
Concept explainers
a.
Construct a frequency distribution for the data.
a.

Answer to Problem 21E
The frequency distribution is obtained as shown below:
Revenue | Frequency |
0-49 | 6 |
50-99 | 29 |
100-149 | 11 |
150-199 | 0 |
200-249 | 1 |
250-299 | 1 |
300-349 | 0 |
350-399 | 0 |
400-449 | 2 |
Total | 50 |
Explanation of Solution
Calculation:
The data represent the list of 50 Country A’s largest corporations with annual revenue expressed in billions of dollars and the frequency distribution is constructed using the classes 0-49, 50-99,100-149, and so on.
Frequency:
The frequencies are calculated using the tally mark and the
- Based on the given information, the class intervals are 0-49, 50-99, 100-149, …,400-449.
- Make a tally mark for each value in the corresponding revenue class and continue for all the values in the data.
- The number of tally marks in each class represents the frequency, f, of that class.
Similarly, the frequency of the remaining classes for the revenue is given below:
Revenue | Tally | Frequency |
0-49 | 6 | |
50-99 | 29 | |
100-149 | 11 | |
150-199 | 0 | |
200-249 | 1 | |
250-299 | 1 | |
300-349 | 0 | |
350-399 | 0 | |
400-449 | 2 | |
Total | 50 |
b.
Construct a relative frequency distribution for the data.
b.

Answer to Problem 21E
The relative frequency distribution is tabulated below:
Revenue | Frequency | Relative frequency |
0-49 | 6 | 0.12 |
50-99 | 29 | 0.58 |
100-149 | 11 | 0.22 |
150-199 | 0 | 0.00 |
200-249 | 1 | 0.02 |
250-299 | 1 | 0.02 |
300-349 | 0 | 0.00 |
350-399 | 0 | 0.00 |
400-449 | 2 | 0.04 |
Total | 50 | 1.00 |
Explanation of Solution
Calculation:
Relative frequency:
The general formula for the relative frequency is as follows:
For the revenue class (0-49), substitute frequency as “6” and total frequency as “50”.
Similarly, the relative frequencies for the remaining revenue classes are obtained below:
Revenue | Frequency | Relative frequency |
0-49 | 6 | 0.12 |
50-99 | 29 | 0.58 |
100-149 | 11 | 0.22 |
150-199 | 0 | 0.00 |
200-249 | 1 | 0.02 |
250-299 | 1 | 0.02 |
300-349 | 0 | 0.00 |
350-399 | 0 | 0.00 |
400-449 | 2 | 0.04 |
Total | 50 | 1.00 |
c.
Construct a cumulative frequency distribution for the data.
c.

Answer to Problem 21E
The cumulative frequency distribution is as follows:
Revenue | Frequency | Cumulative frequency |
0-49 | 6 | 6 |
50-99 | 29 | 35 |
100-149 | 11 | 46 |
150-199 | 0 | 46 |
200-249 | 1 | 47 |
250-299 | 1 | 48 |
300-349 | 0 | 48 |
350-399 | 0 | 48 |
400-449 | 2 | 50 |
Explanation of Solution
Calculation:
Cumulative frequency:
Cumulative frequency of a particular class is the sum of all frequencies up to a class. The last class’s cumulative frequency is equal to the
Thus, the cumulative frequency for each class is tabulated below:
The relative frequencies for the five types of classes are obtained below:
Revenue | Frequency | Cumulative frequency |
0-49 | 6 | 6 |
50-99 | 29 | |
100-149 | 11 | |
150-199 | 0 | |
200-249 | 1 | |
250-299 | 1 | |
300-349 | 0 | |
350-399 | 0 | |
400-449 | 2 |
d.
Construct a cumulative relative frequency distribution for the data.
d.

Answer to Problem 21E
The cumulative relative frequency distribution is given below:
Revenue | Cumulative relative frequency |
0-49 | 0.12 |
50-99 | 0.70 |
100-149 | 0.92 |
150-199 | 0.92 |
200-249 | 0.94 |
250-299 | 0.96 |
300-349 | 0.96 |
350-399 | 0.96 |
400-449 | 1.00 |
Explanation of Solution
Calculation:
Cumulative relative frequency of a particular class is the sum of all relative frequencies up to a class. The last class’s cumulative relative frequency is equal to the approximate value 1.00.
The relative frequencies for the revenue classes from part (b) is given below:
Revenue | Frequency | Relative frequency |
0-49 | 6 | 0.12 |
50-99 | 29 | 0.58 |
100-149 | 11 | 0.22 |
150-199 | 0 | 0.00 |
200-249 | 1 | 0.02 |
250-299 | 1 | 0.02 |
300-349 | 0 | 0.00 |
350-399 | 0 | 0.00 |
400-449 | 2 | 0.04 |
Total | 50 | 1.00 |
Thus, the cumulative relative frequencies for the revenue classes are obtained below:
Revenue | Relative frequency | Cumulative relative frequency |
0-49 | 0.12 | 0.12 |
50-99 | 0.58 | |
100-149 | 0.22 | |
150-199 | 0.00 | |
200-249 | 0.02 | |
250-299 | 0.02 | |
300-349 | 0.00 | |
350-399 | 0.00 | |
400-449 | 0.04 |
e.
Explain about the annual revenue of the largest corporations in Country A using the distributions.
e.

