Mathematics: A Discrete Introduction
3rd Edition
ISBN: 9780840049421
Author: Edward A. Scheinerman
Publisher: Cengage Learning
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Chapter 2.12, Problem 12.16E
To determine
To prove the given expression
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Students have asked these similar questions
(a) Test the hypothesis.
Consider the hypothesis test Ho
=
:
against H₁o < 02. Suppose that the sample sizes aren₁ =
7 and n₂
= 13 and that
$²
= 22.4 and $22
= 28.2. Use α = 0.05.
Ho
is not
✓ rejected.
9-9
IV
(b) Find a 95% confidence interval on of 102. Round your answer to two decimal places (e.g. 98.76).
Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a
university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when
examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both
sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force
for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known.
Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null
hypothesis, 40 = 0. What level of type II error would you recommend here?
Round your answer to four decimal places (e.g. 98.7654). Use a
= 0.05.
β
= i
What sample size would be required?
Assume the sample sizes are to be equal.…
=
Consider the hypothesis test Ho: μ₁ = μ₂ against H₁ μ₁ μ2. Suppose that sample sizes are n₁ =
15 and n₂ =
15, that x1 = 4.7
and X2 = 7.8 and that s² = 4 and s² = 6.26. Assume that o and that the data are drawn from normal distributions. Use
απ 0.05.
(a) Test the hypothesis and find the P-value.
(b) What is the power of the test in part (a) for a true difference in means of 3?
(c) Assuming equal sample sizes, what sample size should be used to obtain ẞ = 0.05 if the true difference in means is - 2? Assume
that α = 0.05.
(a) The null hypothesis is
98.7654).
rejected. The P-value is 0.0008
(b) The power is 0.94
. Round your answer to four decimal places (e.g.
Round your answer to two decimal places (e.g. 98.76).
(c) n₁ = n2 =
1
. Round your answer to the nearest integer.
Chapter 2 Solutions
Mathematics: A Discrete Introduction
Ch. 2.8 - Write out all the possible two-letter words one...Ch. 2.8 - Airports have names, but they also have...Ch. 2.8 - Prob. 8.3ECh. 2.8 - Prob. 8.4ECh. 2.8 - Prob. 8.5ECh. 2.8 - Prob. 8.6ECh. 2.8 - Prob. 8.7ECh. 2.8 - Prob. 8.8ECh. 2.8 - Prob. 8.9ECh. 2.8 - Prob. 8.10E
Ch. 2.8 - Prob. 8.11ECh. 2.8 - Prob. 8.12ECh. 2.8 - Prob. 8.13ECh. 2.8 - Prob. 8.14ECh. 2.8 - Prob. 8.15ECh. 2.8 - Prob. 8.16ECh. 2.8 - Prob. 8.17ECh. 2.8 - Prob. 8.18ECh. 2.8 - Prob. 8.19ECh. 2.9 - Prob. 9.1ECh. 2.9 - Prob. 9.2ECh. 2.9 - Prob. 9.3ECh. 2.9 - Prob. 9.4ECh. 2.9 - Prob. 9.5ECh. 2.9 - Prob. 9.6ECh. 2.9 - Prob. 9.7ECh. 2.9 - Prob. 9.8ECh. 2.9 - Prob. 9.9ECh. 2.9 - Prob. 9.10ECh. 2.9 - Prob. 9.11ECh. 2.9 - Prob. 9.12ECh. 2.9 - Prob. 9.13ECh. 2.9 - Prob. 9.14ECh. 2.9 - Prob. 9.15ECh. 2.9 - Prob. 9.16ECh. 2.9 - Prob. 9.17ECh. 2.9 - Prob. 9.18ECh. 2.10 - Prob. 10.1ECh. 2.10 - Prob. 10.2ECh. 2.10 - Prob. 10.3ECh. 2.10 - Prob. 10.4ECh. 2.10 - Prob. 10.5ECh. 2.10 - Prob. 10.6ECh. 2.10 - Prob. 10.7ECh. 2.10 - Prob. 10.8ECh. 2.10 - Prob. 10.9ECh. 2.10 - Let A=x:4x and let B=x:2x. Prove that AB.Ch. 2.10 - Prob. 10.11ECh. 2.10 - Prob. 10.12ECh. 2.10 - Prob. 10.13ECh. 2.10 - Prob. 10.14ECh. 2.10 - Prob. 10.15ECh. 2.11 - Write the following sentences using the quantifier...Ch. 2.11 - Prob. 11.2ECh. 2.11 - Prob. 11.3ECh. 2.11 - Prob. 11.4ECh. 2.11 - Prob. 11.5ECh. 2.11 - Prob. 11.6ECh. 2.11 - Prob. 11.7ECh. 2.11 - Prob. 11.8ECh. 2.12 - Prob. 12.1ECh. 2.12 - Prob. 12.2ECh. 2.12 - Prob. 12.3ECh. 2.12 - Prob. 12.4ECh. 2.12 - Prob. 12.5ECh. 2.12 - Prob. 12.6ECh. 2.12 - Prob. 12.7ECh. 2.12 - Prob. 12.8ECh. 2.12 - Prob. 12.9ECh. 2.12 - Prob. 12.10ECh. 2.12 - Prob. 12.11ECh. 2.12 - Prob. 12.12ECh. 2.12 - Prob. 12.13ECh. 2.12 - Prob. 12.14ECh. 2.12 - Prob. 12.15ECh. 2.12 - Prob. 12.16ECh. 2.12 - Prob. 12.17ECh. 2.12 - Prob. 12.18ECh. 2.12 - Prob. 12.19ECh. 2.12 - Prob. 12.20ECh. 2.12 - Prob. 12.21ECh. 2.12 - Prob. 12.22ECh. 2.12 - Prob. 12.23ECh. 2.12 - Prob. 12.24ECh. 2.12 - Prob. 12.25ECh. 2.12 - Prob. 12.26ECh. 2.12 - Prob. 12.27ECh. 2.12 - Prob. 12.28ECh. 2.12 - Prob. 12.29ECh. 2.12 - Prob. 12.30ECh. 2.13 - Prob. 13.1ECh. 2.13 - Prob. 13.2ECh. 2.13 - Prob. 13.3ECh. 2.13 - Prob. 13.4ECh. 2.13 - Prob. 13.5ECh. 2.13 - Prob. 13.6ECh. 2.13 - Prob. 13.7ECh. 2 - Prob. 1STCh. 2 - Prob. 2STCh. 2 - Prob. 3STCh. 2 - Prob. 4STCh. 2 - Prob. 5STCh. 2 - Prob. 6STCh. 2 - Prob. 7STCh. 2 - Prob. 8STCh. 2 - Prob. 9STCh. 2 - Prob. 10STCh. 2 - Prob. 11STCh. 2 - Prob. 12STCh. 2 - Prob. 13STCh. 2 - Prob. 14STCh. 2 - Prob. 15STCh. 2 - Prob. 16STCh. 2 - Prob. 17STCh. 2 - Prob. 18STCh. 2 - Prob. 19STCh. 2 - Prob. 20ST
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