Mathematics: A Discrete Introduction
3rd Edition
ISBN: 9780840049421
Author: Edward A. Scheinerman
Publisher: Cengage Learning
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Question
Chapter 2.8, Problem 8.16E
To determine
To calculate: The number of possible combination for a four digit long padlock having nine numbers with a condition that no pair of consecutive numbers in the combination can be same of one place apart on the face.
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John knows that multiplying a number by — 1 merely changes the sign ofthe number. He reasons that multiplying a number by an even power of — 1 will change the sign of the number an even number of times. Heconcludes that this is equivalent to multiplying a number by + 1 , so that every even power of -1 is equal to a +1?
If
-4
-1
11
A =
-1
-3
-2
2
-1
1
2
2
determine the following entries:
a31 =
a22 =
a14
Jillian observed that if the sum of its digits is subtracted from a number the result is always divisible by 3 and by 9. She would like to know if this is always true and if so, why?
Chapter 2 Solutions
Mathematics: A Discrete Introduction
Ch. 2.8 - Write out all the possible two-letter words one...Ch. 2.8 - Airports have names, but they also have...Ch. 2.8 - Prob. 8.3ECh. 2.8 - Prob. 8.4ECh. 2.8 - Prob. 8.5ECh. 2.8 - Prob. 8.6ECh. 2.8 - Prob. 8.7ECh. 2.8 - Prob. 8.8ECh. 2.8 - Prob. 8.9ECh. 2.8 - Prob. 8.10E
Ch. 2.8 - Prob. 8.11ECh. 2.8 - Prob. 8.12ECh. 2.8 - Prob. 8.13ECh. 2.8 - Prob. 8.14ECh. 2.8 - Prob. 8.15ECh. 2.8 - Prob. 8.16ECh. 2.8 - Prob. 8.17ECh. 2.8 - Prob. 8.18ECh. 2.8 - Prob. 8.19ECh. 2.9 - Prob. 9.1ECh. 2.9 - Prob. 9.2ECh. 2.9 - Prob. 9.3ECh. 2.9 - Prob. 9.4ECh. 2.9 - Prob. 9.5ECh. 2.9 - Prob. 9.6ECh. 2.9 - Prob. 9.7ECh. 2.9 - Prob. 9.8ECh. 2.9 - Prob. 9.9ECh. 2.9 - Prob. 9.10ECh. 2.9 - Prob. 9.11ECh. 2.9 - Prob. 9.12ECh. 2.9 - Prob. 9.13ECh. 2.9 - Prob. 9.14ECh. 2.9 - Prob. 9.15ECh. 2.9 - Prob. 9.16ECh. 2.9 - Prob. 9.17ECh. 2.9 - Prob. 9.18ECh. 2.10 - Prob. 10.1ECh. 2.10 - Prob. 10.2ECh. 2.10 - Prob. 10.3ECh. 2.10 - Prob. 10.4ECh. 2.10 - Prob. 10.5ECh. 2.10 - Prob. 10.6ECh. 2.10 - Prob. 10.7ECh. 2.10 - Prob. 10.8ECh. 2.10 - Prob. 10.9ECh. 2.10 - Let A=x:4x and let B=x:2x. Prove that AB.Ch. 2.10 - Prob. 10.11ECh. 2.10 - Prob. 10.12ECh. 2.10 - Prob. 10.13ECh. 2.10 - Prob. 10.14ECh. 2.10 - Prob. 10.15ECh. 2.11 - Write the following sentences using the quantifier...Ch. 2.11 - Prob. 11.2ECh. 2.11 - Prob. 11.3ECh. 2.11 - Prob. 11.4ECh. 2.11 - Prob. 11.5ECh. 2.11 - Prob. 11.6ECh. 2.11 - Prob. 11.7ECh. 2.11 - Prob. 11.8ECh. 2.12 - Prob. 12.1ECh. 2.12 - Prob. 12.2ECh. 2.12 - Prob. 12.3ECh. 2.12 - Prob. 12.4ECh. 2.12 - Prob. 12.5ECh. 2.12 - Prob. 12.6ECh. 2.12 - Prob. 12.7ECh. 2.12 - Prob. 12.8ECh. 2.12 - Prob. 12.9ECh. 2.12 - Prob. 12.10ECh. 2.12 - Prob. 12.11ECh. 2.12 - Prob. 12.12ECh. 2.12 - Prob. 12.13ECh. 2.12 - Prob. 12.14ECh. 2.12 - Prob. 12.15ECh. 2.12 - Prob. 12.16ECh. 2.12 - Prob. 12.17ECh. 2.12 - Prob. 12.18ECh. 2.12 - Prob. 12.19ECh. 2.12 - Prob. 12.20ECh. 2.12 - Prob. 12.21ECh. 2.12 - Prob. 12.22ECh. 2.12 - Prob. 12.23ECh. 2.12 - Prob. 12.24ECh. 2.12 - Prob. 12.25ECh. 2.12 - Prob. 12.26ECh. 2.12 - Prob. 12.27ECh. 2.12 - Prob. 12.28ECh. 2.12 - Prob. 12.29ECh. 2.12 - Prob. 12.30ECh. 2.13 - Prob. 13.1ECh. 2.13 - Prob. 13.2ECh. 2.13 - Prob. 13.3ECh. 2.13 - Prob. 13.4ECh. 2.13 - Prob. 13.5ECh. 2.13 - Prob. 13.6ECh. 2.13 - Prob. 13.7ECh. 2 - Prob. 1STCh. 2 - Prob. 2STCh. 2 - Prob. 3STCh. 2 - Prob. 4STCh. 2 - Prob. 5STCh. 2 - Prob. 6STCh. 2 - Prob. 7STCh. 2 - Prob. 8STCh. 2 - Prob. 9STCh. 2 - Prob. 10STCh. 2 - Prob. 11STCh. 2 - Prob. 12STCh. 2 - Prob. 13STCh. 2 - Prob. 14STCh. 2 - Prob. 15STCh. 2 - Prob. 16STCh. 2 - Prob. 17STCh. 2 - Prob. 18STCh. 2 - Prob. 19STCh. 2 - Prob. 20ST
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- The figure below shows that 4 one-inch segments are needed to make a 1 × 1 square, 12 one-inch segments are needed to make a 2 × 2 square composed of four 1 × 1 squares, and 24 one-inch segments are needed to make a 3 × 3 square composed of nine 1 × 1 squares. How many one-inch segments are needed to make an nx n square composed of 1 x 1 squares?arrow_forwardWhat is a2 if a1 = 4 and an = 3an-1 + 1arrow_forwardSuppose an = 5an-1+ 4an-2 – 3an-3 and a4 = 22, as 127, and a6 = = 717. Find a1, a2, and a3. Aj = a2 a3 = ||arrow_forward
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