Concept explainers
(a)
Interpretation: It should be predicted that why the formula
Concept introduction: The main group elements form chemical compounds in which the central atom has highest oxidation number. The highest oxidation number is always equal to the group number that the element has in the periodic table. Thus, the oxidation number is determined by the position of the element in the periodic table.
These elements also form compounds in the other lower oxidation numbers apart from the highest oxidation number. These other oxidation numbers are as per the electronic configuration of the element and is determined by the number of electrons in the outer shell of each element.
The correct formula has the valid oxidation number of the central element and the formula which do not satisfy this criteria is incorrect
(b)
Interpretation: It should be predicted that why the formula
Concept introduction: The main group elements form chemical compounds in which the central atom has highest oxidation number. The highest oxidation number is always equal to the group number that the element has in the periodic table. Thus, the oxidation number is determined by the position of the element in the periodic table.
These elements also form compounds in the other lower oxidation numbers apart from the highest oxidation number. These other oxidation numbers are as per the electronic configuration of the element and are determined by the number of electrons in the outer shell of each element.
The correct formula has the valid oxidation number of the central element and the formula which do not satisfy this criteria is incorrect
(c)
Interpretation: It should be predicted that why the formula
Concept introduction: The main group elements form chemical compounds in which the central atom has highest oxidation number. The highest oxidation number is always equal to the group number that the element has in the periodic table. Thus, the oxidation number is determined by the position of the element in the periodic table.
These elements also form compounds in the other lower oxidation numbers apart from the highest oxidation number. These other oxidation numbers are as per the electronic configuration of the element and are determined by the number of electrons in the outer shell of each element.
The correct formula has the valid oxidation number of the central element and the formula which do not satisfy this criteria is incorrect
Want to see the full answer?
Check out a sample textbook solution
Chapter 21 Solutions
Bundle: Chemistry & Chemical Reactivity, Loose-Leaf Version, 9th + OWLv2, 4 terms (24 Months) Printed Access Card
- please add appropriate arrows and tell me in detail where to add which or draw itarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) Temporary cross-linked polymer Using: 4% polyvinyl alcohol+ methyl red + 4% sodium boratearrow_forwardcan you please answer both these questions and draw the neccesaryarrow_forward
- can you please give the answer for both these pictures. thankyouarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) | Bakelite like polymer Using: Resorcinol + NaOH + Formalinarrow_forwardQuestion 19 0/2 pts 3 Details You have a mixture of sodium chloride (NaCl) and potassium chloride (KCl) dissolved in water and want to separate out the Cl- ions by precipitating them out using silver ions (Ag+). The chemical equation for the net ionic reaction of NaCl and KCl with silver nitrate, AgNO3, is shown below. Ag+(aq) + Cl(aq) → AgCl(s) The total mass of the NaCl/KCl mixture is 1.299 g. Adding 50.42 mL of 0.381 M solution precipitates out all of the Cl-. What are the masses of NaCl and KCl in the mixture? Atomic masses: g: Mass of NaCl g: Mass of KCL Ag = 107.868 g mol- 1 Cl = 35.453 g mol- 1 K = 39.098 g mol- N = 14.007 g mol−1 Na = 22.99 g mol−1 0 = 15.999 g mol 1 Question Help: ✓ Message instructor Submit Questionarrow_forward
- Part 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerolarrow_forwardIdentify the missing starting materials/ reagents/ products in the following reactions. Show the stereochemistry clearly in the structures, if any. If there is a major product, draw the structures of the major product with stereochemistry clearly indicated where applicable. Show only the diastereomers (you do not have to draw the pairs of enantiomers). If you believe that multiple products are formed in approximately equal amounts (hence neither is the major product), draw the structures of the products, and show the detailed mechanism of these reactions to justify the formation of the multiple products. If you believe no product is formed, explain why briefly. (6 mark for each, except f and g, which are 10 mark each)arrow_forward3. What starting material would you use to synthesize 3-hydroxypentanoic acid using a NaBH4 reduction?arrow_forward
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning