Explanation Result used: The point-slope form of the equation of a straight line is y − y 1 = m ( x − x 1 ) , where ( x 1 , y 1 ) is the point on a line. Calculation: It is given that the point ( x 1 , y 1 ) = ( − 3 , 8 ) and slope m = 4 . In order to find the equation of the line, substitute ( x 1 , y 1 ) = ( − 3 , 8 ) and m = 4 in y − y 1 = m ( x − x 1 )

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

11th Edition

ISBN: 9780135902912

Author: Allyn J. Washington

Publisher: PEARSON

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Chapter 21.2, Problem 5E

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The equation of the line passes through the point (−3,8) with a slope of 4.

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Chapter 21.2, Problem 4E

Chapter 21.2, Problem 6E

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Chapter 21 Solutions

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

Ch. 21.1 - Find the distance between (−2, 6) and (5, −3). Ch. 21.1 - Prob. 2PE Ch. 21.1 - Prob. 1E Ch. 21.1 - Prob. 2E Ch. 21.1 - Prob. 5E Ch. 21.1 - In Exercises 5–14, find the distance between the...Ch. 21.1 - Prob. 7E Ch. 21.1 - Prob. 8E Ch. 21.1 - Prob. 9E Ch. 21.1 - Prob. 10E

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The equation of the line passes through the point ( − 3 , 8 ) with a slope of 4 .

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The equation of the line passes through the point (−3,8) with a slope of 4.

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Chapter 21 Solutions