Explanation Formula used: The standard form of the equation of the parabola with vertex ( h , k ) and axis parallel to the x -axis is ( y − k ) 2 = 4 p ( x − h ) . Calculation: Consider the vertex ( h , k ) is ( 2 , − 3 ) and p = 2 . The equation of the parabola with vertex ( h , k ) and axis parallel to the x -axis is ( y − h ) 2 = 4 p ( x − k ) . From, p = 2 the focus is 2 units from the vertex. Thus, the focus is ( 4 , − 3 )

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

11th Edition

ISBN: 9780135902912

Author: Allyn J. Washington

Publisher: PEARSON

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Chapter 21.4, Problem 37E

To determine

To sketch: The parabola with vertex $(h,k)$ is $(2,−3)$ and $p=2$ when the equation of the parabola with vertex $(h,k)$ and axis parallel to the x-axis is $(y−h)2=4p(x−k)$ .

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Chapter 21.4, Problem 36E

Chapter 21.4, Problem 38E

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Chapter 21 Solutions

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

Ch. 21.1 - Find the distance between (−2, 6) and (5, −3). Ch. 21.1 - Prob. 2PE Ch. 21.1 - Prob. 1E Ch. 21.1 - Prob. 2E Ch. 21.1 - Prob. 5E Ch. 21.1 - In Exercises 5–14, find the distance between the...Ch. 21.1 - Prob. 7E Ch. 21.1 - Prob. 8E Ch. 21.1 - Prob. 9E Ch. 21.1 - Prob. 10E

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The parabola with vertex ( h , k ) is ( 2 , − 3 ) and p = 2 when the equation of the parabola with vertex ( h , k ) and axis parallel to the x -axis is ( y − h ) 2 = 4 p ( x − k ) .

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Chapter 21 Solutions