Applied Physics (11th Edition)
11th Edition
ISBN: 9780134159386
Author: Dale Ewen, Neill Schurter, Erik Gundersen
Publisher: PEARSON
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Chapter 22, Problem 11RQ
To determine
Explain why the sunset looks red.
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A square metal sheet 2.5 cm on a side and of negligible thickness is attached to a balance and inserted into a container of fluid.
The contact angle is found to be zero, as shown in Figure a, and the balance to which the metal sheet is attached reads 0.42 N. A
thin veneer of oil is then spread over the sheet, and the contact angle becomes 180°, as shown in Figure b. The balance now
reads 0.41 N. What is the surface tension of the fluid?
x
Your response differs from the correct answer by more than 10%. Double check your calculations. N/m
a
b
A helium-filled balloon (whose envelope has a mass of m₁ = 0.260 kg) is tied to a uniform string of length l = 2.70 m and mass
m = 0.050 6 kg. The balloon is spherical with a radius of r = 0.399 m. When released in air of temperature 20°C and density Pair
= 1.20 kg/m³, it lifts a length h of string and then remains stationary as shown in the figure below. We wish to find the length of
string lifted by the balloon.
He
(a) When the balloon remains stationary, what is the appropriate analysis model to describe it?
Oa particle in equilibrium model
a particle under constant acceleration model
a particle under constant velocity model
the ideal fluid model
(b) Write a force equation for the balloon from this model in terms of the buoyant force B, the weight F of the balloon,
the weight Fe of the helium, and the weight F of the segment of string of length h. (Use any variable or symbol stated
above along with the following as necessary: π. Follow the sign convention that upward is the positive…
Assume that if the shear stress in steel exceeds about 4.00 × 108 N/m², the steel ruptures.
(a) Determine the shearing force necessary to shear a steel bolt 1.50 cm in diameter.
(No Response) N
(b) Determine the shearing force necessary to punch a 1.50-cm-diameter hole in a steel plate 0.650 cm thick.
(No Response) N
Chapter 22 Solutions
Applied Physics (11th Edition)
Ch. 22 - Prob. 1RQCh. 22 - What property of light determines its color?Ch. 22 - Name the light waves whose wavelengths are (a)...Ch. 22 - What is the apparent color of a green dress in a...Ch. 22 - Prob. 5RQCh. 22 - Prob. 6RQCh. 22 - What is a complementary color? Name the complement...Ch. 22 - How are the primary pigments related to the...Ch. 22 - Prob. 9RQCh. 22 - Prob. 10RQ
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- = = You are preparing your house for a party with your classmates and friends, and want to set up an impressive light display to entertain them. From your study of fluids, you have come up with the idea based on the water flowing from the tank in the figure. You set up the tank as shown in the figure, filled to a depth h 1.15 m, and sitting on a stand of height { 0.300 m. You punch a hole in the tank at a height of Y1 = 0.102 m above the stand. (Ignore the thickness of the tank in your calculation.) You want to punch a second hole higher on the tank so that the streams of water from the two holes arrive at the same position on the table, in a catch basin at a distance d from the right edge of the stand. A pump will continuously carry water from the catch basin back up to the top of the tank to keep the water level fixed. Then, you will use laser pointers on the left side of the tank to light the two streams of water, which will capture the light (see the section on total internal…arrow_forwardA square metal sheet 2.5 cm on a side and of negligible thickness is attached to a balance and inserted into a container of fluid. The contact angle is found to be zero, as shown in Figure a, and the balance to which the metal sheet is attached reads 0.42 N. A thin veneer of oil is then spread over the sheet, and the contact angle becomes 180°, as shown in Figure b. The balance now reads 0.41 N. What is the surface tension of the fluid? N/m aarrow_forwardSucrose is allowed to diffuse along a 12.0-cm length of tubing filled with water. The tube is 6.1 cm² in cross-sectional area. The diffusion coefficient is equal to 5.0 × 10-10 m²/s, and 8.0 × 10−14 x transported along the tube in 18 s. What is the difference in the concentration levels of sucrose at the two ends of the tube? .00567 kg isarrow_forward
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