General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Chapter 22, Problem 22.44CHP
Interpretation Introduction
Interpretation:
The Gamma-radiation energy released in
Concept Introduction:
Nuclear reaction: A nuclear reaction in which a lighter nucleus fuse together spontaneously into new stable nuclei or heavier nuclei split into daughter nuclei with the release of large amount of energy.
Energy released in nuclear reaction: The mass change of the reaction is calculated; and using Einstein mass-energy relation,
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Given the reaction R+ Q → P, indicate
(A). the rate law with respect to P:
(B). the rate law with respect to R:
(C). the rate law with respect to Q:
d[P]
dt
d[R]
dt
d[Q]
dt
The reaction for obtaining NO2 from NO and O2 has the rate equation: v = k[NO]2[O2]. Indicate which of the following options is correct.(A). This rate equation is inconsistent with the reaction consisting of a single trimolecular step.(B). Since the overall order is 3, the reaction must necessarily have some trimolecular step in its mechanism.(C). A two-step mechanism: 1) NO + NO ⇄ N2O2 (fast); 2) N2O2 + O2 → NO2 + NO2 (slow).(D). The mechanism must necessarily consist of three unimolecular elementary steps with very similar rate constants.
a. What is the eluent used in the column chromatography here (a “silica plug filtration” is essentially a very short column)?
b. The spectroscopy of compound 5b is described in the second half of this excerpt, including 1H-NMR and 13C-NMR (which you will learn about in CHEM 2412L), MS (which you will learn about later in CHEM 2411L) and IR. One of the IR signals is at 3530 cm-1. What functional group does this indicate might be present in compound 5b?
Chapter 22 Solutions
General Chemistry: Atoms First
Ch. 22.1 - Prob. 22.1PCh. 22.2 - Prob. 22.2PCh. 22.2 - Prob. 22.3PCh. 22.3 - Prob. 22.4PCh. 22.3 - Prob. 22.5PCh. 22.4 - Prob. 22.6PCh. 22.4 - Prob. 22.7PCh. 22.6 - Prob. 22.8PCh. 22.6 - Prob. 22.9PCh. 22 - Prob. 22.10SP
Ch. 22 - Prob. 22.11SPCh. 22 - Prob. 22.12SPCh. 22 - Prob. 22.13SPCh. 22 - Prob. 22.14SPCh. 22 - Prob. 22.15SPCh. 22 - Prob. 22.16SPCh. 22 - Prob. 22.17SPCh. 22 - Prob. 22.18SPCh. 22 - Prob. 22.19SPCh. 22 - Prob. 22.20SPCh. 22 - Prob. 22.21SPCh. 22 - Prob. 22.22SPCh. 22 - Prob. 22.23SPCh. 22 - Prob. 22.24SPCh. 22 - Prob. 22.25SPCh. 22 - Prob. 22.26SPCh. 22 - Prob. 22.27SPCh. 22 - Prob. 22.28SPCh. 22 - Prob. 22.29SPCh. 22 - Prob. 22.30SPCh. 22 - Prob. 22.31SPCh. 22 - Prob. 22.32SPCh. 22 - Prob. 22.33SPCh. 22 - Prob. 22.36CHPCh. 22 - Prob. 22.37CHPCh. 22 - Prob. 22.38CHPCh. 22 - Prob. 22.39CHPCh. 22 - Prob. 22.40CHPCh. 22 - Prob. 22.41CHPCh. 22 - Prob. 22.42CHPCh. 22 - Prob. 22.43CHPCh. 22 - Prob. 22.44CHPCh. 22 - Prob. 22.45CHPCh. 22 - Prob. 22.46CHPCh. 22 - Prob. 22.47CHPCh. 22 - Prob. 22.48MPCh. 22 - Prob. 22.49MPCh. 22 - Prob. 22.50MPCh. 22 - Prob. 22.51MP
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- Given the equilibrium A2 + B2 ⇌ 2 AB where k1 is the rate coefficient of the forward reaction and k-1 is the rate coefficient of the reverse reaction, with the forward reaction being first-order in A2 and B2, and the reverse reaction being second-order in AB. Equilibrium will be reached later if the relative values of the constants are:(A) k1 high and k-1 high(B) k1 high and k-1 low(C) k1 low and k-1 high(D) k1 low and k-1 lowarrow_forwardA 2-step reaction has the following mechanism: | 1. (fast) R2 R+R 2. (slow) R+Q K₂ P k_1 What series does it have? (A). v= - = (k + k1 − k-1)[R2][Q] (B). v=-k₁[R₂] + k₁[R]² - k₂[R][Q] (C). v=k₂[R]²[Q]² (D). v = k[R₂]1/2[Q]arrow_forwardSteps and explanations. Also provide, if possible, ways to adress this kind of problems in general.arrow_forward
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