ORGANIC CHEMISTRY-PRINT (LL)-W/WILEY
ORGANIC CHEMISTRY-PRINT (LL)-W/WILEY
4th Edition
ISBN: 9781119761105
Author: Klein
Publisher: WILEY
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Chapter 21.7, Problem 42PTS

(a)

Interpretation Introduction

Interpretation:

Using cyclopentanone as a starting material, synthesis of given compounds need to be proposed.

Concept introduction:

The addition of an enamine to α,β -unsaturated carbonyl acceptor (Michael acceptor) to form dicarbonyl compound is known as Stork enamine synthesis.  The difference between Michael addition and stork enamine is that for Michael addition to take place the enolate formed should be doubly stabilized.  The product is then hydrolyzed by an aqueous acid to produce 1,5-dicarbonyl compound.  Steps involved in Stork enamine synthesis are,

  • Formation of an enamine
  • Michael addition
  • Hydrolysis

(b)

Interpretation Introduction

Interpretation:

Using cyclopentanone as a starting material, synthesis of given compounds need to be proposed.

Concept introduction:

If the product is 1,3-difunctionalized means either it has to prepared via Aldol addition or Claisen condensation reaction.

Williamson ether synthesis is the synthesis of ether when alkoxide reacts with an alkyl halide.

(c)

Interpretation Introduction

Interpretation:

Using cyclopentanone as a starting material, synthesis of given compounds need to be proposed.

Concept introduction:

The addition of an enamine to α,β -unsaturated carbonyl acceptor (Michael acceptor) to form dicarbonyl compound is known as Stork enamine synthesis.  The difference between Michael addition and stork enamine is that for Michael addition to take place the enolate formed should be doubly stabilized.  The product is then hydrolyzed by an aqueous acid to produce 1,5-dicarbonyl compound.  Steps involved in Stork enamine synthesis are,

  • Formation of an enamine
  • Michael addition
  • Hydrolysis

The formed 1,5-dicarbonyl compound undergoes reduction when treated with LAH to give 1,5-dihydroxy compound.

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3) Propagation of uncertainty. Every measurement has uncertainty. In this problem, we'll evaluate the uncertainty in every step of a titration of potassium hydrogen phthalate (a common acid used in titrations, abbreviated KHP, formula CsH5KO4) with NaOH of an unknown concentration. The calculation that ultimately needs to be carried out is: concentration NaOH 1000 x mass KHP × purity KHP molar mass KHP x volume NaOH Measurements: a) You use a balance to weigh 0.3992 g of KHP. The uncertainty is ±0.15 mg (0.00015 g). b) You use a buret to slowly add NaOH to the KHP until it reaches the endpoint. It takes 18.73 mL of NaOH. The uncertainty of the burst is 0.03 mL.. c) The manufacturer states the purity of KHP is 100%±0.05%. d) Even though we don't think much about them, molar masses have uncertainty as well. The uncertainty comes from the distribution of isotopes, rather than random measurement error. The uncertainty in the elements composing KHP are: a. Carbon: b. Hydrogen: ±0.0008…
Don't used hand raiting and don't used Ai solution

Chapter 21 Solutions

ORGANIC CHEMISTRY-PRINT (LL)-W/WILEY

Ch. 21.2 - Prob. 10CCCh. 21.2 - Prob. 11CCCh. 21.2 - Prob. 12CCCh. 21.2 - Prob. 13CCCh. 21.3 - Prob. 2LTSCh. 21.3 - Prob. 14PTSCh. 21.3 - Prob. 15PTSCh. 21.3 - Prob. 3LTSCh. 21.3 - Prob. 4LTSCh. 21.3 - Prob. 19PTSCh. 21.3 - Prob. 21CCCh. 21.3 - Prob. 22CCCh. 21.3 - Prob. 23CCCh. 21.4 - Prob. 24CCCh. 21.4 - Prob. 25CCCh. 21.4 - Prob. 26CCCh. 21.4 - Prob. 27CCCh. 21.4 - Prob. 28CCCh. 21.5 - Prob. 29CCCh. 21.5 - Prob. 30CCCh. 21.5 - Prob. 5LTSCh. 21.5 - Prob. 31PTSCh. 21.5 - Prob. 6LTSCh. 21.5 - Prob. 33PTSCh. 21.5 - Prob. 34ATSCh. 21.6 - Prob. 35CCCh. 21.6 - Prob. 36CCCh. 21.6 - Prob. 37CCCh. 21.6 - Prob. 7LTSCh. 21.6 - Prob. 38PTSCh. 21.7 - Prob. 8LTSCh. 21.7 - Prob. 42PTSCh. 21.7 - Prob. 43PTSCh. 21 - Prob. 47PPCh. 21 - Prob. 48PPCh. 21 - Prob. 49PPCh. 21 - Prob. 50PPCh. 21 - Prob. 51PPCh. 21 - Prob. 52PPCh. 21 - Prob. 53PPCh. 21 - Prob. 54PPCh. 21 - Prob. 55PPCh. 21 - Prob. 56PPCh. 21 - Prob. 57PPCh. 21 - Prob. 58PPCh. 21 - Prob. 59PPCh. 21 - Prob. 60PPCh. 21 - Prob. 61PPCh. 21 - Prob. 62PPCh. 21 - Prob. 63PPCh. 21 - Prob. 64PPCh. 21 - Prob. 65PPCh. 21 - Prob. 66PPCh. 21 - Prob. 67PPCh. 21 - Prob. 68PPCh. 21 - Prob. 69PPCh. 21 - Prob. 70PPCh. 21 - Prob. 71PPCh. 21 - Prob. 72PPCh. 21 - Prob. 73PPCh. 21 - Prob. 74PPCh. 21 - Prob. 75PPCh. 21 - Prob. 76PPCh. 21 - Prob. 77PPCh. 21 - Prob. 78PPCh. 21 - Prob. 79PPCh. 21 - Prob. 80PPCh. 21 - Prob. 81PPCh. 21 - Prob. 82PPCh. 21 - Prob. 83PPCh. 21 - Prob. 84PPCh. 21 - Prob. 85PPCh. 21 - Prob. 86PPCh. 21 - Prob. 87PPCh. 21 - Prob. 88PPCh. 21 - Prob. 97IPCh. 21 - Prob. 98IPCh. 21 - Prob. 99IPCh. 21 - Prob. 100IPCh. 21 - Prob. 101IPCh. 21 - Prob. 107IPCh. 21 - Prob. 108IPCh. 21 - Prob. 109IP
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