Chapter 21, Problem 95IL

Interpretation Introduction

Interpretation:

To write the balanced reaction of hydrazine in acid solution with iodate ion and also calculate the $E^{\circ }$ for the reaction.

Concept introduction:

The formula for hydrazine is ${\text{N}}_{\text{2}}{\text{H}}_{\text{4}}$. In acidic solution it exists as ${\text{N}}_{\text{2}}{\text{H}}_5{}^{+}$. It can be oxidized to ${\text{N}}_{\text{2}}$ by the iodate ion. The formula for iodate ion is ${\text{IO}}^{3-}$. Hydrazine acts as a four electron reducing agent.

A balanced chemical equation occurs when the number of atoms in reactant side is equal to the number of atoms in the product side.

The standard cell potential expression is written as follows,

${\text{E}}^{\circ }{}_{\text{cell}}={\text{E}}^{\circ }{}_{\text{cathode}}+{\text{E}}^{\circ }{}_{\text{anode}}$