Explanation Definition used: Identifying a Conic Section from the Second-degree Equation: The second degree equation is of the form A x 2 + B x y + C y 2 + D x + E y + F = 0 . 1. If A = C , B = 0 , a circle . 2. If A ≠ C ( Same sign ) , B = 0 , an ellipse . 3. If A and C have different signs , B = 0 , a hyperbola . 4. If A = 0 , C = 0 , B ≠ 0 , a hyperbola . 5. If either A = 0 or C = 0 ( both not both ) , B = 0 , a parabola . Calculation: Rewrite 15 x 2 = x ( x − 12 ) + 4 y ( y − 6 ) as, 15 x 2 = x 2 − 12 x + 4 y 2 <

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

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ISBN: 9780135902912

Author: Allyn J. Washington

Publisher: PEARSON

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Chapter 21.8, Problem 20E

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The type of curve represented by the equation 15x2=x(x−12)+4y(y−6).

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Chapter 21.8, Problem 19E

Chapter 21.8, Problem 21E

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Chapter 21 Solutions

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

Ch. 21.1 - Find the distance between (−2, 6) and (5, −3). Ch. 21.1 - Prob. 2PE Ch. 21.1 - Prob. 1E Ch. 21.1 - Prob. 2E Ch. 21.1 - Prob. 5E Ch. 21.1 - In Exercises 5–14, find the distance between the...Ch. 21.1 - Prob. 7E Ch. 21.1 - Prob. 8E Ch. 21.1 - Prob. 9E Ch. 21.1 - Prob. 10E

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The type of curve represented by the equation 15 x 2 = x ( x − 12 ) + 4 y ( y − 6 ) .

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The type of curve represented by the equation 15x2=x(x−12)+4y(y−6).

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Chapter 21 Solutions