In the given nuclear decay process, 100 Tc decays to form stable isotope 100 Mo in two possible pathways; the balanced equations has to be written. Concept Introduction : Nuclear reaction: In the nuclear reaction, fusion of two lighter nuclei to produce stable nuclei or the heavier nuclei splits into stable daughter nuclei generates the excess amount of energy. Nuclear reaction equation: The balanced nuclear reaction should conserve both mass number and atomic number. The sum of the mass numbers of the reactants should be equal to the sum of mass numbers of the products in the reaction. The sum of atomic numbers (or the atomic charge) of the reactants should be equal to the sum of atomic numbers (or the atomic charge) of the products in the reaction.

Question

Want to see the full answer?

Answer 1

Question

Chapter 22, Problem 22.46CHP

a)

Interpretation Introduction

Interpretation:

In the given nuclear decay process, 100Tc decays to form stable isotope 100Mo in two possible pathways; the balanced equations has to be written.

Concept Introduction:

Nuclear reaction: In the nuclear reaction, fusion of two lighter nuclei to produce stable nuclei or the heavier nuclei splits into stable daughter nuclei generates the excess amount of energy.

Nuclear reaction equation: The balanced nuclear reaction should conserve both mass number and atomic number.

The sum of the mass numbers of the reactants should be equal to the sum of mass numbers of the products in the reaction.

The sum of atomic numbers (or the atomic charge) of the reactants should be equal to the sum of atomic numbers (or the atomic charge) of the products in the reaction.

b)

Interpretation Introduction

Interpretation:

The energy released in kJ/mol in the given above nuclear decay process; and only one of the pathways is observed the reason has to be calculated.

Concept Introduction:

Nuclear fusion: A nuclear reaction in which a lighter nucleus fuse together spontaneously into new stable nuclei with the release of large amount of energy.

Energy released in nuclear fusion: The mass change of the reaction is calculated; and using Einstein mass-energy relation, ΔE = Δmc2

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

It is not unexpected that the methoxyl substituent on a cyclohexane ring prefers to adopt the equatorial conformation. OMe H A G₂ = +0.6 kcal/mol OMe What is unexpected is that the closely related 2-methoxytetrahydropyran prefers the axial conformation: H H OMe OMe A Gp=-0.6 kcal/mol Methoxy: CH3O group Please be specific and clearly write the reason why this is observed. This effect that provides stabilization of the axial OCH 3 group in this molecule is called the anomeric effect. [Recall in the way of example, the staggered conformer of ethane is more stable than eclipsed owing to bonding MO interacting with anti-bonding MO...]

206 Pb 82 Express your answers as integers. Enter your answers separated by a comma. ▸ View Available Hint(s) VAΣ ΜΕ ΑΣΦ Np, N₁ = 82,126 Submit Previous Answers ? protons, neutrons

Please draw the inverted chair forms of the products for the two equilibrium reactions shown below. Circle the equilibrium reaction that would have a AG = 0, i.e., the relative energy of the reactant (to the left of the equilibrium arrows) equals the relative energy of the product? [No requirement to show or do calculations.] CH3 CH3 HH CH3 1 -CH3