Explanation of Solution
From the given data set and obtained distributions, it is observed that the frequency for the revenues in the range of 50 billion dollars to 149 billion dollars is obtained by the majority of 40 corporations over 50 largest corporations.
Further, the revenue over $200 billion is obtained by only 4 corporations and the revenue over 400 billion dollars is obtained by only 2 corporations.
Moreover, 70 percent of the corporations have revenues under 100 billion dollars. Only 30 percent of corporations have revenues over 100 billion dollars.
f.
Construct the histogram and comment on the shape of the distribution.
f.

Answer to Problem 21E
- The histogram of the data is given below:
The histogram is skewed to the right.
Explanation of Solution
Calculation:
Software procedure:
Step-by-step procedure to draw the frequency histogram chart using MINITAB software:
- Choose Graph > Histogram.
- Choose Simple, and then click OK.
- In Graph variables, enter the Revenue column of data.
- In scale on y-axis, make click on frequency.
- Click on ok.
Skewness:
The data are said to be skewed if there is a lack of symmetry and the values fall on one side, that is, either left or right of the distribution.
Right skewed:
If the tail on the distribution is elongated toward the right and it attains its peak rapidly than its horizontal axis, then it is a right-skewed distribution. It is also called positively skewed.
The distribution of revenue in the histogram has elongated tail toward the right side. There are four corporations in the range of 200 billion dollars to 449 billion dollars.
Therefore, the distribution of the histogram with revenue is skewed to the right.
g.
Find the largest corporation in Country A and find its annual revenue.
g.

