Mathematics: A Discrete Introduction
3rd Edition
ISBN: 9780840049421
Author: Edward A. Scheinerman
Publisher: Cengage Learning
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Chapter 2.13, Problem 13.7E
To determine
To find: The proof for the given expression
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Without evaluating the Legendre symbols, prove the following.
(i) 1(173)+2(2|73)+3(3|73) +...+72(72|73) = 0.
(Hint: As r runs through the numbers 1,2,.
(ii) 1²(1|71)+2²(2|71) +3²(3|71) +...+70² (70|71)
= 71{1(1|71) + 2(2|71) ++70(70|71)}.
72, so does 73 – r.)
By considering the number N = 16p²/p... p² - 2, where P1, P2, … … … ‚ Pn
are primes, prove that there are infinitely many primes of the form
8k - 1.
(c) (i) By first considering the case where n is a prime power, prove that
n
μ² (d)
=
ø(n)
(d)'
n≥ 1.
d\n
(ii) Verify the result of part (c)(i) when n =
20.
Chapter 2 Solutions
Mathematics: A Discrete Introduction
Ch. 2.8 - Write out all the possible two-letter words one...Ch. 2.8 - Airports have names, but they also have...Ch. 2.8 - Prob. 8.3ECh. 2.8 - Prob. 8.4ECh. 2.8 - Prob. 8.5ECh. 2.8 - Prob. 8.6ECh. 2.8 - Prob. 8.7ECh. 2.8 - Prob. 8.8ECh. 2.8 - Prob. 8.9ECh. 2.8 - Prob. 8.10E
Ch. 2.8 - Prob. 8.11ECh. 2.8 - Prob. 8.12ECh. 2.8 - Prob. 8.13ECh. 2.8 - Prob. 8.14ECh. 2.8 - Prob. 8.15ECh. 2.8 - Prob. 8.16ECh. 2.8 - Prob. 8.17ECh. 2.8 - Prob. 8.18ECh. 2.8 - Prob. 8.19ECh. 2.9 - Prob. 9.1ECh. 2.9 - Prob. 9.2ECh. 2.9 - Prob. 9.3ECh. 2.9 - Prob. 9.4ECh. 2.9 - Prob. 9.5ECh. 2.9 - Prob. 9.6ECh. 2.9 - Prob. 9.7ECh. 2.9 - Prob. 9.8ECh. 2.9 - Prob. 9.9ECh. 2.9 - Prob. 9.10ECh. 2.9 - Prob. 9.11ECh. 2.9 - Prob. 9.12ECh. 2.9 - Prob. 9.13ECh. 2.9 - Prob. 9.14ECh. 2.9 - Prob. 9.15ECh. 2.9 - Prob. 9.16ECh. 2.9 - Prob. 9.17ECh. 2.9 - Prob. 9.18ECh. 2.10 - Prob. 10.1ECh. 2.10 - Prob. 10.2ECh. 2.10 - Prob. 10.3ECh. 2.10 - Prob. 10.4ECh. 2.10 - Prob. 10.5ECh. 2.10 - Prob. 10.6ECh. 2.10 - Prob. 10.7ECh. 2.10 - Prob. 10.8ECh. 2.10 - Prob. 10.9ECh. 2.10 - Let A=x:4x and let B=x:2x. Prove that AB.Ch. 2.10 - Prob. 10.11ECh. 2.10 - Prob. 10.12ECh. 2.10 - Prob. 10.13ECh. 2.10 - Prob. 10.14ECh. 2.10 - Prob. 10.15ECh. 2.11 - Write the following sentences using the quantifier...Ch. 2.11 - Prob. 11.2ECh. 2.11 - Prob. 11.3ECh. 2.11 - Prob. 11.4ECh. 2.11 - Prob. 11.5ECh. 2.11 - Prob. 11.6ECh. 2.11 - Prob. 11.7ECh. 2.11 - Prob. 11.8ECh. 2.12 - Prob. 12.1ECh. 2.12 - Prob. 12.2ECh. 2.12 - Prob. 12.3ECh. 2.12 - Prob. 12.4ECh. 2.12 - Prob. 12.5ECh. 2.12 - Prob. 12.6ECh. 2.12 - Prob. 12.7ECh. 2.12 - Prob. 12.8ECh. 2.12 - Prob. 12.9ECh. 2.12 - Prob. 12.10ECh. 2.12 - Prob. 12.11ECh. 2.12 - Prob. 12.12ECh. 2.12 - Prob. 12.13ECh. 2.12 - Prob. 12.14ECh. 2.12 - Prob. 12.15ECh. 2.12 - Prob. 12.16ECh. 2.12 - Prob. 12.17ECh. 2.12 - Prob. 12.18ECh. 2.12 - Prob. 12.19ECh. 2.12 - Prob. 12.20ECh. 2.12 - Prob. 12.21ECh. 2.12 - Prob. 12.22ECh. 2.12 - Prob. 12.23ECh. 2.12 - Prob. 12.24ECh. 2.12 - Prob. 12.25ECh. 2.12 - Prob. 12.26ECh. 2.12 - Prob. 12.27ECh. 2.12 - Prob. 12.28ECh. 2.12 - Prob. 12.29ECh. 2.12 - Prob. 12.30ECh. 2.13 - Prob. 13.1ECh. 2.13 - Prob. 13.2ECh. 2.13 - Prob. 13.3ECh. 2.13 - Prob. 13.4ECh. 2.13 - Prob. 13.5ECh. 2.13 - Prob. 13.6ECh. 2.13 - Prob. 13.7ECh. 2 - Prob. 1STCh. 2 - Prob. 2STCh. 2 - Prob. 3STCh. 2 - Prob. 4STCh. 2 - Prob. 5STCh. 2 - Prob. 6STCh. 2 - Prob. 7STCh. 2 - Prob. 8STCh. 2 - Prob. 9STCh. 2 - Prob. 10STCh. 2 - Prob. 11STCh. 2 - Prob. 12STCh. 2 - Prob. 13STCh. 2 - Prob. 14STCh. 2 - Prob. 15STCh. 2 - Prob. 16STCh. 2 - Prob. 17STCh. 2 - Prob. 18STCh. 2 - Prob. 19STCh. 2 - Prob. 20ST
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