Chapter 21.4, Problem 21.6BFP

Interpretation Introduction

Interpretation:

For given ${\text{ΔG}}^{\text{o}}$ value at $25{}^{\circ }C$ the standard cell potential for the given reaction has to be calculated under given conditions.

Concept Introduction:

Free energy change${\text{ΔG}}^0$: Change in the free energy takes place while reactant converts to product where both are in standard state.  It depends on the equilibrium constant $\text{K}$

  $\begin{array}{c}{\text{ΔG}}^{\text{0}}\text{=}-\text{RT}\left(\text{ln}\text{K}\right)\\ \text{here},\text{T=}\text{Temperature}\\ \text{R=}\text{Gas constant}\\ \text{K}\text{=}\text{Equilibrium}\text{constant}\end{array}$

The Standard Gibb’s free energy change and the standard cell potential are related as followed:

$\text{Δ}°\text{G}\text{=}\text{-nFE}{°}_{\text{cell}}$

$\begin{array}{l}n-Numberofelectronsinvolvedperequivalentofthenetredoxreactioninthecell\\ F-Faraday’sCons\tan t\left(96500C\right) \\ E^{\circ }{}_{cell}-S\tan dardcellpotential.\end{array}$