Answer to Problem 21E
Exxon-Mobil is the largest corporation in Country A and its annual revenue is 443 billion dollars.
Explanation of Solution
From the data set of 50 largest corporations, it is observed that the largest corporation in Country A is Exxon-Mobil and its annual revenue is 443 billion dollars.
The second largest corporation in Country A is Walmart and its annual revenue is 406 billion dollars.
Moreover, the possibility of corporation that has annual revenues less than 150 billion dollars is approximately 92 percent, and the remaining other corporations have annual revenues less than 300 billion dollars.
Want to see more full solutions like this?
Chapter 2 Solutions
Essentials of Statistics for Business and Economics (with XLSTAT Printed Access Card)
- Question 1 The data shown in Table 1 are and R values for 24 samples of size n = 5 taken from a process producing bearings. The measurements are made on the inside diameter of the bearing, with only the last three decimals recorded (i.e., 34.5 should be 0.50345). Table 1: Bearing Diameter Data Sample Number I R Sample Number I R 1 34.5 3 13 35.4 8 2 34.2 4 14 34.0 6 3 31.6 4 15 37.1 5 4 31.5 4 16 34.9 7 5 35.0 5 17 33.5 4 6 34.1 6 18 31.7 3 7 32.6 4 19 34.0 8 8 33.8 3 20 35.1 9 34.8 7 21 33.7 2 10 33.6 8 22 32.8 1 11 31.9 3 23 33.5 3 12 38.6 9 24 34.2 2 (a) Set up and R charts on this process. Does the process seem to be in statistical control? If necessary, revise the trial control limits. [15 pts] (b) If specifications on this diameter are 0.5030±0.0010, find the percentage of nonconforming bearings pro- duced by this process. Assume that diameter is normally distributed. [10 pts] 1arrow_forward4. (5 pts) Conduct a chi-square contingency test (test of independence) to assess whether there is an association between the behavior of the elderly person (did not stop to talk, did stop to talk) and their likelihood of falling. Below, please state your null and alternative hypotheses, calculate your expected values and write them in the table, compute the test statistic, test the null by comparing your test statistic to the critical value in Table A (p. 713-714) of your textbook and/or estimating the P-value, and provide your conclusions in written form. Make sure to show your work. Did not stop walking to talk Stopped walking to talk Suffered a fall 12 11 Totals 23 Did not suffer a fall | 2 Totals 35 37 14 46 60 Tarrow_forwardQuestion 2 Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2. Table 2: Strength Data for Question 2 Sample Number x1 x2 23 x4 x5 R 1 83.0 2 88.6 78.3 78.8 3 85.7 75.8 84.3 81.2 78.7 75.7 77.0 71.0 84.2 81.0 79.1 7.3 80.2 17.6 75.2 80.4 10.4 4 80.8 74.4 82.5 74.1 75.7 77.5 8.4 5 83.4 78.4 82.6 78.2 78.9 80.3 5.2 File Preview 6 75.3 79.9 87.3 89.7 81.8 82.8 14.5 7 74.5 78.0 80.8 73.4 79.7 77.3 7.4 8 79.2 84.4 81.5 86.0 74.5 81.1 11.4 9 80.5 86.2 76.2 64.1 80.2 81.4 9.9 10 75.7 75.2 71.1 82.1 74.3 75.7 10.9 11 80.0 81.5 78.4 73.8 78.1 78.4 7.7 12 80.6 81.8 79.3 73.8 81.7 79.4 8.0 13 82.7 81.3 79.1 82.0 79.5 80.9 3.6 14 79.2 74.9 78.6 77.7 75.3 77.1 4.3 15 85.5 82.1 82.8 73.4 71.7 79.1 13.8 16 78.8 79.6 80.2 79.1 80.8 79.7 2.0 17 82.1 78.2 18 84.5 76.9 75.5 83.5 81.2 19 79.0 77.8 20 84.5 73.1 78.2 82.1 79.2 81.1 7.6 81.2 84.4 81.6 80.8…arrow_forward
- Name: Lab Time: Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26 Contingency Analysis (Ch. 9) In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop) were more likely to suffer a fall in the next six months. I have tabulated the data below. Answer the questions below. Please show your calculations on this or a separate sheet. Did not stop walking to talk Stopped walking to talk Totals Suffered a fall Did not suffer a fall Totals 12 11 23 2 35 37 14 14 46 60 Quiz 7: 1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those who did not stop walking vs. those who did stop walking. Interpret your result verbally.arrow_forwardSolve please and thank you!arrow_forward7. In a 2011 article, M. Radelet and G. Pierce reported a logistic prediction equation for the death penalty verdicts in North Carolina. Let Y denote whether a subject convicted of murder received the death penalty (1=yes), for the defendant's race h (h1, black; h = 2, white), victim's race i (i = 1, black; i = 2, white), and number of additional factors j (j = 0, 1, 2). For the model logit[P(Y = 1)] = a + ß₁₂ + By + B²², they reported = -5.26, D â BD = 0, BD = 0.17, BY = 0, BY = 0.91, B = 0, B = 2.02, B = 3.98. (a) Estimate the probability of receiving the death penalty for the group most likely to receive it. [4 pts] (b) If, instead, parameters used constraints 3D = BY = 35 = 0, report the esti- mates. [3 pts] h (c) If, instead, parameters used constraints Σ₁ = Σ₁ BY = Σ; B = 0, report the estimates. [3 pts] Hint the probabilities, odds and odds ratios do not change with constraints.arrow_forward
- Solve please and thank you!arrow_forwardSolve please and thank you!arrow_forwardQuestion 1:We want to evaluate the impact on the monetary economy for a company of two types of strategy (competitive strategy, cooperative strategy) adopted by buyers.Competitive strategy: strategy characterized by firm behavior aimed at obtaining concessions from the buyer.Cooperative strategy: a strategy based on a problem-solving negotiating attitude, with a high level of trust and cooperation.A random sample of 17 buyers took part in a negotiation experiment in which 9 buyers adopted the competitive strategy, and the other 8 the cooperative strategy. The savings obtained for each group of buyers are presented in the pdf that i sent: For this problem, we assume that the samples are random and come from two normal populations of unknown but equal variances.According to the theory, the average saving of buyers adopting a competitive strategy will be lower than that of buyers adopting a cooperative strategy.a) Specify the population identifications and the hypotheses H0 and H1…arrow_forward
- You assume that the annual incomes for certain workers are normal with a mean of $28,500 and a standard deviation of $2,400. What’s the chance that a randomly selected employee makes more than $30,000?What’s the chance that 36 randomly selected employees make more than $30,000, on average?arrow_forwardWhat’s the chance that a fair coin comes up heads more than 60 times when you toss it 100 times?arrow_forwardSuppose that you have a normal population of quiz scores with mean 40 and standard deviation 10. Select a random sample of 40. What’s the chance that the mean of the quiz scores won’t exceed 45?Select one individual from the population. What’s the chance that his/her quiz score won’t exceed 45?arrow_forward
- Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt


