_forward
- Determine the structure of an alcohol with molecular formula C5H12O that exhibits the following signals in its 13C NMR spectra: a. Broadband decoupled: 73.8 δ, 29.1δ, and 9.5 δ b. DEPT-90: 73.8 δ c. DEPT-135: positive signals at 73.8 δ, and 9.5 δ, and negative signal at 29.1δ,arrow_forwardIdentify the structures of D and E, isomers of molecular formulaC6H12O2, from their IR and 1H NMR data. Signals at 1.35 and 1.60 ppm inthe 1H NMR spectrum of D and 1.90 ppm in the 1H NMR spectrum of Eare multiplets.arrow_forwardAn unknown compound has the formula C3H6O2. Elucidate its structure by scrutinizing its 1H NMR spectra, shown. Specifically, label each different type of H atom in the final structure with its NMR chemical shift in ppm.arrow_forward
- Thymol (molecular formula C10H14O) is the major component of the oil of thyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and 1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose a possible structure for thymol.arrow_forwardCompound P has molecular formula C5H9ClO2. Deduce the structure of P from its 1H and 13C NMR spectra.arrow_forward1. Identify the compound (C4H₂O₂) that gives the following ¹H NMR spectrum. 3H 2H PPM 3Harrow_forward
- Determine the structure of an alcohol with molecular formula C5H12O that exhibits the following signals in its 13C NMR spectra: a. Broadband decoupled: 73.8 δ, 29.1δ, and 9.5 δ b. DEPT-90: 73.8 δ c. DEPT-135: positive signals at 73.8 δ, and 9.5 δ, and negative signal at 29.1δ,arrow_forwardCompound P has molecular formula C5H9ClO2. Deduce the structure of P from its 1H and 13C NMR spectra.arrow_forwardIdentify the structures of isomers H and I (molecular formula C8H11N).a.Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm−1b.Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm−1arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning