Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card
Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card
6th Edition
ISBN: 9781305717367
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
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Chapter 22, Problem 1E
Interpretation Introduction

Interpretation:

The Lewis diagram of the general structure of an amino acid is to be drawn.

Concept introduction:

The Lewis diagram shows the bonding between different atoms of a molecule and the lone pairs of electrons in the molecule. It shows how the valence electrons of an atom are arranged in the molecule. In Lewis diagram, two electrons between the atoms are indicated as a line to show bonding between atoms.

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Answer to Problem 1E

The Lewis diagram of the general structure of an amino acid is shown below.

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card, Chapter 22, Problem 1E , additional homework tip  1

Explanation of Solution

The Lewis structure of a compound shows how the valence electrons of an atom are arranged in the molecule. The molecular structures are given by its valence electrons and lone pairs on central atom.

The total number of valence electrons in an amino acid is the sum of valence electrons of two carbon atoms, valence electrons of four hydrogen atoms, valence electrons of one nitrogen atom and valence electron of two oxygen atoms. There are four valence electrons on carbon atom, one valence electron on each hydrogen atom, five valence electrons on nitrogen atom and six valence electrons on each oxygen atom. Therefore, the total number of valence electron in an amino acid is 29. The Lewis diagram of an amino acid molecule is shown below in Figure 1.

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card, Chapter 22, Problem 1E , additional homework tip  2

Figure 1

Conclusion

The Lewis diagram of the general structure of an amino acid is shown in Figure 1.

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Chapter 22 Solutions

Bundle: Introductory Chemistry: An Active Learning Approach, 6th + OWLv2, 1 term (6 months) Printed Access Card

Ch. 22 - Describe in words the hydrogen bonding that occurs...Ch. 22 - Prob. 12ECh. 22 - Prob. 13ECh. 22 - Prob. 14ECh. 22 - Prob. 15ECh. 22 - Prob. 16ECh. 22 - Prob. 17ECh. 22 - Prob. 18ECh. 22 - Prob. 19ECh. 22 - Prob. 20ECh. 22 - Prob. 21ECh. 22 - Prob. 22ECh. 22 - Prob. 23ECh. 22 - Prob. 24ECh. 22 - Prob. 25ECh. 22 - Prob. 26ECh. 22 - Prob. 27ECh. 22 - Prob. 28ECh. 22 - Prob. 29ECh. 22 - Prob. 30ECh. 22 - Prob. 31ECh. 22 - Prob. 32ECh. 22 - Prob. 33ECh. 22 - Prob. 34ECh. 22 - What physical property do the three classes of...Ch. 22 - Prob. 36ECh. 22 - Prob. 37ECh. 22 - Prob. 38ECh. 22 - Prob. 39ECh. 22 - Prob. 40ECh. 22 - Prob. 41ECh. 22 - Prob. 42ECh. 22 - Prob. 43ECh. 22 - Prob. 44ECh. 22 - Prob. 45ECh. 22 - Prob. 46ECh. 22 - Draw the Lewis diagrams for adenine and thymine.Ch. 22 - Draw the Lewis diagrams for guanine and cytosine.Ch. 22 - Prob. 49ECh. 22 - Prob. 50ECh. 22 - Prob. 51ECh. 22 - Prob. 52ECh. 22 - Draw the Lewis diagram for the DNA fragment that...Ch. 22 - Prob. 54ECh. 22 - Although RNA is single-stranded, the strand...Ch. 22 - Prob. 56ECh. 22 - Prob. 57ECh. 22 - Prob. 58ECh. 22 - Prob. 59ECh. 22 - Prob. 60ECh. 22 - Prob. 61ECh. 22 - Prob. 62ECh. 22 - Prob. 63ECh. 22 - Prob. 64ECh. 22 - Prob. 65ECh. 22 - What element is found in DNA and RNA but not in...Ch. 22 - Prob. 67ECh. 22 - Prob. 68ECh. 22 - Prob. 69ECh. 22 - Prob. 70ECh. 22 - Using the single letter abbreviations A, V, and L,...Ch. 22 - Fill in the blanks in the following statements:...Ch. 22 - Prob. 22.3TCCh. 22 - Prob. 22.4TCCh. 22 - Prob. 22.5TCCh. 22 - a Describe the three components of a nucleotide. b...Ch. 22 - Prob. 1CLECh. 22 - Prob. 2CLECh. 22 - Write a brief description of the relationships...Ch. 22 - Prob. 4CLECh. 22 - Prob. 5CLECh. 22 - Prob. 6CLE
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