Explanation Calculation: It is given that the ceiling is 10 ft at the walls, 14 ft high at the center and the width of a hallway is 16 ft. Therefore, the point ( 6.00 , 4.00 ) on any of the parabolic cross sections. Draw a hallway which has a ceiling as shown below in Figure 1. From Figure 1, it is observed that the semi ellipse is centered at the origin and its major axis along x -axis. Therefore, the equation of the ellipse is x 2 a 2 + y 2 b 2 = 1 . Here, it is observed that the value of a = 16 2 and b = 14 − 10 . That is, a = 8 and b = 4 . The equation of the ellipse becomes x 2 8 2 + y 2 4 2 = 1 . The ceiling is 4 ft from each wall which means x = 4 . Find the value of y for x = 4

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

11th Edition

ISBN: 9780135902912

Author: Allyn J. Washington

Publisher: PEARSON

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Vertices Of An Ellipse

In the study of the conic section of the geometry, An ellipse is a plane curve surrounding two focal points, or foci where the set of all locus of points in the plane has their sum of the distances to the two foci is constant. On the ellipse curve, it is…

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Chapter 21, Problem 9PT

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The height of the ceiling 4 ft from each wall.

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Chapter 21, Problem 8PT

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Chapter 21 Solutions

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

Ch. 21.1 - Find the distance between (−2, 6) and (5, −3). Ch. 21.1 - Prob. 2PE Ch. 21.1 - Prob. 1E Ch. 21.1 - Prob. 2E Ch. 21.1 - Prob. 5E Ch. 21.1 - In Exercises 5–14, find the distance between the...Ch. 21.1 - Prob. 7E Ch. 21.1 - Prob. 8E Ch. 21.1 - Prob. 9E Ch. 21.1 - Prob. 10E

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